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MP Board Class 7 Maths Solutions For Chapter 2 Fractions and Decimals

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MP Board Class 7 Maths Solutions For Chapter 2 Fractions and Decimals

1. \( 5 \times 2 \frac{3}{7}\)

Solution: \( 5 \times 2 \frac{3}{7}=5 \times 12 \frac{1}{7}=\frac{85}{7}=12 \frac{1}{7}\)

2. \(1 \frac{4}{9} \times 6\)

Solution: \( 1 \frac{4}{9} \times 6=a \times 6=\frac{78}{9}=8 \frac{6}{9}\)

 what is

1. \( \frac{1}{2}\) of 10 ?

Solution:

\( \frac{1}{2} \text { of } 10=\frac{1}{2} \times 10=\frac{10}{2}=5\)

2. \( \frac{1}{4}\) of 16 ?

Solution:

\( \frac{1}{4} \text { of } 16=\frac{1}{4} \times 16=\frac{16}{4}=4\)

3. \( \frac{2}{5}\)

Solution: \( \frac{2}{5} \text { of } 25=\frac{2}{5} \times 25=\frac{50}{5}=10\)

Fill in these boxes:

1) \( \frac{1}{2} \times \frac{1}{7}=\frac{1 \times 1}{2 \times 7}=\frac{1}{14} \)

2) \( \frac{1}{5} \times \frac{1}{7}=\frac{1 \times 1}{5 \times 7}=\frac{1}{35} \)

3) \( \frac{1}{7} \times \frac{1}{2}=\frac{1 \times 1}{7 \times 2}=\frac{1}{14} \)

4) \( \frac{1}{7} \times \frac{1}{5}=\frac{1 \times 1}{7 \times 5}=\frac{1}{35} \)

Mp Board Class 7 Book Solutions

Find:

1) \( \frac{1}{3} \times \frac{4}{5} \)

Solution: \( \frac{1}{3} \times \frac{4}{5}=\frac{1 \times 4}{3 \times 5}=\frac{4}{15} \)

2) \( \frac{2}{3} \times \frac{1}{5} \)

Solution: \( \frac{2}{3} \times \frac{1}{5}=\frac{2 \times 1}{3 \times 5}=\frac{2}{15} \)

Solutions To Try These

1) \( \frac{8}{3} \times \frac{4}{7} \)

Solution: \( \frac{8}{3} \times \frac{4}{7}=\frac{8 \times 4}{3 \times 7}=\frac{32}{21} \)

2) \( \frac{3}{4} \times \frac{2}{3} \)

Solution: \( \frac{3}{4} \times \frac{2}{3}=\frac{3 \times 2}{4 \times 3}=\frac{6}{12}=\frac{6 \div 6}{12 \div 6}=\frac{1}{2} \)

MP Board Class 7 Maths Solutions For Chapter 2 Fractions and Decimals

1. Find

(1) \( \frac{1}{4} of \) 1) \frac{1}{4} 2) \( \frac{3}{5} \) 3) \( \frac{4}{3}\)

1) \( \frac{1}{4} \text { of } \frac{1}{4}=\frac{1}{4} \times \frac{1}{4}=\frac{1 \times 1}{4 \times 4}=\frac{1}{16} \)

2). \( \frac{1}{4} \text { of } \frac{3}{5}=\frac{1}{4} \times \frac{3}{5}=\frac{1 \times 3}{4 \times 5}=\frac{3}{20} \)

3) \( \frac{1}{4} \text { of } \frac{4}{3}=\frac{1}{4} \times \frac{4}{3}=\frac{1 \times 4}{4 \times 3}=\frac{4}{12} \)

\( =\frac{4 \div 4}{12 \div 4}=\frac{1}{3} \)

Mp Board Class 7 Book Solutions

2) \( \frac{1}{7} \) of 1) \( \frac{2}{9} \) 2) \( \frac{6}{5} \) 3) \( \frac{3}{10} \)

Solution:

1) \( \frac{1}{7} \text { of } \frac{2}{9}=\frac{1}{7} \times \frac{2}{9}=\frac{1 \times 2}{7 \times 9}=\frac{2}{63} \)

2)\( \frac{1}{7} \text { of } \frac{6}{5}=\frac{1}{7} \times \frac{6}{5}=\frac{1 \times 6}{7 \times 5}=\frac{6}{35} \)

3)\( \frac{1}{7} \text { of } \frac{3}{10}=\frac{1}{7} \times \frac{3}{10}=\frac{1 \times 3}{7 \times 10}=\frac{3}{70} \)

2. Multiply and reduce to lowest form (if possible):

1. \( \frac{2}{3} \times 2 \frac{2}{3} \)

Solution: \( \frac{2}{3} \times 2 \frac{2}{3}=\frac{2}{3} \times \frac{8}{3}=\frac{2 \times 8}{3 \times 3}=\frac{16}{9}=1 \frac{7}{9} \)

2. \( \frac{2}{7} \times \frac{7}{9} \)

Solution:

\( \frac{2}{7} \times \frac{7}{9}=\frac{2 \times 7}{7 \times 9}=\frac{14}{63}=\frac{14 \div 7}{63 \div 7}=\frac{2}{9} \)

3. \( \frac{3}{8} \times \frac{6}{4} \)

Solution:

\( \frac{3}{8} \times \frac{6}{4}=\frac{3 \times 6}{8 \times 4}=\frac{18}{32}=\frac{18 \div 2}{32 \div 2}=\frac{9}{16} \)

Mp Board Class 7 Maths Solutions

4. \( \frac{9}{5} \times \frac{3}{5} \)

Solution:

\( \frac{9}{5} \times \frac{3}{5}=\frac{9 \times 3}{5 \times 5}=\frac{27}{25}=1 \frac{2}{25} \)

5. \( \frac{1}{3} \times \frac{15}{8} \)

Solution:

\( \frac{1}{3} \times \frac{15}{8}=\frac{1 \times 15}{3 \times 8}=\frac{15}{24}=\frac{15 \div 3}{24 \div 3}=\frac{5}{8} \)

6. \( \frac{11}{2} \times \frac{3}{10} \)

Solution: \( \frac{11}{2} \times \frac{3}{10}=\frac{11 \times 3}{2 \times 10}=\frac{33}{20}=1 \frac{13}{20} \)

7. \( \frac{4}{5} \times \frac{12}{7} \)

Solution: \(\frac{4}{5} \times \frac{12}{7}=\frac{4 \times 12}{5 \times 7}=\frac{48}{35}=1 \frac{13}{35} \)

3. Multiply the following fractions:

1) \( \frac{2}{5} \times 5 \frac{1}{4} \)

Solution: \( \frac{2}{5} \times 5 \frac{1}{4}=\frac{2}{5} \times \frac{21}{4} \)

\(=\frac{2 \times 21}{5 \times 4}=\frac{42}{20}=\frac{42 \div 2}{20 \div 2} \) \( =\frac{21}{10}=2 \frac{1}{10} \)

Class 7 Maths Chapter 2 Solutions Mp Board

2) \( 6 \frac{2}{5} \times \frac{7}{9} \)

Solution: \( 6 \frac{2}{5} \times \frac{7}{9}=\frac{32}{5} \times \frac{7}{9} \)

\( =\frac{32 \times 7}{5 \times 9}=\frac{224}{45}=4 \frac{44}{45} \)

3) \( \frac{3}{2} \times 5 \frac{1}{3} \)

Solution: \( \frac{3}{2} \times 5 \frac{1}{3}=\frac{3}{2} \times \frac{16}{3}=\frac{3 \times 16}{2 \times 3}=\frac{48}{6} \)

\( =\frac{48 \div 6}{6 \div 6}=\frac{8}{1}=8 \)

4. \( \frac{5}{6} \times 2 \frac{3}{7} \)

Solution: \( \frac{5}{6} \times 2 \frac{3}{7}=\frac{5}{6} \times \frac{17}{7}=\frac{5 \times 17}{6 \times 7}=\frac{85}{42}=2 \frac{1}{42} \)

5. \( 3 \frac{2}{5} \times \frac{4}{7} \)

Solution: \( 3 \frac{2}{5} \times \frac{4}{7}=\frac{17}{5} \times \frac{4}{7}=\frac{17 \times 4}{5 \times 7}=\frac{68}{35}=1 \frac{33}{35} \)

6. \( 2 \frac{3}{5} \times 3 \)

Solution: \( 2 \frac{3}{5} \times 3=\frac{13}{5} \times 3=\frac{13 \times 3}{5}=\frac{39}{5}=7 \frac{4}{5} \)

