MPBSE Class 12 Physics Ohm’s Law Multiple Choice Question And Answers

Class 12 Physics Ohm’s Law Multiple Choice Question And Answers

Question 1. Two copper wires have a ratio of 1: 4 between their diameters. If the same current passes through both of them, the drift velocity of the electrons will be in the ratio of

  1. 16:1
  2. 4: 1
  3. 1:4
  4. 1:16

Answer: 1. 16:1

Question 2. A conductor of uniform cross-section is carrying a current of 1 ampere. The number of free electrons flowing across the cross-section of the conductor per second is

  1. 6.25 x 1018
  2. 6.25 x 1017
  3. 6.25 X 1016
  4. 6.025 x 1023

Answer: 1. 6.25 x 1018

1 A electric current = the flow of 1 C charge through the cross-sectional area of the conductor in 1 second.

∴ Number of free electrons flowing per second

⇒ \(\frac{1 \mathrm{C}}{\text { charge of an electron }}\)

= \(\frac{1 \mathrm{C}}{1.6 \times 10^{-19} \mathrm{C}}\)

= \(6.25 \times 10^{18}\)

The option 1 is correct.

Question 3. In the circuit,

Class 12 Physics Current Electricity Electric Current and Ohm's Law In Circuit

  1. I = 3A
  2. I1 = 2A
  3. I2 = 1A
  4. VAB = 8V

Answer:

1. I = 3A

2. I1 = 2A

3. I2 = 1A

Ohm’S Law Mcq Class 12 Physics

Question 4. In the circuit,

Class 12 Physics Current Electricity Chapter 1 Electric Current and Ohm's Law Circuit

  1. I = 1 A
  2. I = \(\frac{4}{3}\)A
  3. VAB = 4 V
  4. VAB = 3 V

Answer:

1. I = 1 A

4. VAB = 3 V

Class 12 Physics Ohm’s Law MCQs Question 5. If I = 2 A in the circuit

Class 12 Physics Current Electricity Electric Current and Ohm's Law The Circuit

  1. E = 5 V
  2. I1 = 1.5 A
  3. I2 = 0.5 A
  4. VAB = 3 V

Answer:

1. E = 5 V

2. I1 = 1.5 A

3. I2 = 0.5 A

4. VAB = 3 V

Ohm’S Law Mcq Class 12 Physics

Question 6. If the resistance of the rheostat Rh is gradually increased in the circuit,

Class 12 Physics Current Electricity Electric Current and Ohm's Law The Resistance Of The Rehostar

  1. I will rise gradually
  2. I will fall gradually
  3. I1 will rise gradually
  4. I1 will fall gradually

Answer:

2. I will fall gradually

3. I1 will rise gradually

Question 7. Which of the following observations is correct if the galvanometer resistance is 200Ω in the circuit

Class 12 Physics Current Electricity Electric Current and Ohm's Law Galvanometer Resistance

  1. S = 5Ω, I = 1.5 A,IG = 36.6 mA
  2. S = 1Ω, I = 1.5 A, IG = 14.9 mA
  3. S = 2Ω, I = 2 A, IG = 19.8 mA
  4. S = 3Ω, I = 2 A, IG = 29.6 mA

Answer:

1. S = 5Ω, I = 1.5 A,IG = 36.6 mA

3. S = 2Ω, I = 2 A, IG = 19.8 mA

4. S = 3Ω, I = 2 A, IG = 29.6 mA

Question 8. Brown, black, orange, and gold are the respective colors of the characteristic rings on a carbon resistor. Which of the following values of its resistance are definitely wrong?

  1. 10.6 kΩ
  2. 10.2 kΩ
  3. 9.8 kΩ
  4. 9.4 kΩ

Answer:

1. 10.6 kΩ

4. 9.4 kΩ

Mpbse Class 12 Physics Ohm’S Law Mcqs

Question 9. Three 4Ω resistances can be connected in different combinations. The probable values of the equivalent resistance are

  1. 12Ω
  2. \(\frac{10}{3}\)Ω
  3. \(\frac{4}{3}\)Ω

Answer:

1. 12Ω

2. 6Ω

4. \(\frac{4}{3}\)Ω

Class 12 Physics Ohm’s Law MCQs  Question 10. E1, E2, and r1,r2 are respectively, the emf’s and internal resistances of two cells. The current through an external resistance R, when it is connected to the first cell, is equal to that when it is connected to the second. Here, the probable relations are

  1. E1 = E2,r1 = r2
  2. E1 > E2, r1 > r2
  3. E1 < E2, r1 < r2
  4. E1 > E2, r1 < r2

Answer:

1. E1 = E2,r1 = r2

2. E1 > E2, r1 > r2

3. E1 < E2,r1 < r2

Question 11. A voltmeter and an ammeter are connected in series to an ideal cell of emf E. The voltmeter reading is V and the ammeter reading is I. Choose the correct options.

  1. The voltmeter resistance is \(\frac{V}{I}\)
  2. The potential difference across the ammeter is (E- V)
  3. V<E
  4. Voltmeter resistance + ammeter resistance = \(\frac{E}{I}\)

Answer:

1. The voltmeter resistance is \(\frac{V}{I}\)

2. The potential difference across the ammeter is (E- V)

3. V

Ohm’S Law Multiple Choice Questions

Question 12. Part of a circuit. Which points have the potential same as that of point m?

Class 12 Physics Current Electricity Electric Current and Ohm's Law A Circuit

  1. p
  2. r
  3. t
  4. u

Answer:

2. r

3. t

Question 13. A galvanometer has a resistance of 100Ω and a full-scale range of 50μA. It can be used as a voltmeter or as a higher range ammeter, provided a resistance is added to it. Pick the correct range and resistance combination(s).

  1. 50 V range with 10kΩ resistance in series
  2. 10 V range with 200 kΩ .resistance in series
  3. 5 mA range with 1Ω resistance in parallel
  4. 10 mA range with 1Ω resistance in parallel

Answer:

2. 10 V range with 200 kΩ .resistance in series

3. 5 mA range with 1Ω resistance in parallel

Question 14. A straight conductor AB lies along the axis of a hollow metal cylinder, which is connected to the earth through a conductor C. A quantity of charge will flow through C if

Class 12 Physics Current Electricity Electric Current and Ohm's Law Hollow Metal Cylinder

  1. A Current begins to flow through AB
  2. The current through AB is reversed
  3. AB is removed and a beam of protons flows in its place
  4. AB is removed, and a beam of electrons flows in its place

Answer:

3. AB is removed and a beam of protons flows in its place

4. AB is removed, and a beam of electrons flows in its place

Ohm’S Law Multiple Choice Questions

Class 12 Physics Ohm’s Law MCQs  Question 15. To double the full-scale voltage reading of any galvanometer turned into a voltmeter, you must

  1. Increase the resistance to 3R
  2. Half the resistance R
  3. Increase the resistance to 4R
  4. None of the above

Answer: 4. None of the above

Question 16. The resistance Ω of a conducting wire depends on its material, length l, and area of cross-section A. The resistivity of the material of the wire is p = \(\frac{RA}{l}\) the value of p is different for different materials. It is very low for conducting materials, like metals. Besides, the resistance of a conductor also depends on its temperature. If the resistance of a conductor is R0 at 0° C, and Rt at t° C, then Rt = R0(1 + αt), where a is called the temperature coefficient of resistance. The resistance increases with temperature for metallic conductors but decreases for graphite, a few metal alloys, and for semiconductors like silicon and germanium.

1. The resistance of a metal wire increases by 10% when its temperature rises from 10° C to 110° C. The temperature coefficient of resistance of the metal is

  1. 0.02 °C-1
  2. 0.01 °C-1
  3. 0.002 °C-1
  4. 0.001 °C-1

Answer: 4. 0.001 °C-1

2. The length of this metal wire is doubled by stretching. What will be the change in its resistance?

  1. 100% increase
  2. 200% increase
  3. 300% increase
  4. 500% decrease

Answer: 3. 300% increase

3. The temperature of this new wire is again raised from A B 10°C to 110°C. The percentage increase of its resistance would be

  1. 5%
  2. 10%
  3. 20%
  4. 40%

Answer: 2. 10%

4. The temperature coefficient of resistance of a semiconductor is

  1. Zero
  2. Positive
  3. Negative
  4. Positive or negative depending on the material

Answer: 3. Negative

Electric Resistance Mcq Class 12 Physics

5. The graphs of the relations between current (I) and potential difference (V) of a metal wire at two different temperatures t1 and t2. The relation between t1 and t2 is

Class 12 Physics Current Electricity Electric Current and Ohm's Law A Metal Wire

  1. t1 = t2
  2. t1 < t2
  3. t1 > t2
  4. Insufficient data

Answer: 2. t1 < t2

Question 17. If a current passes through a metal conducting wire of area of cross-section A, the drift velocity of free electrons inside the metal is vd = \(\frac{1}{neA}\) where the amount of electric charge of an electron = e, and the number of free electrons per unit volume of the metal =n. The applied electric field on the wire is E = \(\frac{V}{l}\) y, where a potential difference V exists between two points,l apart, along the length of the wire. If R is the resistance of the wire between those two points, then the resistivity of its material is \(\rho=\frac{R A}{l}\). Besides, the mobility (μ) of the free electrons inside a wire is defined as their drift velocity for a unit-applied electric field.

1. Two copper wires have both lengths and radii in the ratio 1: 2. If the ratio between the electric currents flowing through them is also 1: 2, what would be the ratio between the drift velocities of free electrons?

  1. 1:1
  2. 1:2
  3. 2:1
  4. 4:1

Answer: 3. 2:1

2. The radii of two wires of the same metal are in the ratio 1: 2. The same potential difference is applied between two points at a distance on each of the wires. The ratio between the drift velocities of the free electrons in two wires is

  1. 1:1
  2. 1:2
  3. 2:1
  4. 1:4

Answer: 2. 1:2

Class 12 Physics Ohm’s Law MCQs  3. The radii of two wires, made of two different metals, are in the ratio 1: 2. The number density of free electrons in the first metal is double that in the second metal. If the current in the first wire is 1 A, then the current In the second wire producing the same drift velocity is

  1. 1 A
  2. 2 A
  3. 4 A
  4. 8 A

Answer: 3. 4 A

4. Tire current through unit cross-section of a conductor, culled tire electric current density J, Is related to the applied electric field E as

  1. J = \(\rho\)E
  2. \(J=\frac{1}{\rho} E\)
  3. J = μE
  4. \(J=\frac{1}{\mu} E\)

Answer: 2. \(J=\frac{1}{\rho} E\)

Electric Resistance Mcq Class 12 Physics

Question 18. Measurements and Interpretations of voltage and electric current signals are common In modern medicine. Occasionally, a situation arises In which a voltmeter or an ammeter Is needed but it Is not available. A galvanometer Is an instrument dial that can be used to construct an ammeter (for measuring electric currents). It can also be used to construct a voltmeter (to measure voltages). In both cases, a resistor R must be connected to the galvanometer to effect the change. To turn the galvanometer into an ammeter, the resistor R is connected in parallel. The resistor R is connected in series with the galvanometer in order to turn it into a voltmeter. The current required to produce a full-scale deflection in a galvanometer is 10mA. The internal resistance of the galvanometer is 100Ω. Let Vr be the voltage across r and VR the voltage across R.

1. Which of the following relations correctly applies to the ammeter?

  1. Vr>VR
  2. Vr < VR
  3. Vr=VR
  4. More information is required

Answer: 1. Vr>VR

2. What resistance must be connected in parallel to the galvanometer to turn It into an ammeter capable of reading electric currents up to 10.01 A?

  1. 0.1Ω
  2. 10Ω
  3. None

Answer: 1. 0.1Ω

3. What resistance R must be connected in series to the galvanometer in order to convert it to a 100 V voltmeter?

  1. 900Ω
  2. 1000Ω
  3. 9900Ω
  4. 10000Ω

Answer: 3. 9900Ω

4. In the voltmeter circuit, the current in the resistor R must be

  1. Negligible, so that it has only a small effect on the voltage reading
  2. Substantial, but does not have any effect on the voltage reading
  3. Substantial, but does have some effect on the voltage reading
  4. None of the above

Answer: 1. Negligible, so that it has only a small effect on the voltage reading

Class 12 Physics Ohm’s Law MCQs  5. Which of the following relations correctly applies to the voltmeter circuit?

  1. Vr>VR
  2. Vr<VR
  3. Vr=VR
  4. Vr = 2VR

Answer: 2. Vr<VR

Ohm’S Law Mcq Class 12 Physics

Question 19. Two cells each of emf e but internal resistances r1 and r2 are connected in series through an external resistance R. If the potential difference across the first cell is zero while current flows, the relation of R in terms of r1 and r2 is

  1. R = r1 + r2
  2. R = r1-r2
  3. R = \(\frac{1}{2}\) (rj + r2)
  4. R = \(\frac{1}{2}\)(r1 – r2)

Answer: 2. R = r1-r2

Question 20. Resistance of the thinner wire is 10Ω, then the resistance of the other wire will be

  1. 40Ω
  2. 20Ω
  3. 10Ω

Answer: 3. 10Ω

\(R=\rho \frac{l}{A}=\frac{\rho l}{\pi r^2}\)

∴ \(\frac{R_1}{R_2}=\frac{\rho_1}{\rho_2} \cdot \frac{l_1}{l_2} \cdot\left(\frac{r_2}{r_1}\right)^2=\frac{1}{3} \times \frac{1}{3} \times\left(\frac{3}{1}\right)^2=1\)

R2 = R1 = 10Ω

The option 3 is correct

Question 21. Four cells, each of emf E . and internal resistance r, are connected in series across an external resistance R. By mistake one of the cells is connected in reverse. Then the current in the external circuit is

  1. \(\frac{2 E}{4 r+R}\)
  2. \(\frac{3 E}{4 r+R}\)
  3. \(\frac{3 E}{3 r+R}\)
  4. \(\frac{2 E}{3 r+R}\)

Answer: 1. \(\frac{2 E}{4 r+R}\)

Currently the circuit,

⇒ \(I=\frac{3 E-E}{4 r+R}=\frac{2 E}{4 r+R}\)

The option 1 is correct.

Class 12 Physics Ohm’s Law MCQs  Question 22. A circuit consists of three batteries of emf E1 = 1V, E2 = 2 V, and E3 = 3V and internal resistances 1Ω, 2Ω, and 1Ω respectively which are connected in parallel. The potential difference between points P and Q is

Class 12 Physics Current Electricity Electric Current and Ohm's Law A Circuit Consists Of Three Batteries

  1. 1.0V
  2. 2.0V
  3. 2.2V
  4. 3V

Answer: 2. 2.0V

Equivalent resistance of the internal resistances connected in parallel

= \(\frac{2}{5}\)Ω

Total current = \(\frac{1}{1}+\frac{2}{2}+\frac{3}{1}\)

= 5V

∴ The potential difference between points P and

Q = 5 x \(\frac{2}{5}\)

= 2V

The option 2 is correct

Ohm’S Law Mcq Class 12 Physics

Question 23. A metal wire of a circular cross-section has a resistance. The wire is now stretched without breaking so that its length is doubled and the density is assumed to remain the same. If the resistance of the wire now becomes R2 then R2: R1 is

  1. 1:1
  2. 1:2
  3. 4:1
  4. 1:4

Answer: 3. 4: 1

If the length of the wife is l and its cross-sectional area is A, the volume of the wire, V = lA = constant.

Then, A = \(\frac{V}{l}\)

Now, from the relation \(R=\rho \frac{l}{A}\)

⇒ \(\frac{R_1}{R_2}=\frac{l_1}{l_2} \cdot \frac{A_2}{A_1}=\frac{l_1}{l_2} \cdot \frac{V / l_2}{V / l_1}=\left(\frac{l_1}{l_2}\right)^2=\left(\frac{1}{2}\right)^2=\frac{1}{4}\)

or, \(\frac{R_2}{R_1}=\frac{4}{1}=4: 1\)

The option 3 is correct

Question 24. Two equal resistances, 400Ω each, are connected in series with an 8 V battery. If the resistance of the first one increases by 0.5%, the charge required in the resistance of the second one in order to keep the potential difference across it unaltered is to

  1. Increase it by 1Ω
  2. Increase it by 2Ω
  3. Increase it by 4Ω
  4. Decrease it by 4Ω

Answer: 2. Increase it by 2Ω

Increase in first resistance =400 x \(\frac{0.5}{100}\) = 2Ω

Initially, the emf 8 V will be divided equally between the two resistances. So the voltage across each resistance will be 4 V. When the first resistance is increased, the second resistance should also be increased by 2Ω to keep the voltage across it unchanged.

The option 2 is correct.