7.\( 3 \frac{4}{7} \times \frac{3}{5} \)

Solution: \( =\frac{75 \div 5}{35 \div 5}=\frac{15}{7}=2 \frac{1}{7} \)

\( =\frac{75 \div 5}{35 \div 5}=\frac{15}{7}=2 \frac{1}{7} \)

Mp Board Maths Chapter 2 Solutions

4. Which is greater:

1) \( \frac{2}{7} \) of \( \frac{3}{4} \) or \( \frac{3}{5} \) of \( \frac{5}{8} \)

Solution: \( \frac{2}{7} \text { of } \frac{3}{4}=\frac{2}{7} \times \frac{3}{4}=\frac{2 \times 3}{7 \times 4} \)

\( =\frac{6}{28}=\frac{6 \div 2}{28 \div 2}=\frac{3}{14} \) \( \frac{3}{5} \text { of } \frac{5}{8}=\frac{3}{5} \times \frac{5}{8}=\frac{3 \times 5}{5 \times 8}=\frac{15}{40}=\frac{15 \div 5}{40 \div 5}=\frac{3}{8} \)

LCM = 2 x 7X 4 = 56

LCM of 14, 8 is 56

\( \frac{3}{14}=\frac{3 \times 4}{14 \times 4}=\frac{12}{56} \) \( \frac{3}{8}=\frac{3 \times 7}{8 \times 7}=\frac{21}{56} \)

∴ 21 > 12

LGM of 14, 8 is 56

\( \frac{21}{56}>\frac{12}{56} \Rightarrow \frac{3}{8}>\frac{3}{14} \) \( \frac{3}{5} \text { of } \frac{5}{8}>\frac{2}{7} \text { of } \frac{3}{4} \)

Mp Board Maths Chapter 2 Solutions

2) \( \frac{1}{2} \text { of } \frac{6}{7} \text { or } \frac{2}{3} \text { of } \frac{3}{7} \)

Solution:

\( \begin{aligned}
&\begin{aligned}
\frac{1}{2} \text { of } \frac{6}{7} & =\frac{1}{2} \times \frac{6}{7}=\frac{1 \times 6}{2 \times 7}=\frac{6}{14} \\
& =\frac{6 \div 2}{14 \div 2}=\frac{3}{7}
\end{aligned}\\
&\begin{aligned}
\frac{2}{3} \text { of } \frac{3}{7}=\frac{2}{3} \times \frac{3}{7}=\frac{2 \times 3}{3 \times 7} & =\frac{6}{21} \\
& =\frac{6 \div 3}{21 \div 3}=\frac{2}{7}
\end{aligned}
\end{aligned} \)

3 > 2;

\( \frac{3}{7}>\frac{2}{7} \) \( \frac{1}{2} \text { of } \frac{6}{7}>\frac{2}{3} \text { of } \frac{3}{7} \)

5. Saili plants 4 saplings,in a row,in her garden. The distance between two adjacent saplings is \( \frac{3}{4} \) m. Find the distance between the first and the last sapling.

Solution:

Distance between two saplings = \( \frac{3}{4} \) m.

Distance between the first and the last sapling = \( 3 \times \frac{3}{4}=\frac{3 \times 3}{4}=\frac{9}{4}=2 \frac{1}{4} \mathrm{~m} \)

6. Lipika reads a book for \( 1 \frac{3}{4} \) hours everyday. She reads the entire book in 6 days. How many hours in all were required by her to read the book ?

Solution:

No. of hours taken by Lipika to read the bookin a day = \( 1 \frac{3}{4} \)

No. of days taken toread the entire book = 6 days

Time takenby Lipika to read the book

\( =1 \frac{3}{4} \times 6 \) \( \begin{aligned}
& =\frac{(1 \times 4+3)}{4} \times 6=\frac{7}{4} \times 6=\frac{42}{4} \\
& =\frac{42 \div 2}{4 \div 2}=\frac{21}{2}=10 \frac{1}{2} \text { hours }
\end{aligned} \)

7. A car covers 16 km using 1 litre of petrol.Howmuch distance willit cover using \( 2 \frac{3}{4} \) litres of petrol ?

Solution:

Distance covered with 1 litre of petrol = 16 km

Distance covered with \( 2 \frac{3}{4} \) litres of petrol = \( 16 \times 2 \frac{3}{4} \)

\( \begin{aligned}
& =16 \times\left(\frac{2 \times 4+3}{4}\right)=16 \times \frac{11}{4} \\
& =\frac{16 \times 11}{4}=\frac{176}{4}=44 \mathrm{~km}
\end{aligned} \)

Class 7 Mp Board Maths Question Answers

8.

1) 1) Provide the number in the box such that □, \( \frac{2}{3} \) × □ = \( \frac{10}{30} \)

2) The simplest form of the number obtained in □ is…………….

Solution:

1. \( \frac{2}{3}  \) x  = \( \frac{5}{10}  \) \(\frac{10}{30} \)

2. \( \frac{5}{10}=\frac{5 \div 5}{10 \div 5}=\frac{1}{2} \)

2) 1) Provide the number in the box □, such that \( \frac{3}{5}\) x □ = \( \frac{24}{75}\)

2) The simplest form of the number obtained in □ is ……….

Solution:

1) \( \frac{3}{5} \times \frac{8}{15}=\frac{24}{75} \)

2) \( \frac{8}{15} \)

Think, Discuss And Write

1) Will the reciprocal of a proper fraction be again a proper fraction?

Solution. No, the reciprocal of a proper fraction will not be a proper fraction. It will be an improper fraction.

Example: \( \frac{2}{9} \text { its reciprocal is } \frac{9}{2} \)

\( \frac{2}{9} \) is aproper fraction; \( \frac{9}{2} \) is animproper fraction.

2) Will the reciprocal of an improper fraction be again animproper fraction?

Solution: No, the reciprocal of an improper fraction will not.be an improper fraction again.It will be a proper fraction.

Example: \( \frac{5}{4} \) is animproper fraction.But its reciprocal \( \frac{4}{5} \) is a proper fraction.

MP Board Class 7 Maths Solutions For Chapter 1 Integers

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MP Board Class 7 Maths Solutions For Chapter 1 Integers

1. Evaluate each of the following:

1) (-30) ÷ 10

Solution: (-30) ÷ 10 = -3

2) 50 ÷ (-5)

Solution: 50 ÷ (-5) = -10

3) (-36) ÷ (-9)

Solution: (-36) ÷ (-9) =4

4) (-49) ÷ 49

Solution: (-49) ÷ 49 =-1

5) 13 ÷ [(-2) + 1]

Solution: 13 ÷ [(-2) + 1] = 13 ÷ (-1) = -13

6) 0 ÷(-12)

Solution: 0 ÷ (-12) = 0

7) (-31) ÷ [(-30) + (-1)]

Solution: (-31)+ [(-30) +(-1)] = (-31) + (-31) = 1

8) (-36) +12) ÷ 3

Solution: [(-36) +12)] ÷ 3 =(-3) ÷ 3 =-1

Mp Board Class 7 Maths Solutions

9) [(-6) +5] ÷ [(-2)+1]

Solution: [(- 6) + 5]÷ [(-2) +1] = (-1) + (-1) =1

2) Verify that a + (b + c) (a + b) + (a + c) for each of the following values of a, b and c.

1) a = 12 ; b = -4 ; c = 2 

Solution: a ÷ (b + c) =12 ÷ [(- 4) + 2]

= 12 ÷ (-2) =- 6

[a ÷ b] +[a ÷ c] =[12 ÷ (- 4)] +[12 ÷ 2]

= (-3) +6 = 3

a ÷ (b ÷ c) ≠ (a ÷ b) + (a ÷ c)

2) a = -10 ; b =1 ; c =1

Solution: a ÷ (b + c) = (-10) ÷ (1 + 1)

= (-10) ÷ 2 = -5

[a ÷ b] + [a ÷ c] = [(-10) +1]

+ [(-10) ÷ 1] = (-10) + (-10) = -20

a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c)

Class 7 Maths Chapter 1 Solutions Mp Board

3. Fill in the blanks:

1) 369 + 1 =369

2) (-75) +75 =-1

3) (-206) + (-206) =1

4) (-87) + (-1) = 87

5) -87 + 1 = -87

7) (-48) + 48 =-1

8) 20 +(-10) = -2

9) (-12) +4 = -3 .