Class 12 Physics Ohm’s Law MCQs  Question 25. Two wires of the same radius having lengths l1 and l2 and resistivities p1 and p2 are connected in series. The equivalent resistivity will be

  1. \(\frac{\rho_1 l_2+\rho_2 l_1}{\rho_1+\rho_2}\)
  2. \(\frac{\rho_1 l_1+\rho_2 l_2}{l_1+l_2}\)
  3. \(\frac{\rho_1 l_1-\rho_2 l_2}{l_1-l_2}\)
  4. \(\frac{\rho_1 l_2+\rho_2 l_1}{l_1+l_2}\)

Answer: 2. \(\frac{\rho_1 l_1+\rho_2 l_2}{l_1+l_2}\)

⇒ \(\frac{\rho_1 l_1}{A}+\frac{\rho_2 l_2}{A}=\rho_{\mathrm{eq}} \frac{\left(l_1+l_2\right)}{A}\)

∴ \(\rho_{\mathrm{eq}}=\frac{\rho_1 l_1+\rho_2 l_2}{l_1+l_2}\)

The option 2 is correct.

Question 26. The effective resistance between A and B is \(\frac{7}{12}\)Ω if each side of the cube has 1Ω resistance. The effective resistance between the same two points when the link AB is removed is

Class 12 Physics Current Electricity Electric Current and Ohm's Law The Effective Resistance Between A And B

  1. \(\frac{7}{12}\)Ω
  2. \(\frac{5}{12}\)Ω
  3. \(\frac{7}{5}\)Ω
  4. \(\frac{5}{7}\)Ω

Answer: 3. \(\frac{7}{5}\)Ω

If x is the effective resistance between A and B of the remaining cube, then

⇒ \(\frac{7}{12}=\frac{1 \times x}{1+x}\)

Solving we get, x = \(\frac{7}{5}\)Ω

The option 3 is correct

Ohm’S Law Multiple Choice Questions

Question 27. Four resistors 100Ω, 200Ω, 300Ω, and 400Ω are connected to form four sides of a square. The resistors can be connected in any; order. What is the maximum possible equivalent resistance across the diagonal of the square?

  1. 210Ω
  2. 240Ω
  3. 300Ω
  4. 250Ω

Answer: 4. 250Ω

The resistance across the diagonal of the square formed by the four resistors is equal to the equivalent resistance of the resistors in parallel combination.

Class 12 Physics Current Electricity Electric Current and Ohm's Law Resistance In Parallel Combination In Resistance

The equivalent resistance of the parallel combination is maximum when the resistance on the two sides of the diagonal is equal.

∴ Equivalent resistance,

⇒ \(R=\frac{500 \times 500}{500+500}=250 \Omega\)

The option 4 is correct.

Class 12 Physics Ohm’s Law MCQs  Question 28. What will be the current through the 200Ω resistor in the given circuit a long time after the switch K is made on?

Class 12 Physics Current Electricity Electric Current and Ohm's Law Circuit A Long After Time Circuit

  1. 0
  2. 100mA
  3. 10mA
  4. 1mA

Answer: 3. 10mA

A long time after the switch K is turned on, the 1μF and 2μF capacitors will be open-circuited and no current will flow through them.

Class 12 Physics Current Electricity Electric Current and Ohm's Law Capacitor Will Be Open Circuit

∴ Current through, the 200Ω resistor

⇒ \(\frac{6}{200+400}=\frac{1}{100} \mathrm{~A}\)

= 10mA

The option 3 is correct.

Question 29. When the 5 V potential difference is applied across a wire of length 0.1 m, the drift speed of electrons is 2.5 x 10-4 m s-1. If the electron density in the wire is 8 x 1028 m-3, the resistivity of the material is close to

  1. 1.6 x 10-8Ω.m
  2. 1.6 x 10-7Ω.m
  3. 1.6 x 10-6Ω.m
  4. 1.6 x 10-5Ω.m

Answer: 4. 1.6 x 10-5Ω.m

Drift velocity, \(v=\frac{I}{n e A}\)

⇒ \(I=\frac{V}{R}=\frac{V}{\rho \frac{l}{A}} \quad \text { or, } \rho=\frac{V}{\frac{I}{A} l}=\frac{V}{n e v l}\)

∴ \(\rho=\frac{5}{\left(8 \times 10^{28}\right) \times\left(1.6 \times 10^{-19}\right) \times\left(2.5 \times 10^{-4}\right) \times 0.1}\)

= 1.56 X 10-5Ω.m

= 1.6 X 10-5Ω m

The option 4 is correct.

Ohm’S Law Multiple Choice Questions

Question 30. The temperature dependence of resistances of Cu and undoped Si in the temperature range of 300-400 K, is best described by

  1. Linear increase for Cu, linear increase for Si
  2. Linear increase for Cu, exponential increase for Si
  3. Linear increase for Cu, exponential decrease for Si
  4. Linear decrease for Cu, linear decrease for Si

Answer: 3. Linear increase for Cu, exponential increase for Si

Question In the given circuit the current in each resistance is

Class 12 Physics Current Electricity Electric Current and Ohm's Law Current In A Each Resistor

  1. 1A
  2. 0.25A
  3. 0.5A
  4. zero

Answer: 4. zero

There are two cells of equal electromotive force in opposite directions with each other in each loop. So, the electromotive force in each loop is zero. Hence, the current is also zero.

Option 4 is correct

Class 12 Physics Ohm’s Law MCQs  Question 31. In the given circuit diagram when the current reaches a steady state in the circuit, the charge on the capacitor of capacitance C will be

  1. CE
  2. \(\frac{C E r_1}{r_2+r}\)
  3. \(\frac{C E r_2}{r+r_2}\)
  4. \(\frac{C E r_1}{r_1+r}\)

Answer: 3. \(\frac{C E r_2}{r+r_2}\)

The current reaches a steady state in the circuit means that the current through the capacitor is zero

Class 12 Physics Unit 2 Current Electricity Chapter 1 Electric Current and Ohm's Law Current Through The Capacitor Is Zero

∴ Current in the circuit, \(i=\frac{E}{r+r_2}\)

Potential differences across the capacitor,

⇒ \(V_{A D}=V_{A B}=i r_2=\frac{E r_2}{r+r_2}\)

Therefore, the charge storedin the capacitor C,

⇒ \(Q=C V_{A D}=C E \frac{r_2}{r+r_2}\)

The option 3 is correct

Question 32. A, B, and C are voltmeters of resistance R, 1.5R, and 3R respectively. When some potential difference is applied between X and Y, the voltmeter readings are VA, VB,  and VC respectively. Then

Class 12 Physics Current Electricity Electric Current and Ohm's Law The Voltmeter Of Resistance

  1. VA=VB=VC
  2. VA ≠ VB = VC
  3. VA = VB ≠ VC
  4. VA ≠ VB ≠ VC

Answer: 1. VA=VB=VC

Clearly, VB = VC

Again, equivalent resistance for B and C = \(\frac{1.5 \times 3}{1.5+3}=1 \Omega\)

= resistance of A.

Hence, VA = VB = VC

The option 1 is correct.

Electric Resistance Mcq Class 12 Physics

Question 33. Across a metallic conductor of a non-uniform cross-section, a constant potential difference is applied. The quantity which remains constant along the conductor is

  1. Current density
  2. Current
  3. Drift velocity
  4. Electric field

Current remains constant along the conductor.

The option 2 is correct.

Class 12 Physics Ohm’s Law MCQs  Question 34. In the electrical circuit, the current I through the side AB is

Class 12 Physics Current Electricity Electric Current and Ohm's Law The Electrical Circuit

  1. \(\frac{6}{2}\)A
  2. \(\frac{10}{33}\)A
  3. \(\frac{1}{5}\)A
  4. \(\frac{10}{63}\)A

Answer: 1. \(\frac{6}{2}\)A

E=IR

or, \(10=I\left(10+\frac{20 \times 30}{20+30}+3\right)=0.25 I\)

Here, \(I=\frac{10}{25}=\frac{2}{5} \mathrm{~A}\)

∴ \(I_{A B}=\frac{2}{5} \times \frac{30}{20+30}=\frac{6}{25} \mathrm{~A}\)

The option 1 is correct

Question 35. A cell of emf E and internal resistance r is connected to a variable external resistor R. The graph which gives the terminal voltage of cell V with respect to R is

Class 12 Physics Current Electricity Electric Current and Ohm's Law Terminal Voltage Of Cell

Answer: 2.

Class 12 Physics Current Electricity Electric Current and Ohm's Law Terminal Voltage Of Cell

⇒ \(V=E-I r=E-\frac{E r}{R+r}\)

or, \(\frac{d V}{d R}=\frac{E r}{(R+r)^2}\)

Therefore, the slope of the V-R graph is positive and it decreases within resistance R

The option 2 is correct.

Electric Resistance Mcq Class 12 Physics

Question 36. A carbon resistor of (47 ± 4.7)kΩ is to be marked with rings of different colors for its identification. The color code sequence will be

  1. Yellow—Green—Violet—Gold
  2. Yellow—Violet—Orange—Silver
  3. Violet—Yellow—Orange—Silver
  4. Green—Orange—Violet—Gold

Answer: 2. Yellow—Violet—Orange—Silver

⇒ \((47 \pm 4.7)=47 \pm\left(\frac{4.7}{47} \times 100\right) \%=47 \pm 10 \%\)

∴ \((47 \pm 4.7) \mathrm{k} \Omega=47 \times 10^3 \pm 10 \% \Omega\)

Therefore, the color code sequence will be yellow—Violet—Orange—Silver

The option 2 is correct

Class 12 Physics Ohm’s Law MCQs  Question 37. A set of n equal resistors, of value R each, are connected in series to a battery of emf E and internal resistance R. The current drawn is I. Now, the n resistors are connected in parallel to the same battery. Then the current drawn from the battery becomes 10I. The value of n is

  1. 20
  2. 11
  3. 10
  4. 9

Answer: 3. 10

Equivalent resistance in series,

R1 = nR + R = (n + 1)R

∴ \(I=\frac{E}{R_1}=\frac{E}{(n+1) R}\)…..(1)

Equivalent resistance in parallel

⇒ \(R_2=\left(\frac{R}{n}+R\right)=\left(1+\frac{1}{n}\right) R\)

∴ \(10 I=\frac{E}{R_2}=\frac{E}{\left(1+\frac{1}{n}\right) R}\)…..(2)

From equations (1) and (2)

⇒ \(\frac{10 I}{I}=\frac{(n+1) R}{\left(1+\frac{1}{n}\right) R} \text { or, } 10\left(\frac{n+1}{n}\right)=(n+1)\)

or, n = 10

The option 3 is correct.

Question 38. A battery consists of a variable number n of identical cells (having internal resistance r each) which are connected in series. The terminals of the battery are short-circuited and the current I is measured. Which of the graphs shows the correct relationship between I and n?

Class 12 Physics Current Electricity Electric Current and Ohm's Law Identical Cell

Answer: 3.

Class 12 Physics Current Electricity Electric Current and Ohm's Law Identical Cell.

Current in the circuit containing n identical cells connected in series,

I = \(\frac{ne}{nr}\) [ e = emf of each identical cell]

or, I = \(\frac{e}{r}\)

So, I remain the same with any change of n.

The option is correct.

MPBSE Class 12 Physics Atomic Nucleus Question And Answers

Mpbse Class 12 Physics Atomic Nucleus Solutions

Question 1. The Q -the value of a nuclear reaction A + b → C + d is defined by Q = [mA + mb-mC-md]c², where the masses refer to nuclear rest masses. Determine from the given data whether the following reactions are exothermic or endothermic

1. \({ }_1^1 \mathrm{H}+{ }_1^3 \mathrm{H} \rightarrow{ }_1^2 \mathrm{H}+{ }_1^2 \mathrm{H}\)

2. \({ }_6^{12} \mathrm{C}+{ }_6^{12} \mathrm{C} \rightarrow{ }_{10}^{20} \mathrm{Ne}+{ }_2^4 \mathrm{He}\)

Atomic masses are given to be

\(m\left({ }_1^1 \mathrm{H}\right)=1.007825 \mathrm{u}, m\left({ }_1^2 \mathrm{H}\right)=2.014102 \mathrm{u}\)

\(m\left({ }_1^3 \mathrm{H}\right)=3.016049 \mathrm{u}, m\left({ }_1^{12} \mathrm{C}\right)=12.000000 \mathrm{u}\)

\(m\left({ }_{10}^{20} \mathrm{Ne}\right)=19.992439 \mathrm{u}, \quad m\left({ }_2^4 \mathrm{He}\right)=4.002603 \mathrm{u}\)

Answer:

1. \({ }_1^1 \mathrm{H}+{ }_1^3 \mathrm{H} \rightarrow{ }_1^2 \mathrm{H}+{ }_1^2 \mathrm{H}\)

Q= \(m_{\mathrm{N}}\left({}_1^1\mathrm{H}\right)+m_{\mathrm{N}}\left({ }_1^3 \mathrm{H}\right)m_{\mathrm{N}}\left({ }_1^2 \mathrm{H}\right)-m_{\mathrm{N}}\left({ }_1^2 \mathrm{H}\right)\)

= \(m\left({ }_1^1 \mathrm{H}\right)-m_e+m\left({ }_1^3 \mathrm{H}\right)-m_e-m\left({ }_1^2 \mathrm{H}\right)\) + \(m_em\left({}_1^2\mathrm{H}\right)+m_e\)

= \(m\left({ }_1^1 \mathrm{H}\right)+m\left({ }_1^3 \mathrm{H}\right)-m\left({ }_1^2 \mathrm{H}\right)-m\left({ }_1^2 \mathrm{H}\right)\)

1.007825 + 3.016049-2 × 2.014102

= -0.00433 ×  931.5 MeV = -4.03 MeV

∴ Q < 0, the reaction is endothermic

2. \({ }_6^{12} \mathrm{C}+{ }_6^{12} \mathrm{C} \rightarrow{ }_{10}^{20} \mathrm{Ne}+{ }_2^4 \mathrm{He}\)

Q = \(2 m_{\mathrm{N}}\left({ }_6^{12} \mathrm{C}\right)-m_{\mathrm{N}}\left({ }_{10}^{20} \mathrm{Ne}\right)-m_{\mathrm{N}}\left({ }_2^4 \mathrm{He}\right)\)

= \(=2 m\left({ }_6^{12} \mathrm{C}\right)-12 m_e-m\left({ }_{10}^{20} \mathrm{Ne}\right)+10 m_e\) \(-m\left({ }_2^4 \mathrm{He}\right)+2 m_e\)

= [2 × 12.000000-19.992439-4.002603] × 931.5 MeV

= 0.004958 × 931.5 MeV = 4.62 MeV

Q > 0; so, the reaction is exothermic.

Mpbse Class 12 Physics Atomic Nucleus Solutions

Question 2. Is the fission of  56Fe26 nucleus into two equal fragments,  28Al13 energetically possible? Argue by working out the Q of the process. Given, m ( 56Fe26 ) = 55.93494 u and m(28Al13) = 27.98191 u
Answer:

If possible, let the reaction be \({ }_{26}^{56} \mathrm{Fe} \rightarrow{ }_{13}^{28} \mathrm{Al}+{ }_{13}^{28} \mathrm{Al}\)

Q -value of the process = \(m\left({ }_{26}^{56} \mathrm{Fe}\right)-2 m\left({ }_{13}^{28} \mathrm{Al}\right)\)

55.934944-2 × 27.98191

= -0.02888 × 931.5 MeV

= -26.90 MeV

Since the Q -value is negative, fission is not possible

Question 3. The fission properties of 239Pu94 are very similar to those of 235U92 The average energy released per fission is 180 MeV. How much energy, in MeV, is released if all the atoms in 239Pu941 kg of pure undergo fission?
Answer:

Number of nuclei in 1 kg of 239Pu94

= \(\frac{6.023 \times 10^{23}}{239} \times 1000.0\)

= 2.52 × 10 24

The energy released per fission = 180 MeV

Total energy released = 2.52 x 1024 × 180 MeV

= 4.54 × 1026 MeV

Atomic Nucleus Class 12 Questions And Answers

Question 4. A 1000 MW fission reactor consumes half of its fuel in 5y. How much 235U92 did it contain initially? Assume that the reactor was active 80% of the time and all the energy generated arises from the fission of 235U92 and that this nuclide is consumed by the fission process.
Answer:

Energy generated per gram of 235U92

= \(\frac{6.023 \times 10^{23}}{235} \times 200 \times 1.6 \times 10^{-13} \mathrm{~J} \cdot \mathrm{g}^{-1}\)

Energy generated in 5 y

Power × Time × 80%

(1000 × 106) × (5 × 365 × 24 × 60 × 60) × 80% J

Amount of spent

= \(\frac{\left(1000 \times 10^6\right) \times(5 \times 365 \times 24 \times 60 \times 60)}{6.023 \times 10^{23} \times 200 \times 1.6 \times 10^{-13}} \mathrm{x} \times 235\)

= 1538 kg

Initial mass of 235U92  = 2 × 1538 kg = 3076 kg

Question 5. How long an electric lamp of 100 W can be kept glowing by fusion of 2.0 kg of deuterium? The fusion reaction can be taken as = \({ }_1^2 \mathrm{H}+{ }_1^2\mathrm{H}\rightarrow{}_2^3\mathrm{He}+\mathrm{n}+3.2 \mathrm{MeV}\)
Answer:

Number of nuclei in 2 kg of 2H1

= \(\frac{6.023 \times 10^{23} \times 2000}{2}=6.023 \times 10^{26}\)

Energy generated by the fusion of these nuclei

E = \(\frac{3.2 \times 6.023 \times 10^{26}}{2} \mathrm{MeV}\)

Power of the bulb = 100 W

Let the bulb = 100 W

Energy spent = \(\frac{100 \times t}{1.6 \times 10^{-13}} \mathrm{MeV}\)

∴ \(\frac{100 t}{1.6 \times 10^{-13}}=\frac{3.2 \times 6.023}{2} \times 10^{23}\)

t = \(\frac{3.2 \times 6.023 \times 10^{23} \times 1.6 \times 10^{-13}}{2 \times 100}\)

– 1.54 × 10 12 s

= 4.89 × 104 y

Nuclear Physics Class 12 Important Questions

Question 6. A source contains two phosphorus radionuclides  32P15 (T1/2 = 14.3 d) and 33P15 (T1/2 = 25.3 d). Initially, 10% of the decay comes from 33P15. How long one must wait until 90% do so. 33 32
Answer:

Let i R01 and R02 be the initial activities of 33P15 and 32P15 respectively and R1 and R2 be their activities at any instant t. According to the first observation

R01 = 10% (R01 +R02)

R02 =  9 R01 ……………………………. (1)

Again, R1 = 90% (R1 + R2)

Or, \(\frac{R_2}{R_{02}}=\frac{1}{81} \frac{R_1}{R_{01}}\) ……………………………. (1)

Combining equation (1) and (2)

⇒ \(\frac{R_2}{R_{02}}=\frac{1}{81} \frac{R_1}{R_{01}}\)

Or, \(\frac{R_{02} e^{-\lambda_2 t}}{R_{02}}=\frac{1}{81} \times \frac{R_{01} e^{-\lambda_1 t}}{R_{01}}\)

Or, \(81 e^{-\lambda_2 t}=e^{-\lambda_1 t}\)

⇒ \(\left(\lambda_2-\lambda_1\right) t=\dot{2} .303 \log 81\)

t = \(\frac{2.303 \log 81}{\frac{0.693}{14.3}-\frac{0.693}{25.3}}\)

Since Or, λ = 0.693T½

= 208 . 5 d

Question 7. Under certain circumstances, a nucleus can decay by = 231.1 MeV emitting a particle more massive than an a -particle. Consider the following decay processes

1. \({ }_{88}^{223} \mathrm{Ra} \rightarrow{ }_{82}^{209} \mathrm{~Pb}+{ }_6^{14} \mathrm{C}\)

2. \({ }_{88}^{223} \mathrm{Ra} \rightarrow{ }_{86}^{219} \mathrm{Rn}+{ }_2^4 \mathrm{He}\)

Calculate the Q -values for these two decays and determine that both are energetically possible. 

m( 223Ra88 ) = 223.01850 u, m( 209Ra82 ) = 208.98107 u,

m(219Ra86 ) = 219.00948 u, m(14C6) = 14.00324 u and m(4He2) = 4.00260 u

Answer:

1. \({ }_{88}^{223} \mathrm{Ra} \rightarrow{ }_{82}^{209} \mathrm{~Pb}+{ }_6^{14} \mathrm{C}+Q\)

= \(\left[m_{\mathrm{N}}\left({ }_{88}^{223} \mathrm{Ra}\right)-m_{\mathrm{N}}\left({ }_{82}^{209} \mathrm{~Pb}\right)-m_{\mathrm{N}}\left({ }_6^{14} \mathrm{C}\right)\right]\) x 931.2 MeV

= \(\left[m_{88}^{223} \mathrm{Ra}-m\left({ }_{82}^{209} \mathrm{~Pb}\right)-m\left({ }_6^{14} \mathrm{C}\right)\right] \times 931.2 \mathrm{MeV}\)

31. 8 MeV

∴ Q > 0: so, the decay is possible

2. \({ }_{88}^{223} \mathrm{Ra} \rightarrow{ }_{86}^{219} \mathrm{Rn}+{ }_2^4 \mathrm{He}+Q^{\prime}\)

Q’ = 5.98 MeV [by similar calculation as above]

∴ Q’ > 0; so, this decay is also possible.

Nuclear Physics Class 12 Important Questions

Question 8. Consider the fission of 238U92 by fast neutrons. In one fission event, no neutrons are emitted and the final stable end products, after the beta decay of the primary fragments, are140Ce58 and 99Ru44 Calculate Q for this fission process
Given

\(m\left({ }_{92}^{238} \mathrm{U}\right)=238.05079 \mathrm{u}, m\left({ }_{58}^{140} \mathrm{Ce}\right)=139.90543 \mathrm{u}\)

\(m\left({ }_{44}^{99} \dot{\mathrm{Ru}}\right)=98.90594 \mathrm{u}, \dot{m}_n=1.008667 \mathrm{u}\)

Answer:

The fission reaction is

⇒ \({ }_{92}^{238} \mathrm{U}+{ }_0^1 \mathrm{n}{\beta}{ }_{58}^{140} \mathrm{Ce}+{ }_{44}^{99}\mathrm{Ru}+Q\)

∴ Q = \(\left[m\left({}_{92}^{238}\mathrm{U}\right)+m\left({ }_0^1\mathrm{n}\right)m\left({}_{58}^{140}\mathrm{Ce}\right)-m\left({ }_{44}^{99} \mathrm{Ru}\right)\right] \mathrm{u}\)

= \([238.05079+1.00867-139.90543-98.90594]\)

= 23 1.1 MeV

Question 9. Suppose India had a target of producing by 2020 AD, 200, 000 MW of electric power, 10% of which was to be obtained from nuclear power plants. Suppose we are given that, on average, the efficiency of utilization (i.e., conversion to electric energy) of thermal energy produced in a reactor was 25%. How much amount of fissionable uranium did our country need per year by 2020? Take the heat per fission of 235U92 to be about 200 MeV. Avogadro’s number = 6.023 × 10 mol-1. Nuclear power target = 10% of total generation
Answer:

Nuclear power target = 10% of total generation

= 10% × 2 × 1011 W

= 2 × 1010 W

Efficiency, η = 25%

∴ Total power generated by the nuclear reactor

= \(\frac{2 \times 10^{10}}{25 \%} \mathrm{~W}=8 \times 10^{10} \mathrm{~W}\)

∴ Generated heat by the reactor in 2020

H = 8 × 1010 × 366 × 24 × 60 ×60 J

∴ Number of fission required for generation of this heat,

N = \(\frac{H}{200 \times 1.6 \times 10^{-13}}\)

If m g of  235U92 contains this number of nuclei, then,

m = \(\frac{N \times 235}{6.023 \times 10^{23}} \mathrm{~g}\)

= \(\frac{8 \times 10^{10} \times 366 \times 24 \times 60 \times 60 \times 235}{200 \times 1.6 \times 10^{-13} \times 6.023 \times 10^{23}} \mathrm{~g}\)

= 3.084 × 104  kg

Structure Of Atomic Nucleus Class 12 Questions

Question 10. Calculate and compare the energy released by

  1. Fusion of: 1.0 kg of hydrogen deep within the sun and
  2. The fission oqc of 1.0 kg of 235U in a fission reactor.

Answer: 

1. Equation of fusion reaction,

4 1H → 4He2 + 2 0e+1 + 26 MeV

∴ 26 MeV of energy is released on a combination of four H nuclei.

Number of nuclei in 1 kg of hydrogen

= 6.023 × 1023 × 1000

Energy released,

EH = 6.023  × 1026 ×  26 MeV

2. Fission of one  nucleus releases 200 MeV of energy

Number of nuclei in 1 kg of 235U92 = \(\frac{6.023 \times 10^{23} \times 1000}{235}\)

∴ Energy released,

EU = \(\frac{6.023 \times 10^{23} \times 1000 \times 20}{235}\)

= 5.12 × 1026 MeV

∴ \(\frac{E_{\mathrm{H}}}{E_{\mathrm{U}}}=\frac{3.913 \times 10^{27}}{5.12 \times 10^{26}}\)

= 7.6

Question 11. The half-life of a radioactive substance is 30 days. The number of atoms in the substance is 1012. How many disintegrations of atoms per second does occur?
Answer:

T = 30 d =30 × 24 × 60 × 60 s

⇒ \(\lambda=\frac{0.693}{T}\)

= \(=\frac{0.693}{30 \times 24 \times 60 \times 60}\)

= 2.67 × 10-7(approx)

If t = 1 s, t = 2.67 × 10-7

Hence, eλt  = 1.000000267(approx)

N = N0eλt  = \(\)

= 9.99999733 × 1011 (approx)

∴ Number of atoms disintegrated per second

= N0 – N = 2.67 ×  10 5 (approx)

Question 12. Draw a plot of the potential energy of a pair of nucleons as a function of their separations. Mark the region where the nuclear force is (1) attractive and (il) repulsive. Write any two characteristic features of nuclear forces
Answer:

The required plot

Atomic Nucleus Required Plot

In region AB, nuclear force is attractive.

The nuclear force is not repulsive. The repulsive force corresponding to the region DF is the repulsive coulomb force between protons

Structure Of Atomic Nucleus Class 12 Questions

Question 13.

  1. Draw the Plot of binding energy per nucleon (B.E./A ) as a function of mass number A . Write two important conclusions that can be drawn regarding the nature of
    nuclear force
  2. Use this graph to explain the release of energy in both the processes of nuclear fusion and fission.
  3. Write the basic nuclear process of neutrons undergoing β-decay. Why is the detection of neutrinos found very difficult?

Answer:

1.

Atomic Nucleus Binding Energy Per Nucleon

  1. Two conclusions from the plot: the nuclear force is
  2. Short-range and
  3. Charge independent

2. Mass of a nucleus (M) = mass of its nucleons- binding energy (B)

So, M decreases with an increase in B.

Now, we consider nuclear fission: 1 → 2 + 3.

From mass-energy equivalence,

M1 = M2 + M3+ energy release (Q)

or, Q = M1 – M2 – M3

Q is positive, i.e., energy is released if

M1 > M2 – M3,i.e., B1 < B2 – BM3

or A1e1<A2e2 + A3e3

Where A1A2, A3 are mass numbers A1 = A2 + A3) and e1 , e2 , e3 are binding energy per nucleon. From the plot, we see that this condition is satisfied for high A1, where both e2 and e3 are higher than e1 of the large nucleus 1.

The fission of a large nucleus releases energy. On the other hand, for low A nuclei, e2, and e3 will be less than the e1 of the larger nucleus 1. So, energy will be released rather in the opposite process: 2 + 3 → 1. Therefore, a fusion of small nuclei releases energy

3. It is very difficult to detect neutrinos or antineutrinos experimentally because they have neither any charge nor any mass.

Question 14. Define the activity of a radioactive sample. Write its SI unit. A radioactive sample has the activity of 10000 disintegrations per second (DPS) after 20 hours. After the next 10 hours its activity reduces to 5000 dps. Find out its half-life and initial

The activity of a radioactive sample is defined as the rate of disintegration of the sample. It is also called the count rate. Its SI unit is becquerel (Bq).

1 Bq = 1 decays/s

We know A = A8 e-λt

5000 = 10000e-λt

Or, eλt = \(\frac{10000}{5000}\)

= 2

Taking logs on both sides we get

λt = log 2

Or, λ = \(\frac{\log 2}{t}\)

Now half-life T = \(=\frac{0.693}{\lambda}=\frac{0.693 \times t}{\log 2}=\frac{0.693 \times 600}{\log 2}\)

= 1381. 26 min 23 h

Atomic Nucleus Radioactivity Samples

In this table, the last two values are the given values. Prom these values, the first two values have been calculated,

Atomic Nucleus Class 12 Questions And Answers

Question 15.

1. A radioactive nucleus ‘A ‘ undergoes a series of decays as given below:

Atomic Nucleus Radioactive Nucleus

The mass number and atomic number of A2 are 176 and 71 respectively. Determine the mass and atomic numbers of A4 and A.

2. Write the basic nuclear processes underlying α and β decays

Answer:

1. When βdecay occurs

Atomic Nucleus Nuclear Process Beta Negative

When β decay occurs

Atomic Nucleus Nuclear Process Beta Positive

In the case of β–   decay, the mass number of A is 180 and its atomic number is 72. In the case of β+ decay, the mass number of A is 100 and its atomic number is 74. In both cases, the mass number of A4   Is 172 and its atomic number is 69.

Atomic Nucleus Beta Decay Occurs

Question 16. Explain the processes of nuclear fission and nuclear fusion by using the plot of binding energy per nucleon (BE/A) versus the mass number A

Nuclear fission:

The binding energy per nucleon for heavier nuclei is approximately 7.6 MeV, but for lighter nuclei, it is roughly 8.4 MeV. The heavier nuclei exhibit reduced stability, leading to the fission of the heavier nucleus into lighter nuclei, which therefore releases energy. This process is referred to as nuclear fission.

Nuclear fusion:

The binding energy per nucleon for nuclei with mass number A < 12 is minimal, rendering them less stable. Consequently, two such nuclei can amalgamate to create a somewhat heavier nucleus, which possesses a greater binding energy per nucleon.

Consequently, energy is liberated in this process, referred to as nuclear fusion.

Atomic Nucleus Class 12 Questions And Answers

Question 17. A radioactive isotope has a half-life of 10 years. How long will it take for the activity to reduce to 3.125%?
Answer:

Activity A = λN

Given A = 3. 125 % of \(\frac{3.125 A_0}{100}=\frac{A_0}{32}\)

Or, \(\frac{A}{A_0}=\left(\frac{1}{2}\right)^5\)

∴ \(\frac{N}{N_0}=\left(\frac{1}{2}\right)^5\)

So the activity will reduce to 3.125% after 5 half-lives. Hence required time =5 × 10 = 50 years

MCQs on biopesticides – NEET Biology

NEET Biology Biopesticides Multiple Choice Questions And Answers

Question 1. Pulse pest is:

  1. Rntehtts
  2. Slug and snails
  3. Schocnobices
  4. Leptocorisa.

Answer: 1. Rntehtts

Question 2. The disease apple scab is due to:

  1. Zinc deficiency in the soil
  2. Molybdenum deficiency in the soil
  3. Respiratory gaseous products in cold storage
  4. Xanthomonas malvacerrum .

Answer: 3. Respiratory gaseous products in cold storage

Question 3. Nephantis screencap is responsible for damage of:

  1. Rice
  2. Wheat
  3. Coconut
  4. Cotton.

Answer: 3. Coconut

Question 4. Late blight of potatoes is caused by:

  1. Pythium species
  2. Calviceps purpura
  3. Phytophthora infestans
  4. Uncinula ancestor.

Answer: 1. Pythium species

Read and Learn More NEET Biology Multiple Choice Question and Answers

Question 5. Which of the following herbicides is derived from urea?

  1. Simazine
  2. DDT
  3. Malathion
  4. Aldrin.

Answer: 1. Simazine

NEET Biology Biopesticides On MCQs

Question 6. Stem borer of rice is caused by:

  1. Tnporyza inertias
  2. Leptocorisa varicomis
  3. Pectinophora gossypiella
  4. None of the above.

Answer: 1. Tnporyza incertulas

Biopesticides Mcq For Neet

Question 7. Which of the following pests feeds directly on the rice grains?

  1. Red pumpkin beetle
  2. Rice weevil
  3. Carpet beetle
  4. None of the above.

Answer: 2. Rice weevil

Question 8. The science which deals with the study of the nature, development and control of plant diseases is called as:

  1. Plant pathology
  2. Phytopathology
  3. Pathology
  4. Both (1) and (2).

Answer: 4. Both (1) and (2).

Question 9. A plant is said to be diseased when:

  1. It shows some physiological disorder
  2. There developed some structural abnormality
  3. Its economic value is reduced
  4. All the above.

Answer: 4. All the above.

Question 10. In modern science, a disease is an interaction:

  1. Between the host and parasite
  2. Between the plant and environment
  3. Among the host, parasite and environment
  4. All of the above

Answer: 3. Among the host, parasite and environment

Question 11. Puccinia graminis tritici causes:

  1. Covered smut of wheat
  2. Black rust of wheat
  3. Loose smut of wheat
  4. White rust.

Answer: 2. Black rust of wheat

Biopesticides Mcq For Neet

Question 12. The problem of wheat rust in India was studied by:

  1. J.F. Dastur
  2. E.J. Butler
  3. K.C. Mehta
  4. G.S. Kulkami.

Answer: 3. K.C. Mehta

Question 13. The small insects that suck the milky sap in the tender grains of rice after destroying the crop completely are:

  1. Gundhy or paddy bugs of rice, leukocoria
  2. Larvae of rice grasshopper, hieroglyphs
  3. Rice weevil, Calandra sp.
  4. Lesser grain beetles, Rhizopertha sp.