4. Write five pairs of integers (a, b) such that a ÷ b = -3. One such pair is (6, -2) because 6 ÷ (-2) = -3.

Solution:

Five pairs of integers (a, b) such that a ÷ b = -3 are

1) 9 ÷ (-3) =-3              ∴ [9,-3]

2) 12 ÷ (-4) =-3            ∴ [12,-4]

3) 27 ÷ (-9) = -3          ∴ [27,-9]

4) 15÷ (-5)= -3            ∴ [15,-5]

5) (-18) ÷ 6 =-3            ∴ [-18,6]

Mp Board Maths Chapter 1 Solutions

5. The temperature at 12 noon was 10°C above zero.If it decreases at the rate of 2°C. per horn: until midnight, at what time would the temperature be 8°C below zero? What would be the temperature at mid night?

Solution:

Temperature. at 12 noon = 10°C

Temperature at 1 PM = = 10°C- 2°C = 8°C

Temperature at 3 PM = 6°C – 2°C = 4°C

Temperature at 4 PM = 4°C- 2°C = 2°C

Temperature at 5 PM = 2°C- 2°C = 0°C

Temperature at 6 PM = 0°C- 2°C = – 2°C

Temperature at 7PM = -2°C- 2°C =-4°C

Temperature at 8 PM =- 4°C- 2°C =- 6°C

Temperature at 9 PM = – 6°C- 2°C =- 8°C

The temperature will be 8°C below zero at 9 PM

Temperature at 10 PM =- 8°C- 2°C =- 10°C

Temperature at11 PM =- 10°C- 2°C =- 12°C

Temperature at12 PM i.e. midnight = -12°C- 2°C =- 14°C

Temperature at midnight is 14 degrees below zero.

Mp Board Class 7 Book Solutions

6. In a class test (+3) marks are given for every correct answer and (-2) marks are given for every incorrect answer and no marks for not attempting any question.

1) Radhika scored 20 marks. If she has got 12 correct answers, how many questions has she attempted incorrectly ?

2) Mohini scores -5 marks in this test, though she has got 7 correct answers.How many questions has she attempted incorrectly?

Solution:

1) Marks given for each correct answer = 3

Marks given for 12 correct answers =12×3 = 36

Radhika’s score = 20

Marks given for incorrect answers = 20 -36 = -16

Marks given for each incorrect answer = (-2)

So number of incorrect answers = (-16) + (-2) = 8

2) Marks given for 7 correct answers = 7 x 3 = 21

Mohini’s score = -5

Marks received for incorrect answers = -5-21 = -26

Marks given for one incorrect answer = -2

Number of incorrect answers = -26/-2 =13

7. An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach – 350 m ?

Solution: Total distance covered by elevator = 10 -(-350) =360m

Speed of the elevator = 6 m / min

360 m descent = -360/6 = 60 min

∴ The elevator will take 60 minutes or 1hour to reach- 350m below the ground level.

 1) (-100)÷ 5

Solution: (-100) ÷ 5 = -20

2) (-81) ÷ 9

Solution: (-81) ÷ 9 = -9

3) (-75) ÷ 5

Solution: (-75) ÷ 5 = -15

4) (-32) ÷ 2

Solution: (-32) ÷ 2 = -16

Find

1) 125 ÷ (-25)

Solution: 125 ÷ (-25) = -5

2) 80 ÷ (-5)

Solution: 80÷(-5) = -16

3) 64 ÷(-16)

Solution: 64 +(-16) =- 4

Find

1) (-36) ÷ (-4)

Solution: (-36) ÷ (-4) =9

2) (-201) ÷ (-3)

Solution: (-201) ÷ (-3) =67

3) (-325) ÷ (-13)

Solution: (-325) ÷ (-13) =25

Class 7 Mp Board Maths Question Answers

Solutions To Try These

Is

1) 1 ÷ a = 1 ?

Solution: No,1 ÷ a ≠ 1 unless a =1

2) a ÷ (-1) = -a ? for any integer a. Take different values of a and check.

Solution: Yes, a ÷ (-1) = -a

Examples:

1) Take a = 4

  1. 1 ÷ 4 ≠ 1
  2. 4 ÷ (-1) = -4

2) Take a = -5

  1. 1 ÷ (-5) ≠ 1
  2. (-5) ÷ (-1) = 5 =-(-5)

MP Board Class 7 Maths Solutions For Chapter 4 Simple Equations

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MP Board Class 7 Maths Solutions For Chapter 4 Simple Equations

1. Give the first step you will unr to separate the variable and then solve the equation :

1) x-1 -0

Solution:

Given equation isi – 1- 0

Adding 1 on both sides we get

x -1 +1-0 +1

x=1

2) x +1 =0

Solution:

Given equation is x + 1 -0

Subtracting ‘1’ from both sides we get

x+1-1 -0-1

x =-l

3) x-1 = 5

Solution:

Given equation is x-1 =5

Adding 1 on both sides we get

x-1 +1=5+1

x = 6

4) x + 6 = 2

Solution:

Given equation is x + 6 = 2

Subtracting ‘6’ from both sides we get

x+6-6= 2-6

x = – 4

Mp Board Class 7 Maths Solutions

5) y- 4 = -7

Solution:

Given equation is y – 4 = – 7

Adding 4 on both sides we get

y-4+4=-7+4

y = – 3

6) y – 4 = 4

Solution:

Given equation is y- 4 = 4

Adding 4 on both sides we get

y-4 + 4 = 4+4

y = 8

7) y + 4 = 4

Given equation is y + 4 = 4

Subtracting 4 from both sides we get

y+4-4=4-4

y=0

8) y + 4 = – 4

Solution:

Given equation is y + 4 = – 4

Subtracting 4 from both sides we get

y+4-4 = -4-4

y=-8

Class 7 Maths Chapter 4 Solutions Mp Board

2. Give the first step you will use to separate the variable and then solve the equation:

1) 3l = 42

Solution:

The given equation is 3l = 42

Dividing both sides by 3 we get

\( \frac{3l}{3}=\frac{42}{3} \)

l = 14

2) \( \frac{b}{2}=6 \)

Solution: Given equation is \( \frac{b}{2}=6 \)

Multiplying both sides by 2 we get

\( \frac{b}{2} \times 2=6 \times 2 \)

b = 12

3) \( \frac{p}{7}=4 \)

Solution: Given equation is \( \frac{p}{7}=4 \)

Multiplying both sides by 7 we get

\( \frac{p}{7} \times 7=4 \times 7 \)

p = 28

Mp Board Maths Chapter 4 Solutions

4) 4x = 25

Solution: Given equation is 4x = 25

Dividing both sides by 4 we get

\( \frac{4 x}{4}=\frac{25}{4} \) \( x=\frac{25}{4} \)

5) 8y = 36

Solution:

Given equation is 8y 36

Dividing both sides by 8 we get

\( \frac{8 y}{8}=\frac{36}{8} \) \( y=\frac{36}{8}=\frac{36+4}{8+4}=\frac{9}{2} \) \( y=\frac{9}{2} \)

6) \( \frac{z}{3}=\frac{5}{4} \)

Solution:

Given equation is \( \frac{z}{3}=\frac{5}{4} \)

Multiplying both sides by 3 we get

\( \frac{z}{3} \times 3=\frac{5}{4} \times 3 \Rightarrow z=\frac{5 \times 3}{4} \) \( z=\frac{15}{4} \)

Mp Board Class 7 Book Solutions

7) \( \frac{a}{5}=\frac{7}{15}\)

Solution:

Given equation is \( \frac{a}{5}=\frac{7}{15} \)

\( \begin{aligned}
& \frac{a}{5} \times 5=\frac{7}{15} \times 5 \\
& =\frac{35}{15}=\frac{35+5}{15+5}=\frac{7}{3}
\end{aligned} \) \( a=\frac{7}{3} \)

8) 20t = – 10

Solution:

Given equation is 20t = -10

Dividing both sides by 20 we get

\( \frac{20 \mathrm{t}}{20}=\frac{-10}{20} \Rightarrow t=\frac{-10}{20}=\frac{-1}{2} \) \( t=\frac{-1}{2} \)

3. Give the steps you will use to separate the variable and then solve the equation:

1) 3n – 2 = 46

Solution: Given equation is 3n – 2 = 46

Adding 2 on both sides we get

3n -2 + 2 = 46 + 2

3n = 48

Dividing both sides by 3 we get

\( \frac{3 n}{3}=\frac{48}{3} \Rightarrow 9 n=144 \)

n = 16

2) 5m + 7 = 17

Solution:

Given equation is 5m + 7 = 17

Subtracting 7 from both sides we get

5m + 7-7 = 17-7

=> 5m = 10

Dividing both sides by 5 we get

\( \frac{5 m}{5}=\frac{10}{5} \)

25m = 50

\( \Rightarrow m=\frac{50}{25} \)

m = 2

Class 7 Mp Board Maths Question Answers

3. \( \frac{20 p}{3}=40 \)

Solution:

Given equation is \( \frac{20 p}{3}=40 \)

Multiplying both sides by 3 we get

\( \frac{20 p}{3} \times 3=40 \times 3 \)

20p = 120

Dividing both sides by 20 we get

\( \frac{20 p}{3}=\frac{120}{20} \Rightarrow 400 \mathrm{p}=2400 \)

p = 6

4. \( \frac{3 p}{10}=6 \)

Solution:

Given equation is \( \frac{3 p}{10}=6 \)

Multiplying both sides by 10 we get

\( \frac{3 p}{10} \times 10=6 \times 10 \)

3p = 60

Dividing both sides by 3 we get

\( \frac{3 p}{10}=\frac{60}{3} \Rightarrow 9 p=180 \)

p = 20

4. Solve the following equations:

1)10p = 100

Solution:

Given equation is 10p = 100

Dividing both sides by 10 we get

\( \frac{10 p}{10}=\frac{100}{10} \quad \Rightarrow 100 p=1000 \) \( p=\frac{1000}{100} \)

p = 10

2) 10p + 10 = 100

Solution:

Given equation is 10p+10 = 100

Subtracting 10 from both sides we get

10p + 10 – 10 = 100 – 10

10p = 90

Dividing both sides by 10 we get

\( \frac{10 p}{10}=\frac{90}{10} \)

=> 100p =900

\( p=\frac{900}{100} \)

p= 9

Mp Board Class 7 Maths Solutions

3) \( \frac{p}{4}=5 \)

Solution:

Given equation is \( \frac{p}{4}=5 \)

Multiplying both sides by 4 we get

\( \frac{p}{4} \times 4=5 \times 4 \)

p =20

4) \( \frac{-p}{3}=5 \)

Solution:

Given equation is \( \frac{-p}{3}=5 \)

Multiplying both sides by -3 we get

\( \left(\frac{-p}{3}\right) \times(-3)=5(-3) \)

p = – 15

5) \( \frac{3 p}{4}=6 \)

Solution:

Given equation is \( \frac{3 p}{4}=6 \)

Multiplying both sides by 4 we get

\( \frac{3 p}{4} \times 4=6 \times 4 \)

3p = 24

Dividing both sides by 3 we get

\( \frac{3 p}{3}=\frac{24}{3} \)

9p = 72

p = 8

6) 3s = – 9

Solution:

Given equation is 3s = -9

Dividing both sides by 3 we get

\( \frac{3 s}{3}=\frac{-9}{3} \)

9s = – 27

s = – 3

Mp Board Maths Chapter 4 Solutions

7) 3s + 12 = 0

Solution:

Given equation is 3s + 12 = 0

Substracting 12 from both sides we get

3s + 12- 12 = 0 – 12

=> 3s =- 12

Dividing both sides by 3 we get

\( \frac{3 s}{3}=\frac{-12}{3} \)

=> 9s = -36

s = – 4

8) 3s = 0

Solution:

Given equation is 3s = 0

Dividing both sides by 3 we get

\( \frac{3 s}{3}=\frac{0}{3} \)

=> 9s = 0

s= 0

9) 2q = 6

Solution:

Given equation is 2q =6

Dividing both sides by 2 we get

\( \frac{2 q}{2}=\frac{6}{2} \)

4q = 12

q = 3

10) 2q – 6 = 0

Solution:

Given equation is 2q- 6 = 0

Adding 6 on both sides we get

2q-6 + 6 = 0 + 6

2q = 6

Dividing both sides by 2 we get

\( \frac{2 q}{2}=\frac{6}{2} \)

=4q = 12

q= 3

11) 2q + 6 = 0

Solution:

Given equation is 2q + 6 = 0

Subtracting 6 from both sides we get

2q +6-6 = 0-6

=> 2q= – 6

Dividing both sides by 2 we get

\( \frac{2 q}{2}=\frac{-6}{2} \)

4q = -12

q = -3

Mp Board Maths Chapter 4 Solutions

12) 2q + 6 = 12

Solution:

Given equation is 2q + 6 = 12

Subtracting 6 from both sides we get

2q + 6-6 = 12 -6

=> 2q = 6

Dividing both sides by 2 we get

\( \frac{2 q}{2}=\frac{6}{2} \)

4q = 12

q = 3

MP Board Class 6 Science Solutions

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  • Chapter 1 Food: Where Does it Come from?
  • Chapter 2 Components of Food
  • Chapter 3 Fibre to Fabric
  • Chapter 4 Sorting Materials into Groups
  • Chapter 5 Separation of Substances
  • Chapter 6 Changes Around Us
  • Chapter 7 Getting to know Plants
  • Chapter 8 Body Movements
  • Chapter 9 The Living Organisms and their Surrounding
  • Chapter 10 Motion and Measurement of Distances
  • Chapter 11 Light, Shadows and Reflections
  • Chapter 12 Electricity and Circuits
  • Chapter 13 Fun with Magnets
  • Chapter 14 Water
  • Chapter 15 Air Around Us
  • Chapter 16 Garbage In, Garbage Out

MPBSE Class 10 Science Chapter 7 Coordination In Plants Question and Answers

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MPBSE Class 10 Science Chapter 7 Coordination In Plants Question and Answers

Question 1. What are plant hormones?
Answer:

Plant hormones or phytohormones are non-nutrient diffusible chemical substances that control the activities of plants like growth, development, differentiation, movements, and other physiological processes.

Question 2. How is the movement of the leaves of a Sensitive Plant different from the movement of the shoot toward light?
Answer:

  • Leaves of sensitive plant (Mimosa pudica) droop down on being touched or shaken. It is a harmonistic or seismonastic response where the direction of movement is predetermined by the presence of a turgor cell.
  • The movement of the shoot toward light is a growth movement caused by the differential distribution of auxin.

Coordination In Plants movement of leaves of Sensitive Plant Different From Movement Of Shoot Towards Light

Question 3. Give an example of a plant hormone that promotes growth.
Answer: Auxin (IAA)/Gibberellins (GA).

Question 4. How do auxins promote the growth of a tendril around a support?
Answer:

  • In the region of contact, there is less availability of auxin as compared to the free side. Because of this, there is more growth on the free side.
  • The tendril, therefore, bends over the support. The process continues and several coils are produced.

Coordination In Plants Class 10 Questions And Answers

Question 5. Explain the cause of shoots of the plant bending towards light.
Answer:

  • The bending of the shoot towards unilateral light is caused by the effect of light on auxin distribution.
  • There is less auxin on the illuminated side and more auxin on the shaded side. Therefore, there is more growth on the shaded side and the shoot bends in the other direction.

Question 6. What are nastic and curvature movements? Give one example of each.
Answer:

  • Nastic Movements. They are non-directional movements in which the direction of movements is determined by the structure of the responding organ, for example., the opening of flowers, haptonasty in the Sensitive Plant. Nastie movements can be due to growth or turgor changes.
  • Curvature Movements. They are directional growth movements in which the response of the plant organ is determined by the direction of the stimulus, for example., positive phototropism of shoot.

Question 7.

  1. What are plant hormones?
  2. Write two functions of auxin.

Answer:

  1. Plant Hormones. Plant hormones or phytohormones are non-nutrient diffusible chemical substances that can control various activities of plants like growth, differentiation, movements, development, and other physiological processes.
  2. Functions of Auxin.
    1. Auxin induces cell enlargement.
    2. It prevents premature falling of leaves and fruits.

Question 8.

  1. What is tropism?
  2. How do auxins promote the growth of a tendril around a support?

Answer:

  1. It is the directional curvature movement of generally cylindrical plant organs with the direction of stimulus determining the direction of movement.
  2. More auxin is present on the side of the tendril away from the point of contact. Therefore, there is more growth on the free side as compared to the contact side. The more growth on the free side causes the tendril to coil around the support.