Answer: 1. Gundhy or paddy bugs of rice, leukocoria

Question 14. An organism which causes a disease in a plant is called as:

  1. Parasite
  2. Pathogen
  3. Vector
  4. Host.

Answer: 2. Pathogen

Question 15. Bacteria and fungi are the pathogens belonging to:

  1. Biotic type
  2. Abiotic type
  3. Viral type
  4. Both biotic and abiotic types.

Answer: 1. Biotic type

Question 16. When a disease spreads to the whole of the plant, it is termed as:

  1. Localised
  2. Systemic
  3. Sporadic
  4. Endemic.

Answer: 2. Systemic

Neet Biology Mcqs On Biopesticides

Question 17. The brown leaf spot disease of rice is caused by a fungus called:

  1. Phytophthora infestans
  2. Helminthosporium oryzae
  3. Venturia inadequate
  4. Xanthomonas oryzae.

Answer: 3. Venturia inadequate

Question 18. Insect pests can be controlled by:

  1. Using bastide
  2. Using antibiotics
  3. Spraying sulphur dust
  4. Spraying insecticides.

Answer: 4. Spraying insecticides.

Question 19. Paddy bug is a serious pest of:

  1. Wheat
  2. Paddy
  3. Groundnut
  4. Sugarcane.

Answer: 4. Sugarcane.

Question 20. An abnormal increase in the size of the plant organ due to the increase in the number of cells is called:

  1. Hyperplasia
  2. Hypertrophy
  3. Overgrowth
  4. Canker.

Answer: 1. Hyperplasia

Question 21. Blight refers to the:

  1. Development Of Large And Irregular Spots On The Leaves
  2. Burnt Appearance In The Infected Part Of The Plant
  3. Decaying And Discolouring Of The Different Parts Of The Plant
  4. Death Of The Cells In The Form Of Elongated Lines Or Streaks.

Answer: 2. Burnt Appearance In The Infected Part Of The Plant

Question 22. Khapra beetle (Trogoderma granarium) is a pest of:

  1. Stem Of Rice
  2. Leaves Of Paddy
  3. Stored Grains
  4. Both (1) and (2).

Answer: 3. Stored Grains

Question 23. Wilting in a plant is caused by:

  1. An injury to the root system
  2. Loss of water from the soil
  3. Plugging of xylem by fungi and bacteria
  4. All the above.

Answer: 4. All the above.

Previous Year Neet Questions On Biopesticides

Question 24. In ergot disease, fungal mycelium (Claviceps purpurea) aggregates to form a hard bunch called the:

  1. Blotch
  2. Knot
  3. Spot
  4. Sclerotium.

Answer: 1. Blotch

Mcqs On Biopesticides Question 25. Insecticides are specific inhibitors of:

  1. Nervous system
  2. Blood vascular system
  3. Digestive system
  4. Excretory system.

Answer: 1. Nervous system

Question 26. When a disease in moderate or severe form is localised to a particular region, it is called as

  1. Epidemic
  2. Endemic
  3. Sporadic
  4. Pandemic.

Answer: 2. Endemic

Question 27. The disease in which the floral parts get transformed into leafy structures is called as:

  1. Dieback
  2. Phylloidy
  3. Atrophy
  4. Hypertrophy

Answer: 2. Phylloidy

Question 28. Rust diseases are:

  1. Air bone
  2. Soil bone
  3. Seed borne
  4. All the above

Answer: 1. Air bone

Question 29. Tobacco mosaic virus particles are:

  1. Rod-shaped
  2. Rounded
  3. Comma-shaped
  4. Amoeboid.

Answer: 1. Rod-shaped

Previous Year Neet Questions On Biopesticides

Question 30. Xantliomonas oryzae causes:

  1. Bacterial blight of rice
  2. Citrus canker
  3. Potato mosaic
  4. White rust of crucifers.

Answer: 1. Bacterial blight of rice

Question 31. Bacterial blight of rice is a disease which is

  1. Seed Borne
  2. Air Borne
  3. Soil Borne
  4. Water Borne.

Answer: 1. Seed Borne

Question 32. Malathion is present in:

  1. Baygon
  2. Finit/Flit
  3. Temik
  4. Furadin.

Answer: 2. Finit/Flit

Question 33. Potato mosaic disease is caused by:

  1. Bacteria
  2. Synchytrium sp.
  3. Potato virus X and Y
  4. Both (2) and (3).

Answer: 3. Potato virus X and Y

Question 34. Black stem rust of wheat is caused by:

  1. Ustilago tritici
  2. Puccinia graminis tritici
  3. Altemaria solani
  4. None of these.

Answer: 2. Puccinia graminis tritici

Question 35. A diseased plant shows water-soaked translucent spots on the margin and mid-rib of the leaves. Slowly the spots increase and form yellowish white streaks. Bacterial exudates appear in the form of droplets on the affected parts, which later on dry up forming hard resinous granules. The vascular tissue gets plugged and the plant ultimately dies. The disease is known as:

  1. Potato mosaic
  2. Bacterial blight of rice
  3. Little leaf of brinjal
  4. Late blight of potato.

Answer: 3. Little leaf of brinjal

Question 36. Prophylaxis refers to:

  1. Curing the diseased plants
  2. Improvement of the power of disease resistance of the plants
  3. Prevention of the plants from being exposed to the agencies responsible for various plant diseases
  4. All the above.

Answer: 3. Prevention of the plants from being exposed to the agencies responsible for various plant diseases

Examples Of Biopesticides Mcqs For Neet

Question 37. Quarantine regulations are a measure of control of plant diseases of:

  1. Therapeutic nature
  2. Prophylactic nature
  3. Immunization nature
  4. Not related to plant diseases.

Answer: 2. Prophylactic nature

Question 38. Bordeaux mixture contains:

  1. Borax dissolved in water
  2. Sodium bisulphite dissolved in water
  3. Copper sulphate and lime dissolved in water
  4. Phenyl mercuric acetate dissolved in water.

Answer: 3. Copper sulphate and lime dissolved in water

NEET Objective Questions On Biopesticides Question 39. Quarantine regulations are concerned with

  1. The growing of fruit trees
  2. Prevention of entry of diseased plant material into our country
  3. The spraying of diseased plants with insecticides and fungicides, etc.
  4. None of these

Answer: 2. Prevention of entry of diseased plant material into our country

Question 40. The pesticide used as a preventive measure in buildings is:

  1. Aldrin
  2. Dieldrin
  3. Endrin
  4. DDT.

Answer: 1. Aldrin

Question 41. Systematic removal of diseased plants from a field is called:

  1. Roguing
  2. Crop rotation
  3. Field sanitation
  4. Biological control.

Answer: 1. Roguing

Question 42. A good chemotherapeutic should be:

  1. Cheap, easily available and harmless to the host
  2. Toxic to the pathogen
  3. Capable of remaining on the host surface for quite some time
  4. All of these.

Answer: 4. All of these.

Question 43. A mild mosaic of potato is visible in the form of:

  1. Hypertrophy of leaves
  2. Mild interveinal mottling or chlorosis of leaves
  3. Tubers show necrotic spots
  4. Both (2) and (3).

Answer: 4. Both (2) and (3).

Question 44. A mild mosaic of potato is transmitted by:

  1. Bacteria
  2. Sap inoculum
  3. Insects
  4. Soil.

Answer: 2. Sap inoculum

Examples Of Biopesticides Mcqs For Neet

Question 45. Rugose mosaic of potato is caused by:

  1. Potato virus X
  2. Potato virus Y, t,
  3. Potato virus A
  4. Both (1) and (2).

Answer: 4. Both (1) and (2).

Agricultural Chemical Pesticides And Plant Pests Questions From Competitive Examinations

Question 1. Which of the following pesticides is an acetylcholinesterase inhibitor?

  1. Aldrin
  2. Y-BHC
  3. Endosulfan
  4. Alatliion.

Answer: 4. Allison.

Question 2. Integrated pest management (IPM) stands for:

  1. Chemical control
  2. Biological control
  3. Host plant resistances
  4. Integration of the above.

Answer: 4. Integration of the above.

Question 3. The chemical pesticide present in Baygon is

  1. Parathion
  2. Malatliion
  3. Aldicarb
  4. Propoxur.

Answer: 4. Propoxur.

Question 4. Which one is the active ingredient of flit.?

  1. Malathion
  2. Aldicarb
  3. Propoxur
  4. Carbofuran.

Answer: 1. Malathion

Question 5. Which of the following pesticides is most toxic to vertebrates:

  1. Carbamates
  2. Organochlorines
  3. Organophosphates
  4. None of these.

Answer: 3. Organophosphates

Examples Of Biopesticides Mcqs For Neet

Question 6. D.D.T. and 2, 4-D were introduced:

  1. During World War 1
  2. Just after the World War 1
  3. Towards the beginning of World War 2
  4. Towards the end of World War 2.

Answer: 4. Towards the end of World War 2.

Question 7. Carbofuran is sold in the market as:

  1. Baygon
  2. Furadan
  3. Aldrin
  4. DDT.

Answer: 2. Furadan

Question 8. Which one of the chemicals is present in Baygon?

  1. Aldicarb
  2. Propoxur
  3. Carbofuran
  4. Malathion.

Answer: 2. Propoxur

Question 9. The major drawback of D.D.T. as a pesticide is that

  1. Organisms at once develop resistance to it.
  2. It is significantly less effective than other pesticides
  3. Its cost of production is high
  4. It is not readily and rapidly degraded in nature.

Answer: 4. It is not readily and rapidly degraded in nature.

Question 10. Which is a fungicide?

  1. BHC
  2. DDT
  3. 2,4-D
  4. Bordeaux mixture.

Answer: 4. Bordeaux mixture.

Question 11. A pesticide of a lipophilic nature is:

  1. 2-4D
  2. DDT
  3. BHC
  4. Carbamates.

Answer: 2. DDT

Question 12. The common mode of action of most insecticides is through the attack on:

  1. Nervous system
  2. Circulatory system
  3. Respiratory system
  4. Muscular system.

Answer: 1. Nervous system

Question 13. Which of the following is not correctly matched:

  1. Pyrethroid—Arazine
  2. Organochlorine—D.D.T.
  3. Organophosphate—Malathion
  4. Carbamate—Carbaryl.

Answer: 1. Pyrethoid—Arazine

Biopesticides Mcq For Neet

Question 14. Which of the following ingredients of pesticide killed hundreds of people in the Bhopal gas tragedy:

  1. Carbon tetra chloride
  2. Methyl isocyanate
  3. Mustard gas
  4. Nitrous acid.

Answer: 2. Methyl isocyanate

Question 15. Herbicides interfere with

  1. Carbon dioxide absorption
  2. Water absorption
  3. Translocation of sugar
  4. Photolysis of water.

Answer: 4. Photolysis of water.

Question 16. Drinking mineral water with very low pesticides (about 0.02 ppm) for long periods may:

  1. Cause cancer of the intestine
  2. Produce immunity against mosquito
  3. Cause leukaemia (blood cancer) in most people
  4. Lead to the accumulation of pesticide residues in body fat.

Answer: 4. Lead to accumulation of pesticide residues of body fat.

Question 17. Which one among the following is likely to have the highest level of DDT deposition in its body?

  1. Crab
  2. Eel fish
  3. Sea gull
  4. Phytoplanktons

Answer: 3. Seagull

Mcqs On Biopesticides Question 18. The chemicals used in the National Malaria Eradication Programme are:

  1. BHC
  2. DDT
  3. 2,4-D
  4. Pyrethroid

Answer: 2. DDT

Biopesticides Mcq For Neet

Question 19. Which one is a pest:

  1. Mouse
  2. Pathogen
  3. Insect
  4. All of these.

Answer: 4. All of these.

Question 20. Insecticides obtained from neem plant are:

  1. Pyrethrin
  2. Pyrethroid
  3. Thiocarbamate
  4. Azadirachtin.

Answer: 4. Azadirachtin.

Question 21. Which of the following statements is correct about DDT?

  1. It is not a pollutant
  2. It is a biomagnifying biodegradable pollutant
  3. It is a non-biomagnifying biodegradable pollutant
  4. It is a biomagnifying non-biodegradable pollutant.

Answer: 4. It is a biomagnifying non-biodegradable pollutant.

Mcqs On Biopesticides Question 22. Weed killers generally have properties much like that of:

  1. Hormones
  2. Carbohydrate
  3. Enzymes
  4. All of these.

Answer: 1. Hormones

Question 23. Bordeaux mixture can be prepared by mixing the copper sulphate with:

  1. Limestone
  2. Sodium chloride
  3. Calcium sulphate
  4. Milk of calcium hydroxide.

Answer: 4. Milk of calcium hydroxide.

Question 24. Which is used as weedicide?

  1. 2, 4-D
  2. IBA
  3. IAA
  4. ABA.

Answer: 1. 2, 4-D

Question 25. Biomagnification phenomenon is related to the pollutant:

  1. CO2
  2. NO2
  3. DDT
  4. SO2

Answer: 3. DDT

 

NEET Biology Notes on Human Growth Development

NEET Biology Human Growth Development

  • Growth is defined as an irreversible permanent change in the volume or size of a living body accompanied by a change in the dry weight.
  • It involves 3 phases i.e. phase of cell division, phase of cell elongation, and phase of cell differentiation.
  • Growth is always followed by differentiation and the two phenomena jointly constitute a larger phenomenon called development.
  • The growth centers in higher plants are called meristems which may be apical, lateral, or intercalary.
  • The growth at the cellular level is initiated by plasmatic growth. A cell passes through 3 phases of growth, differentiated as cell formation, cell elongation, and cell maturation.
  • The growth may be measured in terms of fresh weight, dry weight, length, and area.
  • Growth in length can be measured by horizontal microscopy, are indicator, or auxanometer. Bose’s crescograph is the finest instrument for measuring growth.

Sachs was the first to plot growth rate i.e., increase of growth per unit of time, and obtained a sigmoid curve.

Growth And Development Of S -Shaped Growth Curve

Human Growth and Development NEET Notes

He differentiated three phases i.e., lag, log or exponential, and steady-state followed by the senescence phase. In some plants, a linear phase is recognized.

  1. The arithmetic growth of the root can be put as Lt = Lo +rt, where Lo is the length at zero time, Lt at time t, and r is the growth rate.
  2. Maintenance of the ratio between the growth rates of different parts is called allometric growth. The growth shows a diurnal rhythm. They are partly endogenous and partly governed by external factors.
  3. The growing shoot tip follows a helical path and the phenomenon is called circumnutation. Many phases of plants operate by a ‘biological clock’.
  4. When a distinct juvenile phase is identified in the life history, the development is said to be heteroblastic. Such phases have been seen in many plants. Example:  BatrachosperDuan, Hedera, Citrus, Quercus, etc.

The juvenility may be due to arrested development or low light intensity. In Acacia melamoxylon, it recapitulates phylogeny.

Human Growth And Development NEET Notes

NEET Biology Notes On Human Growth Development Factors Affecting Growth

The growth of plants is fundamentally regulated by genetic factors via the production of several enzymes. Multiple environmental elements affect growth, including flight, temperature, CO2 levels, moisture, nutrition, and pollution.

  • Plants growing in darkness exhibit etiolation. Light intensity influences leaf orientation, chlorophyll synthesis, and other factors. Sun leaves differ from shadow leaves.
  • Optimal growth is observed under red light, while minimal growth occurs under green light among monochromatic lights. Gamma, ultraviolet, and X-rays are detrimental to plants. The length of light influences flowering.
  • The temperature thresholds for the growth phase are 5°C, 20-30°C, and 35-40°C. They respond to diurnal (photo-temperature) and nocturnal temperatures. This occurrence is referred to as thermoperiodicity.
  • Exposure to severe temperatures results in harm to plants. For instance, desiccation, refrigeration, and cryopreservation.
  • To endure these challenges, a plant exhibits both internal and external adaptations.
    An elevation in CO2concentration from 300 to 1000 ppm enhances net respiration (NR) and relative growth rate (RGR) in certain plant species. Moisture stress may cause the RGR to decline to zero.
  • The growth of plants is affected by mineral deficiencies, specifically nitrogen, calcium, iodine, and boron.
  • Growth is significantly impacted by contaminants including fluorine, ozone, and ethylene.

Human Growth And Development NEET Notes

NEET Biology Notes On Human Growth Development Growth regulators

  1. Growth is regulated not only by environmental factors like light and temperature but also by certain chemical substances within the plants.
  • These substances are known as plant hormones, growth hormones, phytohormones, or growth regulators.
  • A plant hormone can be defined as a chemical substance, which is capable of translocation and regulating one or more physiological reactions, when present in low concentrations.
  • The plant hormones can have a positive effect on a process and thus promote it, or they have a negative effect and cause inhibition. A particular hormone may promote certain processes, or inhibit some other processes.

Human Growth And Development NEET Notes

NEET Biology Notes On Human Growth Development Auxins

  • Auxins (auxin = to grow) are a class of phytohormones that promote longitudinal growth in plants.
  • Auxins that occur in plants are called natural auxins eg.- indole-3-acetic acid, Indolc- 3-acetaldehyde, and Indolc-3-pyruvic acid.
  • Synthetic auxins are synthesized artificially and have properties like auxins, eg.- Naphthalene Acetic Acid (NAA), Indole Butyric Acid (IBA), Indole Propionic Acid (IPA), 2, 4-Dichlorophenoxy acetic acid (2,4-D).
  • The biosynthesis of auxin has been traced back from the amino acid tryptophan.
  • The movement of auxins is polar and basipetal in most plants.
  • Auxins can be degraded by the enzyme system IAA oxidase and also by light. They can be inactivated by X-rays UV-rays and gamma rays.
  • Auxins are synthesized in the apices ol‘ the stem.
  • The most characteristic action of auxin is to promote cell enlargement.
  • Auxins cause growth in leaves, roots, stems, etc. by Indicating cell enlargement and cell elongation.
  • The cell enlargement is due to ;
    1. Increase in osmotic content of the cell.
    2. increase in cell permeability to water. ,
    3. Reduction in wall pressure,
    4. Increase in wall synthesis and,
    5. Synthesis of specific RNA and proteins which increase cell wall plasticity.

Human Growth And Development NEET Notes

NEET Biology Notes On Human Growth Development Gibberellins

They are weakly acidic plant growth hormones that possess a gibbon ring, structure, and can bring about cell elongation of both leaves and stems in general, and intermodal length of genetically dwarf plants in particular.

  • They are named after the fungus Gibberella  (= Fusariitm moniliform) which produces balance (foolish seedling disease) in rice. The hormone was discovered by Yabuta and Suniiki. Yabuta (1935) coined the term gibberellin.
  • About 100 gibberellins are known, GA or gibberellic acid is the commonest. GA4 and GA2 are also commercially used. Gibberellins are synthesized in plants in the leaves of buds, developing embryos, and root tips.
  • GA3 promotes intermodal elongation and flowering.
  • They promote stem growth by activating the subapical meristem of the stem tip.
  • The elongation of internodes before flowering in rosette plants is called bolting.
  • Applications of gibberellins induce bolting.
  • Gibberellins induce flowering in long-day plants during short-day conditions, e.g.- cabbage, Rudbeckia.
  • Gibberellins induce flowering in plants that require cool winter nights before flowering (i.e., they substitute the cold treatment, vernalization).
  • Gibberellins break the dormancy in buds and seeds.
  • Gibberellins promote the germination of cereal grains such as barley, wheat, rice, etc.
  • Gibberellins promote the development of parthenocarpic fruits in tomatoes, apples, almonds, etc.
    1. The size of the fruits and seeds also increases due to gibberellin treatment.
    2. When giberellins are sprayed on plants their leaves become expanded. It increases the total photosynthetic area and biomass.
    3. Gibberellins inhibit the formation of adventitious roots from the cut end of the stem.
    4. Parthenocarpy. They can induce parthenocarpy in several plants.
    5. Maleness. Gibberellins stimulate maleness.
    6. Fruit Yield. Gibberellin application increases the number and size of fruits, e.g., grapes.
    7. Malt. There is increased malt production when gibberellins are provided to germinating barley grains (due to greater production of a-amylase).
    8. Sugarcane. GA application increases the sugar yield of sugarcane by promoting intermodal length.

NEET Human Growth And Development Chapter Notes

NEET Biology Notes On Human Growth Development Cytokinins

Cytokinins are slightly basic growth hormones, often derivatives of amino-purine (sometimes adenine), that stimulate cell division in plants. The initial cytokinin was identified by Miller et al. (1955) via the autoclaving of Herring sperm DNA.

  • The substance is a synthetic compound known as kinetin. It is 9-furfurylaminopurine. The initial natural cytokinin was identified by Letham et al. (1963). It was satin fabric. Approximately 18 cytokinins have been identified, including dihydrozeatin, IPA, and benzyl adenine.
  • Cytokinins are crucial for cytokinesis via chromosomal duplication and may occur in their absence.
  • Cytokinins induce division in permanent cells in the presence of auxin.
  • Cytokinins, like to auxin and gibberellins, induce cell elongation.
  • Buds arise when cytokinins are in surplus, but roots develop when their ratios are inverted (Skoog and Miller, 1957).
  • Cytokinins promote plastid differentiation, lignification, and the development of interfascicular cambium.
  • Cytokinins postpone the senescence of leaves and other tissues. They also enhance resilience to harsh temperatures and diseases.
  • They function antagonistically to auxin, which facilitates apical dominance.
    Similar to gibberellins, they mitigate seed dormancy.
  • They facilitate phloem movement.
  • Cytokinins, similar to auxins and ethylene, facilitate the development of female characteristics in flowers.

Human Growth And Development Class 12 Notes For NEET

NEET Biology Notes On Human Growth Development Ethylene

  1. Ethylene (CH2 = CH2) is a volatile gas present in the atmosphere and as a component of smoke and other industrial gases. Ethylene is formed by incomplete combustion of carbon-rich compounds such as coal, petroleum, and natural gas.
  2. Soon after the introduction of illuminating gas (produced from coal) for home and street lighting, evidence of plant damage was observed. Physiological studies confirmed that plants produce ethylene by metabolic process during growth and development.
  3. Ripening fruits in particular synthesize quantities of ethylene that build up to rather high concentrations within intercellular spaces of fruit tissue. The most important effect of ethylene on fruit ripening is that it is produced in large amounts which coincides with the respiratory climacteric.
  4. Excess of auxin causes ethylene synthesis.
  5. In the presence of ethylene, roots become apogeotropic while stems turn positively geotropic.
  6. Abscission of various parts (leaves, flowers, fruits,) is stimulated by ethylene which induces the formation of hydrolases.
  7. Ethylene promotes apical dominance and prolongs the dormancy of lateral buds.
  8. In low concentrations ethylene helps in root initiation, growth of lateral roots, and root hairs.

NEET Biology Human Growth And Development Revision Notes

NEET Biology Notes On Human Growth Development Abscisic Acid (Aba)

  • It is also called stress hormone or dormant because the production of hormones is stimulated by drought, water logging, and other adverse environmental conditions.
  • The hormone is an inhibitor that counteracts the influence of growth-promoting hormones (auxin, gibberellins, and cytokinins), induces dormancy, and helps overcome conditions of stress. The hormone was discovered by Addicott et al in 1963.
  • It is commonly formed inside chloroplasts either from mevalonic acid or xanthophyll-like violoxanthin.
  • It is known as dormant as it induces dormancy in buds, underground stems, and seeds.
  • This hormone was first isolated by Addicott et al (1963) from cotton balls.
  • It is produced in many parts of the plants but more abundantly inside the chloroplasts of green cells.
  • The hormone is formed from mevalonic acid or xanthophylls.
  • It is transported to all parts of the plant through diffusion as well as transport channels (phloem and xylem).
  • Abscisic acid induces dormancy of buds towards the approach of winter.
  • The buds as well as seeds sprout only when abscisic acid is overcome by gibberellin.
  • The formation of abscisic acid stops mitosis in the vascular cambium towards the approach of winter.
  • Abscisic acid promotes the abscission of flowers and fruits.

NEET Biology Notes Oon Human Growth Development Calines

  • The effect of auxin on root, stem, and leaves is not an isolated reaction but involves other natural hormones called canines which are of three types :
  1. Rhizocaline: It is a special root-forming honnone produced by the leaves and transported in a polar manner down the stem.
  2. Caulocaline: It is a stem-forming hormone synthesized in roots from where it is translocated to its site of activity in the stem. ,
  3. Phyllocaline: It stimulates mesophyll development in leaves. It is synthesized only in the presence of light and the actual site of its synthesis is not known.

NEET Biology Human Growth And Development Important Points

NEET Biology Notes On Human Growth Development Florigen

It is a floral hormone that is produced in photo-induced leaves and translocated to apical and lateral meristems where flower formation is initiated

Growth And Development Uses Of Some Synthetic Auxins

NEET Biology Human Growth And Development Important Points

NEET Biology Notes On Human Growth Development Useful Information

  • Went is credited with the discovery of auxins.
  • Hitchcock and Zimmerman showed that flowering in Nicotiana can be accelerated by auxins.
  • Auxins prevent premature leaf fall by arresting the formation of the abscission layer.
  • Snow (1933) showed that the reactivation of the cambial cells in the spring season is due to auxins.
  • Went named the growth-promoting substance Auxin (auxin = to grow)
  • Kogl and Haagen Smith isolated three chemicals from human urine and named them auxin a, auxin b, and heteroauxin.
  • IAA was first discovered by KogI et al in 1934.
  • Letham et al obtained the first naturally occurring cytokinin from unripe maize grain called Zeatin (6 hydroxy, 3 methyl trans, 2 butenyl amino purine).
  • Crookes et al recognized ethylene as a plant hormone. r4 Cams and Addict (1961) extracted abscisin-1 and abscisic-II from old cotton bolls and young cotton bolls respectively.
  • Knott (1934) found that the locus for photoperiodic induction occurs in the leaves.
  • Wellensick (1964) found that the locus for perception of cold treatment is the mer- istematic cells, especially the shoot apex.
  • Yabuta (1935) separated the hormone and named it Gibberellin.
  • O Yabuta (1938) prepared a crystalline form of Gibberellin.
  • Hitchcock and Zimmerman showed that flowering in Nicotiana can be acceler¬ated by auxins.
  • Snow (1933) showed that the cambial cells become activated in spring due to auxins.
  • Brain et al (1955) isolated GA3 in pure form.
  • Cross et al (1961) worked out the structure of Gibberellin or GA3. It is chemically CL 19 ^22
  • The first cytokinin was discovered by Miller et al and called Kinetin.
  • Draghett (1933) used the term crypto vegetation to signify a state of vegetation maintained by certain plants under low-temperature conditions of winter.
  • Peter Ray et al showed that IAA promotes the liberation of a water-soluble xyloglucan from the cell wall.
  • Boysen Jensen (1931) while working on coleoptiles of oats (Avena saliva), concluded that growth triggering substance is synthesized in the coleoptile tips.
  • Paal (1919) confirmed that growth-promoting substance is synthesized in the stem tips only.
  • Went extracted the substance from Avena coleoptile tip and observed its effects
    on the stump. He named the substance as auxin.
  • Kogl, Erxlaben, and Haagen-Smit isolated heteroauxin from human urine which was chemically Indole-3-acetic acid (IAA). The term auxin was coined by KogI.

Stages Of Human Growth And Development NEET 

NEET Biology Notes On Human Growth Development Photoperiodism

  • Light is of crucial significance in the flowering of plants. The response of a plant to the Native lengths of light and dark periods is called photoperiodism and the length of the daylight required by the plant to flower is called photoperiod.
  • Garner and Allard (1920) classified plants into three groups according to their photoperiods.
  • Short-dav plants (SDP or long-night plants): These plants flower when the day length is less than a certain critical length (critical day length is the photoperiod required to induce flowering) say 12 hours. Some examples of short-day plants are tobacco, soybean, Xanlhium, and Chrysanthemum. etc.
  • Long-day plants: These plants flower when the day length is greater than a certain critical length example. Spinach, sugarbeet, radish, henbane, potato etc.
  • Day-neutral plants: These plants flower in all possible photoperiods e.g. tomato, four o’clock, cotton, cucumber, balsam, maize, etc.
  • The photoperiodic stimulus is received by a pigment called phytochrome present in leaves. This pigment is a protein with a chromophore prosthetic group. It seems to be localized in the cell membranes. Phytochrome exists in two interconvertible forms i.e. Pr and Pfr.
  • The Pr form of phytochrome absorbs red light (660 nm) and is converted into Pfr form while Pfr forms absorb far-red light (730 nm) and are converted into Pr form. Under continuous darkness, the Pfr form of phytochrome gradually changes to Pr form which promotes the formation of flowering stimulus in short-day plants.
  • If the long dark period is interrupted by red light, the Pr form is converted into Pfr form which inhibits the formation of flowering stimulus in short-day plants. In long-day plants, the flowering is promoted by the Pfr form of phytochrome as the long light period favors the conversion of Pr to the Pfr form of phytochrome.
  • It is. therefore, concluded that flowering in short-day plants is promoted by the Pr form and inhibited by the Pfr form whereas in long-day plants, flowering is promoted by the Pfr form of phytochrome and inhibited by the Pr form.
  • The floral stimulus is a floral hormone. Butler and others isolated the phytochrome pigment responsible for the above change. It is a glycoprotein having a molecular weight of 1,25,000 and located in the plasma membrane. It occurs in two forms PR and Pp^ which are interconvertible as under :
  • The photo-induced leaves synthesize this floral hormone called florigen which is translocated to the site of flower formation. Cajlachjan (1958) suggested that there are two steps involved in the flowering process, the first mediated by gibberellin and the second by the flowering factor called ‘adhesive.’
  • Together, gibberellin and anthesine constitute the true florigen.

Photoperiodism and C/N Ratio: Kraus and Kraybill, 1918, while working with tomato plants discovered an interesting correlation. They found that different levels of carbohydrate and nitrate supply produce different responses in the plant. Broadly speaking there are four possibilities.

  1. Very high C/N Ratio → Plants remain weakly vegetative and no flowering is observed.
  2. High C/N Ratio → Plants show less vegetative growth but flower profusely.
  3. Low C/N Ratio→ Plants show luxuriant vegetative growth but no flowering is observed.
  4. Very low C/N Ratio → Plants show weak vegetative growth but fail to produce flowers.
  • The Day neutrals or photo neutrals do not need any specific photoperiod for flowering example, Cucumis, Gossypium, impatiens, Lycopersicon, Zea, Mirabilis, etc.
  • The photoperiod needed for flowering is called a critical day length. In short-day plants, it indicates the minimum period whereas in long-day plants, it tells the maximum photoperiod.
  • Based on experiments Knott, and Cajlachjan confirmed that photoperiodic and photoperiodic stimulus is captured by leaves of cotyledons. The experiments were conducted on loin pioups of plants of Chrysanthemum.

The photoperiodic stimulus may be systemic (Xanthium) or localiscil ((cosmos), Host flowering ooouis in red wavelength. poor flowering under blue and no flowering occurs in green.

Factors Affecting Growth And Development NEET

NEET Biology Notes On Human Growth Development Vernalization

  • Many species, especially biennials and perennials, arc induced or promoted to flower by low temperatures. Vernalization is the low-temperature treatment given to water-soaked seeds, slightly germinated seeds, or seedlings to hasten the time of plants that will develop from them.
  • So, vernalization can best be defined as “The acquisition or acceleration of tire ability to flower by a chilling treatment.’’ (Chounrd 1960).
  • T.D Lysenko used the term vernalization as a low-temperature promotion of flowering in plants, The low-temperature requirement for flowering was first noticed by lvlippart (1837) while working with two varieties of wheat, the winter wheat and the spring wheat.
  • He concluded that winter wheat requires low treatment (0 – 5° C) for subsequent flowering, a tire phenomenon now called vernalization. It is an aerobic process.
  • Plains, in nature, requiring vernalization commonly behave as biennials. The biennials complete their life cycle in two years. They germinate and grow vegetatively in the first year and produce flowers in the second year of growth.
  • These fulfill their cold requirement during winter.
  • Russian scientists recognized the following two phrases in vernalization.
  • Thermophase. It requires a temperature varying between 10 – 20° C together with some moisture and oxygen (so that the embryo wakes up from the dormancy).
  • This phase has to be completed before the initiation of the primordia of reproductive organs. The period of low-temperature treatment varies from four days to three months in different plants. Thermophase can take place during the day as well as at night.
  • Photophase. A thermophase has to be followed by a period of illumination (i.e., photoperiod) and a period of relatively high temperature.
  • This low-temperature treatment given to the seeds to reduce the vegetative growth period and accelerate flowering is called vernalization or Yarovization. The site of vernalization is believed to be the growing point (apical bud).
  • The German botanist, Melchers (1939) demonstrated that the product of vernalization could be transmitted from a vernalized to an unvernalized Hyoscyamus plant through a graft union. He named this substance vernalin which is a hypothetical one and has not been isolated yet.
  • The vernalization effect is reversible and the process is called deyernalization. If the vernalized seeds are kept at high temperatures or under anaerobic conditions, they revert to their normal nature and produce biennial plants.

Growth Hormones And Development NEET

Human development NEET notes Mechanism Of Vernalization

  • To explain the mechanism of vernalization in physiological terms, three different hypotheses have been put forward.
  • Antagonism between vegetative and reproductive growth. According to this theory, vegetative growth and flowering are antagonistic to each other. Thus any means of repressing vegetative growth would result in flowering.
  • Phasic development hypothesis. Lysenko (1932) emphasized the distinction between growth (quantitative change or increase in size) and development (a qualitative change or progressive change in the characteristics of new organs produced in cell division) and opined what has become known as the ‘Phasic development theory’.
  • According to this theory, the process of development of an annual seed plant consists of a series of phases that must occur in some predetermined sequence. When the proceeding phase is completed, the onset of any one phase will only take place.
  • Flower-producing substances hypothesis—Regarding the role of flower-producing substances during vernalization in cereal plants, Purvis (1961) has proposed a scheme. According to Purvis’s scheme, B is some compound that is part of a reaction system leading to flowering.