Question 9. How is the movement of leaves of sensitive plants different from the movement of a shoot towards light?
Answer:

Coordination In Plants The Movement Of Leaves Of Sensitive Plant Different From The Movement Of A Shoot Towards Light

Coordination In Plants Class 10 Questions And Answers

Question 10. Which plant hormone

  1. Inhibits the growth of plants
  2. Increases yield
  3. Controls cell division.

Answer:

  1. Abscisic acid
  2. Gibberellin
  3. Cytokinin.

Question 11. What is phototropism?
Answer:

Phototropism. It is the directional growth movement of curvature that occurs in plant organs in response to unilateral light.

Question 12. What is hydrotropism?
Answer:

Hydrotropism. It is the tropic or directional movement of curvature that occurs due to unilateral exposure to water. Roots are positively hydrotropic.

Question 13. If you keep the potted plant horizontally for 2-3 days, what type of movements would be shown by the shoot and root after 2-3 days? Why?
Answer:

  • The potted plant develops a geotropic response. It is different in shoot and root. The apical part of the shoot will bend upwardly.
  • It is the negative geotropic response. The apical part of the root will bend downward. It is the positive geotropic response.

Question 14.

  1. Which plant hormone is present in greater concentration in the areas of rapid cell division?
  2. Give one example of a plant growth promoter and plant growth inhibitor.

Answer:

  1. Cytokinin hormone occurs in greater concentration in the areas of rapid cell division.
  2. Growth Promoter – Auxin
    1. Growth Inhibitor – Abscisic acid (ABA).

Mpbse Class 10 Science Chapter 7 Solutions

Question 15. Why does the shoot of the plant bend towards light when it is kept inside a cardboard box with a small hole?
Answer:

  • Light coming from the hole functions as a unilateral stimulus. It results in passing auxin formed on the illuminated side to the shaded side.
  • The shaded side comes to have more auxin. Therefore, it shows more growth. Due to this, the shoot bends to the other side or source of light.

Question 16. What is geotropism? Describe an experiment to demonstrate positive and negative geotropism.
Answer:

Geotropism. It is a tropic or growth movement of curvature which occurs in response to the vector of gravity. The main stem is generally negatively geotropic while the main root is positively geotropic.

Question 17. List in tabular form three differences in the movement of leaves of Sensitive Plants when touched and the movement of tendrils towards the support.
Answer:

Coordination In Plants The Movement Of Leaves Of Sensitive Plant When Touched And Movement Of Tendril Towards The Support

Question 18.

  1. Name the property that causes a tendril to circle the object.
  2. What is the benefit of it?
  3. Fill in the blank_____

Coordination In Plants Harmone And Function

Answer:

  1. Thigmotropism.
  2. By circling the support, the tendril can hold the plant to support and allow it to climb further to exposing the leaves properly
  3. Inhibits growth.
    1. Cytokinin.

Question 19. How does the sensitive plant detect the touch and how do the leaves move in response?
Answer:

  • Touch is a stimulus that is converted into an electrochemical potential that reaches the bases of the leaflets and the leaf.
  • The cells at the base show efflux of K+ and water. As a result, they shrink in size and cause the folding of leaflets and drooping of leaves.

Question 20. What are plant hormones? Name the plant hormones responsible for the following :

  1. Growth of stem
  2. Promotion of cell division
  3. Inhibition of growth
  4. Elongation of cells.

Answer: Plant hormones are non-nutrient, diffusible, chemical substances that control and coordinate growth, movements, and development.

  1. Growth of Stem. Gibberellin
  2. Promotion of Cell Division. Cytokinin.
  3. Inhibition of Growth. Abscisic acid.
  4. Elongation of Cells. Auxin.

Important Questions On Coordination In Plants Class 10

Question 21.

  1. Plants do not have any nervous system but yet if we touch a sensitive plant, some observable changes take place in its leaves. Explain how could this plant respond to external stimuli and how it is communicated.
  2. Name the hormone that needs to be administered to
    1. Increase the height of a dwarf plant
    2. It causes rapid cell division in fruits and seeds.

Answer:

Touching the sensitive plant creates an electrochemical impulse that travels from cell to cell quickly and reaches the bases of leaflets and leaves.

Special cells present at these bases shrink and cause bending movement of leaves and leaflets. Recovery occurs in about ten minutes when basal cells regain turgidity.

  1. Height of Dwarf Plant. Gibberellin.
  2. Rapid Cell Division. Cytokinin.

MPBSE Class 10 Science Chapter 9 Heredity Question And Answers

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MPBSE Class 10 Science Chapter 9 Heredity Question And Answers

Question 1. In a monohybrid cross between tall Pea plants TT and short Pea plants tt, a scientist obtained only tall Pea plants Tt in the F1 generation. However, on selling the F1 generation Pea plants he obtained both tall and short plants in the F2 generation. Based on the above observations and with other angiosperms also, can the scientist arrive at a law? If yes, explain the law. If not, give a justification for your answer.
Answer:

There are two possibilities for the occurrence of tall plants in the F1 generation :

  • Only the factor for tallness passed into F1 progeny. Both the alleles of tallness and shortness passed into F1 progeny but only the allele of tallness is expressing itself.
  • The second option is correct because the trait of shortness has appeared in the F2 generation.
  • Again this can happen only when the alleles for the two traits separate during gamete formation and randomly come together during fertilization.
  • The scientist could, therefore, deduce the laws out of these observations : (1) Law of dominance. (2) Law of segregation.

Question 2.

  1. List two differences in tabular form between dominant and recessive traits.
  2. What percentage or proportion of the plants in F2 generation or progeny was round in Mendel’s cross between round and wrinkled seeded Pea plants?

Differences Between Dominant And Recessive Traits

Answer: (1)

Heredity Difference between Dominant trait And recessive Trait

2. 75% of plants had round seeds while 25% of plants had wrinkled seeds. The ratio is 3: 1.

Mpbse Class 10 Science Chapter 9 Solutions

Question 3. “A trait may be inherited but may not be expressed.” Justify the statement with the help of a suitable example.
Answer:

  1. The trachea is a cylindrical conduit for air from the pharynx to the lungs.
  2. The lining epithelium captures dust particles and bacteria, expelling them forth.
  3. The trachea remains patent despite lower air pressure owing to the presence of C-shaped cartilaginous rings.

Question 4. Name the plant Mendel used for his experiment. What type of progeny was obtained by Mendel in F1 and F1 generations when he crossed tall and short plants? Write the ratios he obtained in F2 generation plants.
Answer:

Garden Pea (Pisum sativum)

F1 Generation. All tall.

F2 Generation. 3 tall: 1 short or 3: 1

or 1 pure tall: 2 hybrid tall: 1 dwarf or 1: 2: 1.

Question 5.

  1. Why did Mendel experiment to study the inheritance of two traits in garden peas?
  2. What were his findings concerning the inheritance of traits in the F1 and F2 generations?
  3. State the ratio obtained in the F2 generation in the above-mentioned experiment.

Answer:

  1. To study the independent inheritance of traits/factors of different characters.
  2. F1 Progeny. All dominant. F2 Progeny. Both parental traits as well as some new combinations or recombinants.
  3. 9 : 3 : 3: 1 where 9/16 and 1/16 are parental types while two types of recombinants appear in the ratio of 3/16 and 3/16.

Heredity Class 10 Questions And Answers

Question 6. A green-stemmed rose plant denoted by GG and a brown-stemmed rose plant denoted by GG are allowed to undergo a cross with each other.

1. List your observations regarding (z) the Colour of the stem in the F1 progeny and the Percentage of brown stemmed plants in F2 progeny if F1 plants are self-pollinated. The ratio of GG and Gg in F2 progeny.

2. Based on the findings of this cross, what conclusion can be drawn?

Answer:

  1. Colour in F1 Progeny. Green
  2. Percentage of Brown Stemmed Plants in F2 Progeny. 25%
  3. Ratio of GG and Gg in F2 Progeny. 1: 2.

Conclusion: The trait which is expressed in whole F1 progeny is dominant while the other trait which remains unexpressed in F1 progeny but reappears in F2 progeny is recessive.

Question 7.

  1. Why is the F1 progeny always of tall plants when a tall pea plant is crossed with a short pea plant?
  2. How is F2 progeny obtained by self-pollination of F1 progeny different from F1 progeny? Give a reason for this observation.
  3. State a conclusion that can be drawn based on this observation.

Answer:

  1. The trait or factor for tallness is dominant while the trait for shortness is recessive.
  2. The recessive trait appears in the F2 generation due to its segregation during gamete formation and the random coming together of the two traits or factors during fertilization. When two factors of shortness come together the recessive trait will appear.
  3. The traits or factors are particulate structures which do not get destroyed or blend during inheritance.