Growth And Development In Flower Producing Substances Hypothesis

Difference Between Growth And Development NEET

NEET growth and development Biology Factors Affecting Vernalization

  1. Water and Oxygen. Dry seeds cannot be vernalized. Seeds need to imbibe about 30¬40% moisture before they can be vernalized. Although moisture may be present, in the absence of air or oxygen, seeds or plants cannot be vernalized.
  2. In other words, active respiration is essential. This is supported by the fact that the inhibitors of respiration such as cyanide and dinitrophenol prevent vernalization even when other conditions are favourable.
  3. Temperature. The seeds of plants can be vernalized by exposing them to low temperatures. Usually, a temperature in the range of 1-7° C is equally effective. Vernalization, although weak, is still possible at temperatures lower than this range up to-4 °C and the higher range up to 12°C. Temperature beyond 12°C does not cause vernalization.
  4. Food Substances. If vernalization has to take place, there should be a source of carbohydrates. Isolated embryos of cereals cannot be vernalized till these are supplied with sucrose and minerals.
  5. Effect of Light. Light does not affect the process of vernalization. Many plants like carrots and hyoscyams have both vernalization and photoperiodic requirements for flowering.
  6. Effect on Hormones. Many species with an obligate vernalization requirement such as Carrot and Hyoscyams are rosette in habit during the vegetative stage. When vernalized, these plants show flowering, and flowering is accompanied by rapid elongation.
  7. Such an elongation of the stem is called bolting. In such rosette plants, the vernalization requirement can be replaced by the application of gibberellic acid.
  8. In these plants, GA causes both bolting and flowering without the necessity of exposure to low temperatures.

Role Of Endocrine System In Human Growth NEET

NEET Biology Notes On Human Growth Development Senescence

As the young plant grows, it undergoes aging and develops into mature plants in an orderly fashion. Senescence constitutes a collective, progressive, and deteriorative development process that ultimately leads to the complete loss of organization and function of plant or plant parts.

Types of senescence. Mainly senescence is of two types :

  1. Whole plant senescence. In the case of monocarpic species ( which flower and form fruit only once in their lifetime and then die) whole plant senescence occurs e.g.wheat, soybeans (annuals), agave, bamboo, sunflower etc.
  2. Organ senescence. In polycarpic species (which flower and form fruit repeatedly) senescence and death are not associated with flowering and fruiting. Organ senescence is of the following types.
  3. Shoot senescence. In herbaceous perennials, the whole above-ground part of the plant body may senescence and die each year. example: Gladius, Ginger, Rumex, Banana.
  4. Simultaneous or synchronous senescence. Leaves of temperate deciduous woody arcs may sense and fall at a certain season of the year. It is controlled by environmental factors rather than internal factors.
  5. Sequential senescence. It is the progressive senescence of older leaves which may occur at any time of year. Each leaf in most of the plants has a limited life span, so that the shoot grows in height, lower older leaves tend to senesce and die.
  6. Retardants of Sense . Kinetin, a growth regulator, retards senescence of leaves. It causes a rapid increase in the rate of RNA and protein synthesis and it also causes mobilization of metabolites.
  • Growth is a quantitative phenomenon and can be measured over time.
  • Quiescence is the suspension of growth due to external factors such as changes in surrounding conditions.
  • Seed dormancy may be due to rudimentary, embryos, permeable seed coats, mechanically resistant seed coats, physiologically immature embryos, and due to presence of germination inhibitors.
  • The common germination inhibitors are abscisic acid, phenolic acids, short-chain fatty acids, and coumarin.
  • Rhizophora. Sonneratia and Heriticra growing in marshy land show a special type of germination termed vivipary, in which seed germination within the fruit, while still attached to the parent plant.
  • The rate of growth is called the efficiency index.
  • Auxin precursors tire the compounds which can be converted to auxins.
  • Antiauxins inhibit the action of auxins
  • Free auxins can be easily extracted and are active.
  • Bound auxins are inactive and hard to extract. They need the use of organic solvents. A dynamic equilibrium exists between the two forms.

Human Growth And Development NEET Chapter Summary

NEET Biology Notes on Human Growth Development Quanta to Memory

  • The presence of more auxin on the lower side of the stem apex causes more growth oil on that side.
  • The presence of more auxin in the root has a negative effect i.e., it inhibits growth on the lower side.
  • IAA (Indole Acetic Acid) is the principal naturally occurring auxin found in all plants studied so far and also in fungi.
  • IAA Destruction is caused by : (i) Photo-oxidation by blue light, and (ii) Dark oxidation by IAA-oxidase.
  • Auxin IAA stimulates ethylene synthesis in a plant.
  • IAA also occurs in human urine, especially in persons suffering from pellagra.
  • Bioiissay means the testing of a substance for its activity in living organisms under controlled conditions.
  • Abscission is the shedding of leaves, fruits, or (lowers by a plant generally due to a change in the hormonal balance.
  • The term Phytoalexin was introduced by Muller (1956) example. Pisatin in Pisum sativum is due to an infection of Ascochyta Ω.
  • 0•025 % of maleic hydrazide prevents potato sprouting.
  • Cytokinins along with auxins help in the differentiation of roots and shoots.
  • 2,4 D is a synthetic auxin acting as a weedicide.
  • Abscisic acid inhibits gibberellin-mediated amylase formation during the germination of cereal grains.
  • ABA has been found to induce parthenocarpic development in roses.
  • The use of abscisic acid promotes rooting in many stem cuttings.
  • It counteracts the effects of all growth-promoting hormones (auxins, gibberellins, cytokinins) and therefore, keeps their activity under check.
  • The role of IAA in humans is not known.
  • In maize, the single cotyledon never leaves the germinating grain and plumule grows out of coleoptile.
  • Vernalization was first studied in Europe on the winter varieties of cereals such as wheat, barley, rye, and oat.
  • The chemical nature of vernalin (Cold induced stimulus) is not known.
  • In growth anabolic processes dominate over the catabolic processes and therefore growth is the final product of successful metabolism.

NEET Biology Tools And Techniques Multiple Choice Questions

NEET Biology Tools And Techniques Multiple Choice Questions

Question 1. Fluorescent dye bonded to monoclonal antibodies is used to locate particular:

  1. Cell proteins
  2. Cells
  3. Diseased parts
  4. Organs of defence.

Answer: 1. Cell proteins

Question 2. The scientists who developed the technique of keeping tissue and organs alive outside the body are:

  1. Ringer
  2. Cannon
  3. Lorenty
  4. Binning and Rohrer.

Answer: 1. Ringer

Read and Learn More NEET Biology Multiple Choice Question and Answers

Question 3. The Electron microscope has revealed the presence of:

  1. Chloroplasts
  2. Leucoplasts
  3. Ribosomes
  4. Chromosomes.

Answer: 3. Ribosomes

Tools and Techniques MCQs For NEET

Question 4. Magnification of a “compound microscope” does not depend upon :

  1. The focal length of the objective
  2. The focal length of the eyepiece
  3. Tube length of the microscope
  4. Numerical aperture of the objective.

Answer: 4. Numerical aperture of objective.

Question 5. For studying the metabolism of deoxyribonucleic acid, an autoradiographic technique is used involving:

  1. Tritiated uridine
  2. Tritiated thymidine
  3. Tritiated mannose
  4. Tritiated amino acids.

Answer: 2. Tritiated thymidine

Question 6. Phase contrast microscope was designed by:

  1. Tolles
  2. Zernicke
  3. Hooke
  4. Zsigmondy.

Answer: 1. Tolles

Question 7. Scanning electron microscope (sem) is primarily used for :

  1. 3-D external surface only
  2. 3-D internal study of tissue
  3. 2-D external study
  4. 2-D internal study.

Answer: 1. 3-D external surface only

Question 8. In a microscope. A lens closer to the eye is called :

  1. Ocular
  2. Eye piece
  3. Both 1 & 2
  4. Oculomotor.

Answer: 1. Eyepiece

Question 9. The electron microscope is made up of :

  1. Fluorochromes
  2. Polariser and analyser filter
  3. Electromagnetic lenses
  4. Objective and ocular lenses.

Answer: 3. Electromagnetic lenses

Tools and Techniques MCQs For NEET

Question 10. Angstrom, the unit of measurement in the transmission electron microscope , is equal to :

  1. 0.01tim
  2. 0.001pm
  3. 0.0001pm
  4. 0.00001pm.

Answer: 3. 0.0001pm

Question 11. The resolving power of an electron microscope is :

  1. 1A
  2. 10a
  3. 100A
  4. 10004.

Answer: 2. 10a

Question 12. Knoll and Ruska first designed the electron microscope in the year:

  1. 1932
  2. 194S
  3. 1941
  4. 1900.

Answer: 1. 1932

Question 13. Among the following isotopes, which is not radioactive?

  1. C-o
  2. P-
  3. H
  4. O-.

Answer: 4. O-.

Question 14. X-ray crystallography is used to study :

  1. Structure of lipids
  2. Composition of proteins and nucleic acids
  3. Arrangement of proteins
  4. Three-dimensional structure of proteins.

Answer: 2. Composition of proteins and nucleic acids

NEET Biology Tools And Techniques Questions

Question 15. One of the important techniques used to study the synthesis of molecules and to trace the metabolic pathway or events in cells is:

  1. Autoradiography
  2. Microspectrophotometry
  3. Calorimetry
  4. Chromatography.

Answer: 1. Autoradiography

Question 16. Resolution power is the ability to :

  1. Distinguish two close points
  2. Distinguish two close objects
  3. Distinguish amongst organelles
  4. Magnify images.

Answer: 1. Distinguish two close points

Question 17. What will you call the study of plants and animals outside the body in a glass tube?

  1. In vivo
  2. In vitro
  3. Innate
  4. Desperate.

Answer: 2. Innate

Question 18. When biologists wish to study the internal ultrastructure of cells, they most likely would use :

  1. A good modern light microscope
  2. A scanning electron microscope
  3. A transmission electron microscope
  4. None of the above.

Answer: 3. A transmission electron microscope

Question 19. Living cells can be studied by :

  1. Phase contrast microscope
  2. Fluorescent microscope
  3. Electron microscope
  4. Light microscope.

Answer: 1. Phase contrast microscope

NEET Biology Tools And Techniques Questions

Question 20. The method most frequently used to determine the molecular weight of proteins is :

  1. X-ray diffraction
  2. Classical chemistry
  3. Ultra-centrifugation
  4. Both 1 and 2.

Answer: 3. Ultra-centrifugation

Biotechnology Principles and Processes MCQ for NEET Question 21. Which of the following techniques other than a microscope

  1. Plasmolysis
  2. Maceration
  3. Chromatography
  4. Auto-radiography.

Answer: 4. Auto-radiography.

Question 22. The electron microscope differs from the ordinary microscope in having resolving power due to the use of:

  1. Electrons, which have a longer wavelength than ordinary light, as the source of illumination
  2. Ultraviolet light as the source of illumination
  3. Fast electrons which have shorter wavelengths than ordinary light rays as the source of illumination
  4. Gamma rays as the source of illumination.

Answer: 3. Fast electrons which have shorter wavelengths than ordinary light rays as the source of illumination

Question 23. A student wants to study the metaphysic behaviour of chromosomes/chromosomes in a living cell. The technique most suitable is:

  1. Phase contrast microscope
  2. Scanning electron microscope
  3. X-ray microscope
  4. Cell fractionation.

Answer: 1. Phase contrast microscope

Question 24. What is the primary objective of cell fractionation?

  1. To view the structure of cell membranes
  2. To identify the enzymes outside the organelles
  3. To determine the size of various organelles
  4. To separate the organelles.

Answer: 4. To separate the organelles.

Biotechnology Tools MCQs For NEET

Question 25. High-wavelength UV rays are used in:

  1. Fluorescent microscope
  2. Polarising microscope
  3. Ultraviolet microscope
  4. Phase-contrast microscope.

Answer: 1. Fluorescent microscope

Question 26. The pattern of protein binding on dna can be studied by

  1. Light microscope
  2. Electron microscope
  3. Ultracentrifugation
  4. X-ray crystallography.

Answer: 4. X-ray crystallography.

Question 27. Fundamentally a dead cell differs from a living cell when seen under a phase contrast microscope because:

  1. It has become separated from other cells
  2. Its vital forces have been destroyed
  3. A change in its surrounding environment has occurred
  4. A change in its specific organization has occurred.

Answer: 2. Its vital forces have been destroyed

Question 28. The part of a cell that can be seen with an electron microscope, but never with a light microscope is/are the:

  1. Nucleus
  2. Golgi bodies
  3. Chloroplasts
  4. Mebrane separating the nucleus from the cytoplasm

Answer: 3. Chloroplasts

NEET Previous Year Questions On Lab Techniques

Question 29. A lab technician spun a cell suspension from leaf tissue in a centrifuge in a slurry of sucrose at a speed that formed a bright green band about halfway down the solution in the tube. In what fraction would you expect to find the nuclei?

  1. In a pellet at the bottom of the tube
  2. In the green band
  3. In a dark band above the green band
  4. In the supernatant.

Answer: 1. In a pellet at the bottom of the tube

Question 30. You have developed a stain that colours alpha and beta tubulin a bright orange colour. When the stain is ap- plied to non-dividing leaf cells, what area of the cell would you expect to be orange when viewed with a light microscope?

  1. The nucleus
  2. The cell wall adjacent to the surface of the plasma membrane
  3. The cytoskeleton
  4. Flagella.

Answer: 4. Flagella.

Question 31. A cytologist must decide what type of microscope to purchase for his laboratory. The lab examines fibres and hairs. And other forensic evidence as whole specimens. As the microscope salesperson, you suggest that he should buy:

  1. A light microscope with a resolution power of 1 nm.
  2. A scanning electron microscope.
  3. A transmission electron microscope with a maximum magnification of 1,000 x.
  4. An electron microscope with resolution power of about 2 nanometres.

Answer: 2. A transmission electron microscope with a maximum magnification of 1,000 x.

NEET Biology MCQ Test  Question 32. Cellulose in a cell is stained by :

  1. Ivlethylene blue
  2. Zinc chloro-iodide
  3. Sudan iv
  4. Ruthenium red.

Answer: 2. Zinc chloro-iodide

Question 33. Elisa is used to detecting viruses where the key reagent is:

  1. Catalase
  2. Osmic acid
  3. Acetylcholinesterase
  4. Alkaline phosphate.

Answer: 4. Alkaline phosphate.

Question 34. A fluorescence microscope is used to:

  1. Increase resolving power
  2. Localise cell components
  3. Obtain x-ray dif1iaction pattern of dna
  4. Study cells and their components in a living state using phase differences in light rays.

Answer: 2. Localise cell components

NEET Previous Year Questions On Lab Techniques

Question 35. Cell organelles can be separated by :

  1. Differential centrifugation
  2. Autoradiography
  3. Thin section microtomy
  4. X-ray diffraction.

Answer: 1. Differential centrifugation

Question 36. If a biochemical analysis of mitochondria is to be done, the best procedure would be:

  1. Subject the cells to cell fractionation (centrifuge) and obtain mitochondria.
  2. Grind the cell filter out the mixture and take the debris
  3. Plasmolyse the cells, filter them and take the debris
  4. Select cells which have a large number of mitochondria.

Answer: 4. Select cells which have a large number of mitochondria.

Human Health And Disease MCQ With Answers For NEET

Human Health And Disease MCQ With Answers For NEET

Question 1. The population of Homo sapiens was 453 millions in:

  1. 1550 A.D.
  2. 4000 B.C.
  3. 1650 A.D.
  4. 8000 B.C.

Answer: 3. 1650 A.D.

Question 2. The average annual birth rate per 1000 individuals in developing countries is:

  1. 10
  2. 37
  3. 19
  4. None of the above

Answer: 2. 37

Question 3. The causes of uneven distribution of the world’s population in various regions may be due to the:

  1. Geographical factors
  2. Socio-economic factors
  3. Demographic factors
  4. All of the above factors.

Answer: 4. All of the above factors.

Question 4. Major areas of population concentration in the world are:

  1. South East Asia, Japan, India
  2. European countries
  3. Latin American countries
  4. North America.

Answer: 1. South East Asia, Japan, India

Read and Learn More NEET Biology Multiple Choice Question and Answers

Question 5. The density of a population in a given country is obtained by:

  1. Dividing the total number of persons living in the country by the total land area
  2. Dividing the total number of persons living in the country by the total fertile land area
  3. Dividing the total number of persons living in the country by the total forest land area
  4. Dividing the total number of persons living in the country by the amount of production of natural resources.

Answer: 1. Dividing the total number of persons living in the country by the total land area

Human Health And Disease MCQ With Answers For NEET

Question 6. The population density of the Netherlands is higher than that of India because of:

  1. More land area is there in the Netherlands as compared to India
  2. A greater proportion of the inhabitable area is there in the Netherlands than that in India
  3. Greater economic advancement of the Netherlands
  4. More natural resources in the Netherlands.