Question 8. Mendel crossed two plants with visible contrasting characteristics and found that there were no halfway characteristics in the plants of F1 progeny. Explain the reason for this observation of Mendel.
Answer:

Despite having inherited both the contrasting traits, F1 progeny shows the trait of only one parent. This is because in the hybrid (F1 plants) only one trait expresses its effect. The trait is dominant. The other trait which does not express its effect in the hybrid is called recessive.

Law Of Inheritance Class 10 Biology

Question 9. What are chromosomes? Explain stability of the DNA of the species is ensured in sexually reproducing organisms.
Answer:

  • Chromosomes are thread-like entities based in the nucleus. Their DNA contains the genetic elements of the species. Every cell contains two copies of each chromosome.
  • In germ cells, generated post-meiosis, just one chromosome of each kind is present.
  • It may be either paternal or maternal. During fertilization, two gametes merge, reinstating the diploid state of chromosomes in the zygote and the subsequent cells of the organism derived from it.

Question 10.

  1. Name the two types of gametes produced by men.
  2. Does a male child inherit an X chromosome from his father? Justify.
  3. How many types of gametes are produced by a human female?

Answer:

  1. Men produce two types of sperms, X-carrying (gymnosperms) and Y-carrying (angiosperms) in equal proportion.
  2. No. A male child inherits the X chromosome from his mother. From their father, he inherits the Y chromosome.
  3. The female produces only one type of ova. They carry X chromosomes.

 

MPBSE Class 10 Science Chapter 6 Life Processes Question and Answers

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MPBSE Class 10 Science Life Processes Question and Answers

Question 1. (1) How many times does the blood go through the heart during one cycle in fish and why?

{2) List the respiratory pigment present in our body. Where is it present?

(3) Why are valves present in the heart and veins?
Answer:

  1. Fish have a single circulation of blood in contrast to double circulation in humans. In fish, the heart pumps the blood into the gills for purification. From the gills, the purified blood goes to the body and then comes back to the heart for pumping.
  2. Haemoglobin is the respiratory pigment. It is present in the red blood corpuscles.
  3.  Valves are present in the heart and veins to prevent the backflow of blood.

Question 2. (1) Explain in brief the mechanism of circulation of blood in the human body.

(2) “Lymph is another type of fluid involved in transportation.” Justify the statement by explaining the process.
Answer:

(1) The right atrium receives deoxygenated blood from the heart (coronary sinus), upper part of the body (superior vena cava), and middle and lower part of the body (inferior vena cava). The left atrium receives oxygenated blood from the lungs.

  • As the two atria get filled, they contract simultaneously and pour their blood into the ventricles of their side through auriculo-ventricular apertures.
  • On getting filled, the ventricles undergo systole. The left ventricle sends oxygenated blood to all body parts through the systemic aorta. The right ventricle sends deoxygenated blood to the lungs through the pulmonary arch for oxygenation.

(2) Lymph is a transportation fluid formed from tissue fluid. It is specialised to collect large size secretions and excretions which cannot directly pass into the blood, For Example., proteins, hormones, and fat. The lymph picks them and pours their contents into the blood in the region of the subclavian vein.

Life Processes Class 10 Questions And Answers

Question 3. (1)(A) Receives deoxygenated blood from vena cava (B) Sends deoxygenated blood to the lung through the pulmonary artery (C) Receives oxygenated blood from lungs and (D) Sends oxygenated blood to all parts of the body through the aorta.

(2) What does the blood consist of?

(3) Name the respiratory pigment in human beings and discuss its role.
Answer:

  1. (A) Right atrium (B) Right ventricle (C) Left atrium (D) Left ventricle.
  2. Blood consists of blood plasma (55%) and blood cells (45%) of three types red blood corpuscles, white blood corpuscles and blood platelets.
  3. Haemoglobin is the respiratory pigment that is found in red blood corpuscles. It carries oxygen as oxyhaemoglobin and a part of carbon dioxide as carbaminohaemoglobin.

Question 4. What is lymph? How is the composition of lymph different from blood plasma? What is the direction of its flow? List two functions of the lymphatic system.
Answer:

Lymph is a straw-coloured viscous fluid which is formed from tissue fluid and flows inside tubes called lymph vessels.

Lymph differs from blood plasma in having :

  1. 94% water instead of 92% in plasma
  2. 3.0 to 4.5 per cent protein instead of 6-8% protein in blood plasma
  3. Globulin and fibrinogen contents are lower
  4. Lymph receives a direct supply of secretion and excretion of tissues while blood obtains the same from lymph.

Direction of Flow. Unidirectional from tissues all over the body to subclavian veins.

Functions of Lymphatic System.

  1.  The lymphatic system functions as a middleman between tissue fluid and blood,
  2. It picks up germs and takes them to lymph nodes for disposal.

Question 5. (A) What do the following transport: (1) Xylem (2) Phloem (3) Pulmonary vein (4) Vena Cava?

(B) Write two points of difference between the pulmonary artery and the pulmonary vein.
Answer:

  1. (A) Xylem. Transports sap (water and mineral salts) from roots to aerial parts of the plant.
  2. Phloem. It translocates food and other solutes from a place of manufacture or storage to a place of utilisation both in upward and downward directions.
  3.  Pulmonary Vein. It carries oxygenated blood from the lungs to the left auricle.
  4. Vena Cava. It carries deoxygenated blood from different parts of the body to the right auricle. Differences between Pulmonary Artery and Pulmonary Vein

Transportation Difference Between Pulmonary Artery And Pulmonary Vein

Mpbse Class 10 Science Chapter 6 Solutions

Question 6. (1) The upward movement of water normally requires a pump in our houses but in tall trees, water rises up without any external support. Explain the mechanism.

(2) State three points of difference between the transport of materials in the xylem and phloem.
Answer:

(1) Water rises up the top of the tallest plants through the development of a negative pressure caused by loss of water in transpiration. Transpiration or loss of water in vapour form occurs from mesophyll and other cells of aerial parts.

  1. As there are innumerable numbers of cells losing water, they develop a tremendous suction pressure and withdraw water from the nearby xylem channels. This puts the water present in the xylem channel under a negative pressure of 10-20 atm.
  2. Negative pressure or pull caused by transpiration is unable to break the continuity of the water column due to the presence of cohesion force amongst water molecules and adhesion force between water and the wall of the xylem channel.
  3. The negative pressure or transpiration pull reaches the root region and forces water to move upwards. It is just like upward pulling of a cold drink with the help of a straw pipe. The mechanism of the ascent of sap through transpiration pull and cohesion force was given by Dixon and Jolly (1894).

Transportation Difference Between Transport In Xylem And Phloem

2. Force. It comes from the development of negative press- 2. It develops from the formation of turgor pressure, sure or transpiration pull.

3. Channel. The conducting channels are made of the conducting channels are formed of living sieves dead lignified elements, vessels and tracheids. tube elements.

Question 7. (1) Mention any two components of blood.

(2) Trace the movement of oxygenated blood in the body.

(3) Write the function of valves present in between atria and ventricles.

(4) Write one structural difference between artery and vein.
Answer:

  1. Composition of Blood. Blood cells—45%. Plasma—55%. Blood cells arc of three types—red blood corpuscles, white blood corpuscles and blood platelets.
  2. Movement of Oxygenated Blood. Blood is oxygenated in the lungs. Pulmonary veins carry the oxygenated blood from the lungs to the left atrium. The left atrium pours the oxygenated blood into the left ventricle. On contraction left ventricle pushes the oxygenated blood into the aorta for supply to various parts of the body.
  3.  Function of Valves. A tricuspid valve lies over the right atrioventricular aperture. A bicuspid valve occurs over the left atrioventricular aperture. They are meant to prevent the backflow of blood into the atria when the ventricles contract.
  4. Artery’ and Vein. An artery has a thicker elastic well and a narrower lumen while the vein has a thinner nonelastic wall with wider lumen and semilunar valves for preventing backflow of blood.

Important Questions Of Life Processes Class 10

Question 8. (1) Write two water-conducting elements present in plants. How does water enter continuously into the root system?

(2) Explain why plants have low energy needs as compared to animals.
Answer:

  1. The two water-conducting elements of plants are tracheids and vessels. Continuous Entry of Water.
  2.  Plants have low energy requirements.

Question 9. List in tabular form three differences between blood and lymph.
Answer:

Transportation Difference Between The Blood And Lymph

Question 10. “Blood circulation in fishes is different from the blood circulation in human beings.” Justify the statement.
Answer:

Fishes have two-chambered venous hearts with a single circulation. Human beings have four-chambered arterio¬venous hearts with double circulation.

Question 11. (1) Write the correct sequence of steps followed during the journey of oxygen-rich blood from the lungs to various organs of the human body.

(2) What happens when the system of blood vessels develops a leak?
Answer:

1. Lungs → Pulmonary veins → Left atrium → Left atrial diastole followed by contraction → Left ventricle → Left ventricle diastole followed by contraction → Aorta → Various parts of body except lungs.

2. (A) Leakage will reduce blood quantity, blood pressure mid-efficiency of a pumping system,

(B) Blood coagulation at the site of length will plug the leakage

Life Processes Class 10 Mcq

Question 13. Give Reasons

  1. Ventricles have thicker muscular walls than atria
  2. The transport system in plants is slow
  3. The circulation of blood in aquatic vertebrates differs from that in terrestrial vertebrates.
  4. During the daytime, water and minerals travel faster through the xylem as compared to the night.
  5. Veins have valves whereas arteries do not.

Answer:

  1. Thicker Walls of Ventricles.
  2. Slow Transport in Plants. Plants have a lower requirement of energy.
  3.  In aquatic vertebrates, like lush there is a single blood circulation while in terrestrial vertebrates there is double circulation.
  4. The rate of water and mineral movement is higher during the daytime due to very high transpiration.
  5. There is no forceful movement of blood in the veins. Veins possess valves to prevent backflow.

MPBSE Class 11 Chemistry Hydrogen Multiple Choice Question and Answers

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Class 11 Hydrogen Important Questions

MPBSE Class 11 Chemistry Hydrogen Multiple Choice Question and Answers

Question 1. At absolute zero

  1. Only para-hydrogen exists
  2. Onlypara- hydrogen exists
  3. Both ortho- and para-hydrogen exist
  4. Neither para- nor ortho-hydrogen exists

Answer: 1. Only para-hydrogen exists

Question 2. In which of the following reaction dihydrogen acts as an oxidising agent—

  1. F2 + H2 → 2HF
  2. Cl2 + H2  → 2HC1
  3. N2 + 3H2 →2NH3
  4. 2Na + H2 → 2NaH

Answer: 4. 2Na + H2 → 2NaH

Question 3. Which of the following halogens has the least affinity towards hydrogen—

  1. I2
  2. CI2
  3. Br2
  4. F2

Answer: 1. I2

Question 4. Which of the following compounds on electrolysis produces hydrogen—

  1. dil. H2S04
  2. dil. solution of NaOH
  3. Ba(OH)2 solution
  4. KOH solution

Answer: 3. Ba(OH)2 solution

Hydrogen Mcq Class 11

MPBSE Class 11 Chemistry MCQs Question 5. The thermal stability of Gr.-15 hydrides follows the order

  1. ASH3 > PH3 > NH3 > SbH3 > BiH3
  2. NH3 > PH3 > ASH3 > SbH3 > BiH3
  3. NH3 > AsH3 > PH3 > SbH3 > BiH3
  4. BiH3 > SbH3 > AsH3 > PH3 > NH3

Answer: NH3 > PH3 > ASH3 > SbH3 > BiH3

MPBSE Class 11 Chemistry Hydrogen Multiple Choice Question and Answers

Question 6. The correct order of vaporization enthalpy of the following hydride is

  1. NH3<PH3<AsH3
  2. AsH3<PH3<NH3
  3. PH3<AsH3<NH3
  4. NH3<AsH3<PH3

Answer: 3. PH3<AsH3<NH3

Question 7. Interstitial hydrides are formed by—

  1. S-block elements
  2. P-block elements
  3. D-block elements
  4. Intert gas elements

Answer: 3. D-block elements

Question 8. The correct descending order of thermal stability of alkali metals hydrides is—

  1. LiH > NaH > KH > RbH > CsH
  2. CsH > RbH > KH > NaH > LiH
  3. NaH > KH > LiH > CsH > RbH
  4. CsH > LiH > KH > NaH > RbH

Answer: 1. LiH > NaH > KH > RbH > CsH

Class 11 Chemistry Hydrogen Mcqs

MPBSE Class 11 Chemistry MCQs  Question 9. Solubility of NaClin the solvents H20 and DaO is

  1. Equal in both
  2. More in D20
  3. More in H20
  4. Only in H20

Answer: 3. More in H20

Class 10 ScienceClass 11 Chemistry
Class 11 ChemistryTransformation of Sentences
Class 8 MathsClass 8 Science

Question 10. The degree of hardness of 1L sample water containing 0.002 mol MgS04 is

  1. 20 ppm
  2. 200 ppm
  3. 2000ppm
  4. 120ppm

Answer: 2. 200 ppm

Question 11. Which of the following reacts with water to produce electron-precise hydrides—

  1. Ca3P2
  2. AI4C3
  3. Mg3N2
  4. None of these

Answer: 2. Al4C3

Hydrogen Class 11 MCQ Question 12. Which of the following couples reacts with water to produce the same gaseous product—

  1. K and K02
  2. K and K02
  3. Na and Na202
  4. Ba and Ba02

Answer: 2. K and K02

Question 13. Which of the following compounds contain free hydrogen

  1. Water
  2. Marsh gas
  3. Water gas
  4. Acid

Answer: 3. Water gas

Question 14. Which of the following reacts with metallic sodium to produce hydrogen—

  1. CH4
  2. C2H6
  3. C2H4
  4. C2H2

Answer: 4. C2H2

Question 15. Semi-water gas is

  1. CO + H2 + N2
  2. H2 + CH4
  3. CO + H2+ O2
  4. CO + H2

Answer: 1. CO + H2 + N2

Hydrogen Class 11 Ncert Solutions

Question 16. Which of the following metals does not react with cold water liberates H2  with boiling water

  1. Na
  2. K
  3. Pt
  4. Fe

Answer: 4. Fe

Question 17. Volume of ’10 volume’ H202 required to convert 0.01 mol PbS into PbS04 is—

  1. 11.2 mL
  2. 22.4 mL
  3. 33.6 mL
  4. 44.8 mL

Answer: 4. 44.8 mL

Hydrogen Class 11 MCQ Question 18. On dilution of H202, the value of dielectric constant

  1. Increases
  2. Remains same
  3. Decreases
  4. None of these

Answer: 1. Increases

Question 19. By which of the following water gets oxidized to oxygen

  1. Cl02
  2. KMn04
  3. H202
  4. F2

Answer: 4. F2

Question 20. Which of the following does not get oxidized by H202

  1. Na2S03
  2. PBS
  3. KI
  4. O3

Answer: 4. O3

Question 21. The temperature at which the density of D20 is maximum is

  1. 9°C
  2. 11.5°C
  3. 15.9°C
  4. 20°C

Answer: 11.5°C

Question 22. Which of the following undergoes disproportionation reaction with water—

  1. S03
  2. F2
  3. Cl2
  4. N2

Answer: 2. F2

Multiple Choice Questions On Hydrogen

Hydrogen Class 11 MCQ Question 23. Which of the following undergoes disproportionation reaction with water—

  1. S03
  2. F2
  3. Cl2
  4. N2

Answer: 3. Cl2

Question 24. The non-inflammable hydrides

  1. NH3
  2. PH3
  3. ASH3
  4. SbH3

Answer: 1. NH3

Question 25. The triple point of water is

  1. 203K
  2. 193K
  3. 273K
  4. 373K

Answer: 3. 273K

Question 26. The process by which hydrogen is prepared by the reaction of silicon, iron alloy, and NaOH is

  1. Woodprocess
  2. Haber’s process
  3. Silicol process
  4. Bosch process

Answer: 3. Silicol process

Multiple Choice Questions On Hydrogen

Question 27. An element reacts with hydrogen to form a compound A, which in reaction with water liberates hydrogen again. The elements—

  1. Cl
  2. CS
  3. Se
  4. N2

Answer: 2. CS

Question 28. Only one element of which of the following groups forms a metal hydride

  1. Gr-6
  2. Gr-7
  3. Gr-8
  4. Gr-9

Answer: 1. Gr-6

Question 29. An acidic solution of which of the following turns orange in the presence of H202 —

  1. Ba02
  2. Na202
  3. Ti02
  4. Pb02

Answer: 3. Ti02

Question 30. In the following reaction the isotopic oxygens \(2 \mathrm{MnO}_4^{-}+3 \mathrm{H}_2 \mathrm{O}_2^{18} \rightarrow 2 \mathrm{MnO}_2+3 \mathrm{O}_2+2 \mathrm{H}_2 \mathrm{O}+2 \mathrm{OH}^{-}\)