Answer: 2. A Greater proportion of the inhabitable area is there in the Netherlands than that in India

Human Health And Disease Mcq For Neet

Question 7. The high population concentration of India is due to the:

  1. The poor economic status of the people of the country
  2. Availability of fertile land
  3. Industrial advancement
  4. Non-availability of resources.

Answer: 1. Poor economic status of the people of the country

Question 8. The very dense population of Indo-Gangetic plains is due to the:

  1. Availability of adequate river water
  2. Fertile alluvial soil of the region
  3. Both of the above factors
  4. Presence of large cities.

Answer: 3. Both of the above factors

Question 9. Some densely populated cities like Durgapur and Bhilai came up recently as a result of:

  1. Removal of forests
  2. Better transport facilities
  3. Better agricultural opportunities
  4. Development of resource-based industries.

Answer: 4. Development of resource-based industries.

Question 10. Most of the world’s largest cities are found at coastal locations primarily due to the:

  1. Pleasant coastal climates
  2. Availability of water
  3. Availability of seafood
  4. The fact that the sea provides a cheaper mode of transport.

Answer: 4. Fact that the sea provides a cheaper mode of transport.

Question 11. Demography is the study of:

  1. Fossils and their distribution
  2. Statistics of population
  3. Relationship between man and the environment
  4. None of the above.

Answer: 2. Statistics of population

Human Health And Disease Mcq For Neet

Question 12. The term biotic potential means:

  1. Distribution of human population in an area
  2. The rate of growth of population in an area
  3. The physiological capacity of an organism to reproduce
  4. The increase in number of human population in a country.

Answer: 3. The physiological capacity of an organism to reproduce

Question 13. The basic cause of continued urban growth is due to the:

  1. Better transport facility
  2. Entertainment facility
  3. Prosperity in cities
  4. Better health facilities.

Answer: 3. Prosperity in cities

Question 14. Increasing urbanization causes:

  1. Overcrowding
  2. Health and pollution hazards
  3. Socio-economic problems
  4. All the above.

Answer: 4. All the above.

Question 15. The biosphere consists of interaction ecological functional units called:

  1. Ecosystems
  2. Populations
  3. Communities
  4. Species.

Answer: 1. Ecosystems

Neet Mcqs On Human Health And Disease With Answers

Question 16. Agriculture and urbanization are two examples of man’s capacity to create new:

  1. Species
  2. Ecosystem
  3. Biosphere
  4. Lithosphere.

Answer: 2. Ecosystem

Question 17. The middle phase of the population growth curve is a phase of:

  1. No growth
  2. Low growth
  3. Maximum growth
  4. Stabilised growth.

Answer: 3. Maximum growth

Question 18. A population can grow exponentially:

  1. When food is the only limiting resource
  2. When first invading a suitable and previously unoccupied habitat
  3. Only if there is no predation
  4. Only in the laboratory.

Answer: 2. When first invading a suitable and previously unoccupied habitat

Question 19. Which of the following does not directly affect biotic potential?

  1. A female’s age of first reproduction
  2. Carrying capacity of the environment
  3. Length of time a female is fertile
  4. Average number of offspring per brood or litter.

Answer: 2. Carrying capacity of the environment

Human Health And Disease Class 12 Mcq

Question 20. The best way to decrease the population of a country is:

  1. To educate the people
  2. To have better living conditions
  3. Mass killing
  4. To practise and implement family planning techniques.

Answer: 4. To practise and implement family planning techniques.

Question 21. The main factors for the growth of the human population in India are:

  1. High birth rate
  2. Less death rate
  3. Lack of education
  4. All of the above.

Answer: 4. All of the above.

Question 22. The prenatal diagnostic technique is known as:

  1. Implantation
  2. Amniocentesis
  3. Parthenogenesis
  4. Biomedical termination of pregnancy.

Answer: 2. Amniocentesis

Question 23. At the current rate of growth, the human population is doubling itself every:

  1. 50 yrs
  2. 25 yrs
  3. 40 yrs
  4. 35 yrs.

Answer: 4. 35 yrs.

Question 24. The carrying capacity is represented by:

  1. K
  2. S
  3. J
  4. I.

Answer: 1. K

Question 25. What is the popular name of IVF?

  1. Amniocentesis
  2. Tubectomy
  3. Rhythm method
  4. Test tube baby.

Answer: 4. Test tube baby.

Human Health And Disease Class 12 Mcq

Question 26. The most thickly populated country in the world is:

  1. Australia
  2. India
  3. Japan
  4. The USA.

Answer: 3. Australia

Question 27. The most thinly populated country in the world is:

  1. Australia
  2. India
  3. Japan
  4. The USA.

Answer: 1. Australia

Question 28. The most thickly populated state of India is:

  1. Orissa
  2. Tamil Nadu
  3. Punjab
  4. Kerala.

Answer: 4. Kerala.

Question 29. The environmental resistance means:

  1. The environmental factors which tend to maintain homeostasis by regulating emigration
  2. Factors imposing a check on population size
  3. Resistance of a species to the environmental factors which impose a check on population size
  4. The physiological capacity of a species to resist changes in the environment.

Answer: 2. Factors imposing a check on population size

Question 30. Fertilisation of the ovum may be prevented by:

  1. Tubal ligation
  2. Vasectomy
  3. Use of IUCD
  4. All of the above.

Answer: 4. All of the above.

Question 31. Which is biologically responsible for the sex of the child?

  1. Father
  2. Mother
  3. Both parents
  4. God.

Answer: 1. Father

Common Human Diseases Mcqs For Neet

Question 32. A contraceptive pill contains:

  1. Progesterone and estrogen
  2. Spermicidal salts
  3. Chemicals that cause abortion
  4. Chemicals that prevent fertilization.

Answer: 1. Progesterone and estrogen

Question 33. According to the 1991 census, human population was:

  1. 689 million
  2. 840 million
  3. 1032 million
  4. 960 million.

Answer: 2. 840 million

Question 34. A contraceptive pill prevents ovulation by:

  1. Blocking fallopian tubes
  2. Inhibiting the release of FSH and LH
  3. Stimulating release of FSH and LH
  4. Causing immediate degeneration.

Answer: 2. Inhibiting release of FSH and LH

Question 35. Which mechanical device to control childbirth is fitted on the cervix?

  1. Diaphragm
  2. Condom
  3. Loop
  4. Copper T.

Answer: 1. Diaphragm

Question 36. Laparoscopy means:

  1. Removal of ovary
  2. Removal of a part of the oviduct
  3. Tubular ligation
  4. Fitting copper T.

Answer: 3. Tubular ligation

Question 37. Mothers nurse the foetus in the womb for:

  1. 180 days
  2. 210 days
  3. 270 days
  4. 320 days.

Answer: 3. 270 days

Question 38. According to the 1991 census, the urban population of India is about:

  1. 30%
  2. 24%
  3. 57%
  4. 34%.

Answer: 2. 24%

Common Human Diseases Mcqs For Neet

Question 39. At present world population is increasing at the rate of:

  1. 2%
  2. 2.25%
  3. 2.50%
  4. 30%.

Answer: 1. 2%

Question 40. The rapid decline in a population due to a high mortality rate is:

  1. Population density
  2. Population crash
  3. Population explosion
  4. All of the above.

Answer: 2. Population crash

Question 41. Growth of the population of an area depends upon:

  1. Natality rate
  2. Immigration
  3. Environmental resistance
  4. All of the above.

Answer: 4. All of the above.

Question 42. The physiological capacity of a species of animals to produce that progeny in the absence of natural enemies, disease or other inhibiting factors is:

  1. Carrying capacity
  2. Biotic potential
  3. Population explosion
  4. All of the above.

Answer: 2. Biotic potential

Question 43. The concept that “population tends to increase geometrically while food supply increases arithmetically” was put forward by:

  1. Thomas Malthus
  2. Adam Smith
  3. Stuart Mill
  4. Charles Darwin.

Answer: 1. Thomas Malthus

Question 44. In India, the human population is heavily weighted towards the younger age groups as a result of:

  1. Short lifespan and low birth rate
  2. Long life-span of many individuals and low birth rate
  3. The short life span of many individuals
  4. Long life span and low birth rate.

Answer: 3. Short life span of many individuals

Question 45. Which mechanical means is used to cover the penis before coital activity?

  1. Diaphragm
  2. Condom
  3. Loop
  4. Copper-T.

Answer: 2. Condom

Common Human Diseases Mcqs For Neet

Question 46. The best way to control the population is:

  1. Education
  2. Family planning
  3. Better living conditions
  4. Better health care.

Answer: 2. Family planning

Question 47. An IUCD is:

  1. Copper-T
  2. Condom
  3. Vasectomy
  4. Pill.

Answer: 1. Copper-T

Question 48. Surgical removal of the testes of males to control the population is:

  1. Castration
  2. Tubectomy
  3. Laparoscopy
  4. Vasectomy.

Answer: 1. Castration

Question 49. A permanent method of birth control is:

  1. Vasectomy
  2. Tubectomy
  3. Both (1) and (2)
  4. None of these.

Answer: 3. Both (1) and (2)

Question 50. Which mechanical device to control childbirth is fitted on the cervix?

  1. Diaphragm
  2. Condom
  3. Loop
  4. Cooper T.

Answer: 1. Diaphragm

Question 51. Saheli, a female antifertility pill is used:

  1. Daily
  2. Weekly
  3. Quarterly
  4. Monthly.

Answer: 2. Weekly

Question 52. Which of the following is a 100% effective method of birth control?

  1. Use of oral contraceptives
  2. Use of I.U.C. Devices
  3. Use of condoms
  4. Medical Termination of Pregnancy.

Answer: 1. Use of oral contraceptives

Question 53. In the past, to control population, the Family Planning Department has been advocating:

  1. Ligation
  2. Salpectomy
  3. Vasectomy
  4. All of the above.

Answer: 4. All of the above.

Question 54. Government-sponsored “Family Planning Programme” started in:

  1. 1947
  2. 1950
  3. 1951
  4. 1955.

Answer: 3. 1951

Question 55. Laparoscopy means:

  1. Removal of ovary
  2. Removal of a part of the oviduct
  3. Tubular ligation
  4. Fitting copper T.

Answer: 3. Tubular ligation

Question 56. The chemical method of birth control involves the use of:

  1. Condom
  2. Loop
  3. Cream or jelly
  4. Diaphragm.

Answer: 3. Cream or jelly

Human Health And Disease Mcq For Neet

Question 57. A contraceptive can be:

  1. Condom, cervical cap or diaphragm
  2. Intrauterine device
  3. Pill
  4. All the above.

Answer: 4. All the above.

Question 58. Which of the following is a mechanical device of birth control?

  1. Copper-T
  2. A combined pill
  3. Foam tablet
  4. Abortion pill.

Answer: 1. Copper-T

Question 59. Fertilisation of the ovum may be prevented by:

  1. Tubal ligation
  2. Vasectomy
  3. Use of IUCD
  4. All of these.

Answer: 4. All of these.

Question 60. A sterilization technique is:

  1. Loop
  2. Diaphragm
  3. Tubectomy
  4. Cervical cap.

Answer: 4. Cervical cap

Question 61. According to the 1991 census, the urban population of India was about:

  1. 30%
  2. 24%
  3. 57%
  4. 34%.

Answer: 2. 24%

NEET Questions Human Health and Diseases Question 62. In 1991, the Indian population was:

  1. 832.93 million
  2. 843.93 million
  3. 840.90 million
  4. 830.90 million.

Answer: 2. 843.93 million

Question 63. The 1991 census of population in India indicates:

  1. Sudden fall in the birth rate
  2. Minor fall in birth rate
  3. No fall in birth rate
  4. Increased birth rate.

Answer: 2. Minor fall in birth rate

Human Health And Disease Mcq For Neet

Question 64. In India, the marriageable age for females is:

  1. 15 years
  2. 18 years
  3. 20 years
  4. 21 years.

Answer: 2. 18 years

Question 65. Which of the following is involved in test-tube baby production?

  1. Laparoscopy
  2. Catheter
  3. In-vitro fertilization
  4. All of these.

Answer: 4. All of these.

Question 66. Amniocentesis can reveal the foetus’s:

  1. Chromosomal abnormalities
  2. Physical deformities
  3. Metabolic disorders
  4. Only (1) and (3).

Answer: 4. Only (1) and (3).

Question 67. In amniocentesis:

  1. The foetal cells are taken out, cultured and examined for metabolic defects
  2. The foetus is examined for metabolic defects
  3. The foetus is examined for sex
  4. The amniotic fluid is examined for metabolic defects.

Answer: 1. The foetus is examined for metabolic defects

Question 68. Which of the following is a pre-natal diagnostic technique?

  1. X-ray technique
  2. IUCD
  3. Tubectomy
  4. Amniocentesis.

Answer: 4. Amniocentesis.

Question 69. Test-tube baby is the one:

  1. Who is reared on artificial medium outside the womb
  2. Whose early growth is inside the female body but later growth on artificial medium
  3. Whose fertilization and early growth are on an artificial medium but later implantation in the female uterus
  4. Whose growth is inside the fallopian tube instead of the uterus.

Answer: 3. Whose fertilization and early growth is on an artificial medium but later implantation in the female uterus

Question 70. Pre-natal defects in the foetus can be detected by:

  1. Laparoscopy
  2. Amniocentesis
  3. Genetic engineering
  4. Sonography.

Answer: 2. Amniocentesis

 

Human Health And Disease Class 12 Multiple Choice Questions

NEET Biology Human Health And  Common Human Diseases Multiple Choice Questions And Answers

Question 1. Common examples of allergens are mites in dust, pollens, and animal dander. Allergy is due to the release of chemicals such as:

  1. IgF
  2. Histamine
  3. Colostrum
  4. Histamine and serotonin

Answer: 4. Histamine and serotonin

Question 2. Which of the following is an autoimmune disease?

  1. Gout
  2. Rheumatoid arthritis
  3. Diabetes inspires
  4. SCID.

Answer: 2. Rheumatoid arthritis

Question 3. BCG vaccine is given against:

  1. Typhoid
  2. Cholera
  3. TB
  4. Diphtheria.

Answer: 3. Diphtheria.

Question 4. Which of the following is a symptom(s) of ascariasis?

  1. Muscular pain and fever
  2. Internal bleeding and anaemia
  3. Blockage of intestinal passage
  4. All the above.

Answer: 4. All the above.

Read and Learn More NEET Biology Multiple Choice Question and Answers

Question 5. The appearance of dry, scaly lesions on various parts of the body such as skin, nails and scalp accompanied by intense itching. This disease is caused by:

  1. Epidermophyton
  2. Microsporum
  3. Trichophyton
  4. All the above.

Answer: 4. All the above.

Human Health And Disease Class 12 MCQs

Human Health and Disease MCQs with Answers Question 6. Elephantiasis or filariasis is caused by Wuchereria bancrofti and W. malayi. The major symptoms are

  1. Chronic inflammation of lymphatic vessels of lower limbs
  2. Deformities of genital organs
  3. Swelling of scrotum
  4. All the above.

Answer: 4. All the above.

Human Health And Disease Mcq For Neet

Question 7. Sporozoites of malarial parasite on entering the blood first attack:

  1. RBCs
  2. Liver cells
  3. Blood platelets
  4. WBCs

Answer: 2. Liver cells

Question 8. Who is the initiator of the ‘Lab to Land’ concept?

  1. M.S. Swaminathan
  2. Norman Borlaug
  3. G.S. Khush
  4. G.S. Randhawa.

Answer: 1. M.S. Swaminathan

Question 9. In pneumonia, symptoms include fever, cough, chills, and headache, and lips and fingers may turn grey to blue colour. It is caused by

  1. Streptococcus pneumonia
  2. Haemophilus influenza
  3. Aedes
  4. Both (1) and (2).

Answer: 4. Both (1) and (2).

Question 10. The proteins produced by B-lymphocytes in response to pathogens are called

  1. Antigens
  2. Interferons
  3. Antibodies
  4. PMNL.

Answer: 3. PMNL.

Question 11. Japenese elephantiasis is transmitted by:

  1. Housefly
  2. Tse-tse fly
  3. Phlebotomus
  4. Mosquito.

Answer: 4. Mosquito

Question 12. Select the correct statement:

  1. Barbiturates when given to criminals make them tell the truth
  2. Morphine is Olien given to persons who have undergone surgery as a painkiller
  3. Chewing tobacco lowers blood pressure and heart rate
  4. Cocaine is given to patients who have undergone surgery and recovering slowly.

Answer: 2. Morphine is Olien given to persons who have undergone surgery as a pain killer

Question 13. A patient is suspected to be suffering from acquired immune deficiency syndrome. Which diagnostic technique will you recommend for its detection?