  1. Both get converted into 02
  2. Both get converted into oh
  3. Both get converted into more
  4. One of them gets converted to 02, another to mn02

Answer: Both get converted into 02

Question 31. X on electrolysis produces Y which on vacuum distillation produces H202. The numbers of peroxo linkage present X and Y are

  1. 1,1
  2. 1,2
  3. 0>1
  4. 0,0

Answer: 3. 0>1

Question 32. The compound which on electrolysis in its molten or liquid state liberates hydrogen at the anode is

  1. NaOH
  2. CaH2
  3. HC1
  4. H20

Answer: 2. CaH2

Question 33. Which of the following couples exhibit the maximum isotope effect

  1. H D
  2. O O
  3. CI CI
  4. C C

Answer: 1. H D

Class 11 Chemistry Hydrogen Mcqs

Question 34. Which of the following emits by tritium

  1. Neutron
  2. Ray
  3. Particle
  4. Particle

Answer: 3. Particle

MPBSE Class 11 Chemistry MCQs Question 35. Oxidation of benzene by H202 in the presence of ferrous sulfate produces

  1. Pheno
  2. Cyclohexane
  3. Anisole
  4. Benzaldehyde

Answer: 1. Pheno

Multiple Choice Questions On Hydrogen

Question 36. The oxidation state of Cr in the product obtained by the reduction of K2Cr20? by atomic hydrogen is

  1. +6
  2. +2
  3. 0
  4. +3

Answer: 4. +3

Question 37. Which of the following does not get reduced by H2 in its aqueous solution

  1. Cu2+
  2. Fe3+
  3. Zn2+
  4. Ag+

Answer: 3. Zn2+

Question 38. Which of the following compounds has a similar odor as that of H202

  1. Caustic soda
  2. Chloroform
  3. Alcohol
  4. Nitric acid

Answer: 4. Nitric acid

Question 39. Which of the following compounds reacts with atomic hydrogen to form formaldehyde

  1. CO
  2. C02
  3. CH4
  4. C2H2

Answer: 1. CO

Class 11 Chemistry Hydrogen Mcqs

Question 40. Which of the following isotopes of hydrogen is the most reactive

  1. H
  2. H
  3. H
  4. All the isotopes are equally reactive

Answer: 1. H

MPBSE Class 11 Chemistry MCQs Question 41. When equal amounts of Zn are allowed to react separately with excess H2S04 and excess NaOH, then the ratio of the volumes of hydrogen produced for the first and the second case respectively

  1. 1:2
  2. 2:1
  3. 4:9
  4. 1:1

Answer: 4. 1:1

Question 42. Which of the following hydrides of s-block elements have a polymeric structure

  1. LiH
  2. BeH2
  3. No
  4. MgH2

Answer: 2. BeH2

Question 43. Which of the following statements is true—

  1. Ifz= 15, the element forms a covalent hydride
  2. Ifz= 23, the element forms an ionic hydride
  3. Ifz= 19, the element forms an ionic hydride
  4. Ifz= 44, the element forms metalic hydride

Answer: 1. Ifz= 15, the element forms a covalent hydride

Question 44. Which of the following hydrides are polynuclear hydrides

  1. No
  2. C3H8
  3. N2H4
  4. HF

Answer: C3H8

Question 45. Which of the following statements is correct

  1. Metallic hydrides are hydrogen-deficient
  2. Metallic hydrides are conductors of heat and electricity
  3. Ionic hydrides in their solid state do not conduct electricity
  4. Ionic hydrides on electrolysis in their molten state produce h2 at the cathode.

Answer: 1. Metalic hydrides are hydrogen deficient

Question 46. Which of the following ions get exchanged with Na+ ion of zeolite when zeolite is added to thehard water

  1. H+ ion
  2. Ca2+ ion
  3. So+ ion
  4. Mg2+ ion

Answer: 2. Ca2+ ion

MPBSE Class 11 Chemistry MCQs Question 47. Which of the following reactions are neurolysis

  1. 2Na + 2D20 → 2NaOD + D2
  2. AlClg + 3D20 →Al(OD)3 + 3DC1
  3. Ca + 2D20→ Ca(OD)2 + D2
  4. Fe2(S4)3 + 6D20-> 2Fe(0D)3 + 3D2S04

Answer: 2. AlClg + 3D20→ Al(OD)3 + 3DC1

Multiple Choice Questions On Hydrogen

Question 48. Which of the following reactions are redox reactions

  1. H2O + so2 → H2SO3
  2. CaO + H20 → Ca(OH)2
  3. 2Na + 2H20 → 2NaOH + H2
  4. 2F2 + 2H20 → 02 + 4HF

Answer: 3. 2Na + 2H20 → 2NaOH + H2

Question 49. In which of the following reactions H202 acts as a reductant—

  1. CgHg + H202 → CgHgOH + H220
  2. PbS + 4H202 → PbS04 + 4H20
  3. Na0Br +H202 → NaBr + H20 + 02
  4. 2Mn04 +6H+ + 5H202 → 2Mn2+ + 8H20 + 502

Answer: 3. Na0Br +H202 → NaBr + H20 + 02

Question 50. Which of the properties are the same for a metal and its hydride

  1. Hardness
  2. Electrical conductance
  3. Magnetic property
  4. Metallic lustre

Answer: 1. Hardness

Question 51. The correct orders are—

  1. H2 < D2 < T2 : boilingpoint
  2. H2 < D2 < T2 : freezing point
  3. H2 < D2 < T2 : latent heat ofvaporisation
  4. T2O > H20 > D20 : dissociation constant

Answer: 1. H2 < D2 < T2 : boilingpoint

Question 52. Which of the following reacts with zinc to produce hydrogen gas

  1. dil.HCl
  2. cold water
  3. hot NaOH solution
  4. cone. H2S04

Answer: 2. cold water

Question 53. Which of the following properties has a greater magnitude in D20 than that in H20

  1. Viscosity
  2. Surface tension
  3. dielectric constant
  4. latent heat of vaporisation

Answer: 2. Viscosity

Question 54. Which of the following metal hydrides get reduced by hydrogen

  1. CuO
  2. Pb304
  3. Na202
  4. MgO

Answer: 1. CuO

Multiple Choice Questions On Hydrogen

Question 55. Multimolecular covalent hydrides of s-block are

  1. LiH
  2. BeH2
  3. NaH
  4. MgH2

Answer: 2. BeH2

MPBSE Class 11 Chemistry MCQs Question 56. The oxidation numbers of the most electronegative element in the product were obtained due to the reaction between Ba02 and dil. H2S04 are—

  1. -1
  2. 0
  3. -2
  4. +1

Answer: 1. -1

Question 57. Which of the following compounds decreases the rate of decomposition of H202 —

  1. CO(NH2)2
  2. Mn02
  3. PbNHCOCH3
  4. (COOH)2

Answer: 1. CO(NH2)2

Question 58. Which of the following produces H202 on hydrolysis

  1. Pemitricacid
  2. Perchloric acid
  3. Perdisulphuric acid
  4. Caro’s acid

Answer: 1. Pemitricacid

Question 59. Choose the correct statements

  1. The concentration of 20 volume H202 solution is 60.7g L-1
  2. volume strength of 2(N)H202 solution is 15
  3. volume strength of 2(N)H202 solutions 11.2
  4. The concentration of the 20-volume H202 solution is 50.7g. L-1

Answer: 1. The Concentration of 20-volume H202 solution is 60.7g L-1

Question 60. Choose the correct alternative—

  1. a mixture of HCl and HCIO is formed when chlorine reacts with cold water
  2. arrange color of K2Cr207 solution turns blue when it reacts with H202
  3. under low pressure, isopropyl alcohol reacts with a small amount of H202 to produce formaldehyde
  4. hydrolith produces black coloured product when it reacts with PbS04

Answer: 1. a mixture of HC1 and HCIO is formed when chlorine reacts with cold water

Question 60. Which of the following alternatives is not true—

  1. The correct order of reactivity of h2 towards the halogens
  2. Is: cl2 > br2 > i2 > f2
  3. The concentration of h202 used in rockets is 90%
  4. H2 gets more readily absorbed on the surface of metal than d2
  5. Conversion of atomic hydrogen into molecular hydrogens is an exothermic process

Answer: 1. Correct order of reactivity of h2 towards the halogens