  1. ELISA
  2. MRI
  3. Ultrasound
  4. Widal

Answer: 1. ELISA

Human Health And Disease Mcq For Neet

Question 14. The side effects of the use of anabolic steroids in females are

  1. Aggressiveness
  2. Masculinisation
  3. Enlargement of clitoris and deepening of voice
  4. All the above

Answer: 4. All the above
.
Question 15. At what stage does HIV infection usually show symptoms of AIDS

  1. When the infecting retrovirus enters host cells
  2. When viral DNA is produced by reverse transcriptase
  3. Within 15 days of sexual contact with an infected person
  4. When HIV replicates rapidly in the helper T- lymphocytes and damages a large number of these.

Answer: 4. When HIV replicates rapidly in the helper T-lymphocytes and damages a large number of these.

Question 16. Antigens are:

  1. The micro-organisms which are the source of disease in the body
  2. A foreign body which is harmful to the animal and evokes the generation of antibodies
  3. The substance generated in the body in response to the infection
  4. None of these.

Answer: 2. A foreign body which is harmful to the animal and evokes the generation of antibodies

Question 17. Koch’s postulates include which of the following?

  1. The organism must be regularly found in the body of the patient
  2. Must be isolated and grown in an artificial medium
  3. When the culture is inoculated into the healthy person it must cause disease and can be recovered again
  4. All the above.

Answer: 4. All the above.

Question 18. Reservoir of infection is:

  1. Site where pathogens reside without causing any damage
  2. Soil, water and air
  3. Another animal
  4. Another person who is suffering.

Answer: 1. Site where pathogens reside without causing any damage

Human Health And Disease Class 12 Mcq

Question 19. Antibodies fight against:

  1. Starvation
  2. Stress
  3. Thirst
  4. Infection.

Answer: 4. Infection.

Human Health and Disease NEET Questions Question 20. The humoral immune system consists of:

  1. A family of diverse proteins present in body fluids
  2. Some special types of cells destroy the pathogens
  3. Both cells as well as polysaccharides
  4. All the above.

Answer: 1. A family of diverse proteins present in body fluids

Question 21. How many principal lines of defence are present in the body?

  1. Two
  2. Three
  3. Five
  4. Innumerable.

Answer: 2. Three

Question 22. Which of the following is a correct statement?

  1. B-cells directly engulf the pathogenic bacteria
  2. B-cells produce antibodies soon after they are produced
  3. B-cells produce a large clone of plasma cells soon after it is formed
  4. The B-cells produce the plasma cells in the body only after they are triggered by a specific antigen.

Answer: 4. The B-cells produce the plasma cells in the body only after they are triggered by a specific antigen.

Question 23. Antiserum is a serum containing:

  1. Antigens
  2. Leucocytes
  3. Active antibodies
  4. None of the above.

Answer: 3. Active antibodies

Question 24. Interferon is a glycoprotein which possesses:

  1. Antiviral activity
  2. Antifungal activity
  3. Antiparasitic activity
  4. Antibacterial activity.

Answer: 1. Antiviral activity

Neet Mcqs On Human Health And Disease With Answers

Question 25. Antibodies are:

  1. A large family of protein molecules produced by the body’s defence cells in the body fluids neutralise the antigens
  2. The chemicals produced by the invading microbes destroy and damage the body’s cells
  3. Certain substances enclosed in lymphocytes
  4. None of the above.

Answer: 1. A large family of protein molecules produced by the body’s defence cells in the body fluids which neutralise the antigens

Question 26. The mode of transmission of communicable diseases is dealt by a branch of science named:

  1. Epidemiology
  2. Immunology
  3. Aetiology
  4. Angiology.

Answer: 1. Epidemiology

Question 27. The degree of pathogenicity is called:

  1. Infestation
  2. Infection
  3. Virulence
  4. Resistance.

Answer: 3. Virulence

Question 28. Which one of the following diseases is caused by bacteria?

  1. Chicken-pox
  2. Poliomyelitis
  3. Measles
  4. Tetanus.

Answer: 4. Tetanus.

Question 29. Which one of the following communicable diseases is not caused by bacteria?

  1. Diphtheria
  2. Typhoid
  3. Leprosy
  4. Poliomyelitis.

Answer: 4. Poliomyelitis.

Question 30. The causative organism of cholera is a:

  1. Bacterium
  2. Protozoan
  3. Nematode
  4. Virus.

Answer: 1. Bacterium

Neet Mcqs On Human Health And Disease With Answers

Question 31. Tetanus is caused by:

  1. Bacterium
  2. Fungus
  3. Protozoan
  4. Virus.

Answer: 1. Bacterium

Question 32. Poliomyelitis is caused by

  1. Bacteria
  2. Virus
  3. Protozoan
  4. Nematodes.

Answer: 2. Virus

Question 33. AIDS is caused by:

  1. Cocci
  2. Bacilli
  3. TMV
  4. HIV.

Answer: 4. HIV.

Question 34. Invention and study of the effects of medicines on the organism is known as:

  1. Toxicology
  2. Pharmacology
  3. Pharmacy
  4. Haematology.

Answer: 2. Pharmacology

Question 35. DPT vaccine is given to infants to immunize them against:

  1. Diphtheria, pneumonia and typhoid
  2. Diphtheria, whooping cough and tetanus
  3. Diarrhoea, pneumonia and tuberculosis
  4. Diphtheria, whooping cough and typhoid.

Answer: 2. Diphtheria, whooping cough and tetanus

Question 36. Dengue fever is caused by:

  1. Bacteria
  2. Plasmodium
  3. Virus
  4. Entamoeba histolytica.

Answer: 3. Virus

Question 37. Vims cause contagious epidemic disease with high fever and a rash all over the body. Its incidence is among children. It’s one attack that gives immunity. Which one is of the following?

  1. Mumps
  2. Plague
  3. Brain fever
  4. Measles.

Answer: 4. Measles.

Question 38. Syphilis is a venereal disease. It is caused by:

  1. Neisseria
  2. Vibrio
  3. Corynebacterium
  4. Treponema pallidum.

Answer: 4. Treponema pallidum.

MCQs on Human Health and Diseases Question 39. The contagious diseases are:

  1. Measles
  2. Chickenpox
  3. Whooping cough
  4. All the above.

Answer: 4. All the above.

Common Human Diseases Mcqs For Neet

Question 40. Where are the gametocytes of Plasmodium first formed and found?

  1. Liver of man
  2. Stomach of female mosquito
  3. Blood of man
  4. RBC of the blood of man.

Answer: 4. RBC of the blood of man.

Question 41. Entamoeba histolytica has:

  1. Well developed pseudopodia
  2. Contractile vacuole
  3. Both (1) and (2)
  4. None of the above.

Answer: 4. None of the above

Question 42. Which mosquito actually transmits malaria and acts as an intermediate host of Plasmodium?

  1. Male Anopheles
  2. Female Anopheles
  3. Male Culex
  4. Female Culex.

Answer: 2. Female Anopheles

MCQs on Human Health and Diseases Question 43. The credit of working out the complicated life cycle of Plasmodium goes to:

  1. Louis Pasteur
  2. John Snow
  3. Robert Koch
  4. Ronald Ross.

Answer: 4. Ronald Ross.

Question 44. The symptoms of Malaria fever appear at their peak in a patient when:

  1. Sporozoites enter liver
  2. Merozoites enter red blood cells
  3. Red blood cells rupture and haemozoin is released
  4. Gametocytes are formed.

Answer: 3. Red blood cells rupture and haemozoin is released

Question 45. Which of the following worms is viviparous?

  1. Wuchereria bancrofti
  2. Ancylostoma dudoenale
  3. Ascaris lumbricodes
  4. Taenia solium.

Answer: 1. Wuchereria bancrofti

Question 46. The infective stage of plasmodium is:

  1. Trophozoite
  2. Sporozoite
  3. Merozoite
  4. Schizont.

Answer: 2. Sporozoite

Question 47. A chronic contagious eye disease, caused by a virus is called:

  1. Thrombosis
  2. Myopia
  3. Conjunctivitis
  4. Night blindness.

Answer: 3. Conjunctivitis

Question 48. The region of the body where the poliomyelitis virus multiplies is:

  1. Nerve cells
  2. Muscle cells
  3. Intestinal cells
  4. None of the above.

Answer: 1. Nerve cells

Question 49. The disease Tilariasis’ is caused by the worm:

  1. Wuchereria bancrofti
  2. Ancylostoma duodenale
  3. Trichinella spiralis
  4. Enterobius vermicularis.

Answer: 1. Wuchereria bancrofti

Common Human Diseases Mcqs For Neet

Question 50. The mode of transmission of the disease Filariasis is:

  1. Bite of mosquito
  2. Eating unwashed eatables
  3. Eating unripe Pork
  4. Both (2) and (3).

Answer: 1. Bite of mosquito

Question 51. Which mosquito aids in the transmission of the disease filariasis?

  1. Male Anopheles
  2. Female Anopheles
  3. Culex
  4. Both (1) and (2).

Answer: 3. Culex

Question 52. A disease characterised by chronic sleeplessness is:

  1. Insomnia
  2. Jaundice
  3. Sleeping sickness
  4. Nervous breakdown.

Answer: 1. Insomnia

Question 53. Trachoma is caused by the infection of:

  1. Virus
  2. Fungus
  3. Nematode
  4. Bacterium.

Answer: 1. Virus

Question 54. Chickenpox can be easily identified from measles due to the:

  1. High fever
  2. Irritation all over the skin
  3. Dew drop-like rashes
  4. Sneezing and water discharge from the nose.

Answer: 3. Dew drop-like rashes

Question 55. Varicella virus causes:

  1. Smallpox
  2. Chickenpox
  3. Measles
  4. Influenza

Answer: 2. Chickenpox

Question 56. Elephantiasis is caused by:

  1. Tapeworm
  2. Wuchereria
  3. Ascaris
  4. Culex.

Answer: 2. Wuchereria

Question 57. The incubation period of smallpox is:

  1. 2 days
  2. 12 days
  3. 12 hours
  4. 2 to 12 days.

Answer: 2. 12 days

Question 58. The infective period of enteric fever is:

  1. 6 hours
  2. 6 days
  3. 6 weeks
  4. 6 minutes.

Answer: 2. 6 days

Common Human Diseases Mcqs For Neet

Question 59. Protection against poliomyelitis and tetanus is done simultaneously by:

  1. Sulpha drugs
  2. Gamma globulin inoculation
  3. Multiple vaccines
  4. Pasteur treatment.

Answer: 3. Multiple vaccine

Question 60. After floods, the victims are usually attacked by:

  1. Appendicitis
  2. Peritonitis
  3. Rabies
  4. Cholera.

Answer: 4. Cholera.

 

Morphology Of Flowering Plants MCQs For NEET Biology

NEET Biology Inflorescence And Flower Multiple Choice Questions And Answers

Question 1. If a raceme inflorescence is branched, it is called :

  1. Umbel
  2. Panicle
  3. Head
  4. Cymose.

Answer: 2. Panicle

Question 2. The arrangement of flowers in a raceme is :

  1. Basipetal
  2. Acropetal
  3. Head
  4. Cymose.

Answer: 2. Acropetal

Question 3. A raceme of sessile flowers is termed :

  1. Catkin
  2. Hypanthodium
  3. Spike
  4. Umbel.

Answer: 3. Spike

Morphology Of Flowering Plants Mcq For Neet

Question 4. Multiparous cyme is the characteristic of :

  1. Calotropis
  2. Acacia
  3. Begonia
  4. Bignonia.

Answer: 1. Calotropis

Read and Learn More NEET Biology Multiple Choice Question and Answers

Morphology of Flowering Plants NEET Questions Question 5. ln Mimosa pudica, the inflorescence is :

  1. Raceme
  2. Cymose head
  3. Spike
  4. Umbel.

Answer: 2. Cymose head

NEET Biology MCQs Morphology of Flowering Plants

Question 6. Involucre forms the cup in the inflorescence of :

  1. Fig
  2. Salvia
  3. Sunflower
  4. Poinsettia.

Answer: 4. Poinsettia.

Question 7. Zig-development of the inflorescence axis is an example of:

  1. Helicoid cyme
  2. Verticillasrer
  3. Umbel
  4. Scorpioid.

Answer: 1. Helicoid cyme

Question 8. Considering the angiosperm flower :

  1. Anemophilous are more advanced than regular flowers
  2. Irregular flowers are more primitive than regular flowers
  3. A solitary axillary or solitary terminal flower is more primitive than the inflorescence, likewise, capitulum and umbel are the most advanced forms of inflorescence.
  4. An inflorescence is more primitive than a solitary axillary or solitary terminal flower and the umbel is more primitive than a spike.

Answer: 3. A solitary axillary or solitary terminal flower is more primitive than the inflorescence, likewise capitulum and umbel are the most advanced forms of inflorescence.

Question 9. In Musaceae, the inflorescence is :

  1. Spike
  2. Head
  3. Capitulum
  4. Spadix.

Answer: 4. Spadix.

Question 10. Ovule of Opuntia is coiled and called:

  1. Anatropous
  2. Circinotropous
  3. Hemitropous
  4. Amphitropous.

Answer: 2. Circinotropous

Morphology Of Flowering Plants Mcq For Neet

Question 11. An inflorescence in which flowers arise from different levels but reach the same level is called :

  1. Catkin
  2. Umbel
  3. Corymb
  4. Spadix.

Answer: 3. Corymb

Question 12. Cauliflory is :

  1. Formation of flowers in clusters
  2. Production of flowers on young branches
  3. Production of flowers on old stem from new buds
  4. Formation of plants from epiphyllous buds.

Answer: 3. Production of flowers on old stem from new buds

Question 13. Feathery stigma is present in :

  1. Wheat
  2. Pea
  3. Ceasalpinia
  4. Darura.

Answer: 1. Wheat

Question 14. The inflorescence in candytuft is :

  1. Raceme
  2. Corymb
  3. Cyme
  4. Umbel.

Answer: 2. Corymb

Question 15. Hypanthodium is a characteristic inflorescence of:

  1. Ficus
  2. Pineapple
  3. Mulberry
  4. Poinsettia.

Answer: 1. Ficus

Morphology Of Flowering Plants Mcq For Neet

Question 16. In onion, the inflorescence is :

  1. Umbellate cyme
  2. Catkin
  3. Raceme
  4. Corymb.

Answer: 1. Umbellate cyme

Question 17. In a compound umbel, each umbellet is subtended by :

  1. Involucre
  2. Ramenta
  3. Involucral
  4. Bracteole.

Answer: 3. Involucral

Question 18. The inflorescence of Acacia is to be distinguished as a:

  1. Spike
  2. Spikelet
  3. Cymose head
  4. Raceme.

Answer: 3. Cymose head

Question 19. The peduncle is :

  1. Floral axis
  2. Inflorescence axis
  3. Thalamus
  4. Bract.

Answer: 2. Inflorescence axis

Question 20. Inflorescence with a female flower in the middle and male flowers all around surrounded by a cup-like structure is known as :

  1. Catkin
  2. Cyathium
  3. Verticillaster
  4. Capitulum.

Answer: 2. Cyathium

Neet Mcqs On Morphology Of Flowering Plants

Question 21. A brightly colored bract-like covering associated with the banana the inflorescence is called :

  1. Spathe
  2. Scape
  3. Spiral
  4. Scapigeron.

Answer: 1. Spathe

Question 22. Inflorescence is :

  1. Number of flowers present on an axis
  2. Arrangement of flowers on an axis
  3. Method of the opening of flowers
  4. Type of flowers bome on the peduncle.

Answer: 2. Arrangement of flowers on an axis

Question 23. In monocots male gametophyte is :

  1. Megaspore
  2. Nucellus
  3. Microspore
  4. Tetrad.

Answer: 3. Microspore

Question 24. Inflorescence of mulberry is :

  1. Catkin
  2. Raceme
  3. Spadix
  4. Capitulum.

Answer: 1. Catkin

Question 25. A catkin of unisexual flowers is found in :

  1. Mulberry
  2. Wheat
  3. Onion
  4. Fig.

Answer: 1. Mulbeny

Question 26. The inflorescence of wheat is :

  1. Spike
  2. Spikelet
  3. Spike of spikelets
  4. Panicle of spikelets.

Answer: 3. Spike of spikelets

Question 27. Flower is a :

  1. Modified cone
  2. Modified spike
  3. Modified branch system
  4. Modified reproductive shoot.

Answer: 4. Modified reproductive shoot.

Morphology Of Plants Mcqs For Neet With Answers

Question 28. Flowers are always present in :

  1. Cryptogams
  2. Pteridophytes
  3. Angiosperms
  4. Bryophytes.

Answer: 3. Angiosperms

Question 29. The floral formula represents :

  1. Number and arrangement of floral parts
  2. Number of flowers in an inflorescence
  3. Type of flowers in a family
  4. None of the above.

Answer: 1. Number and arrangement of floral parts

Question 30. Flowers devoid of sepals and petals are called as :

  1. Florets
  2. Monothecous
  3. Achlamydeous
  4. None of the above.

Answer: 3. Achlamydeous

Question 31. Unisexual flowers are also known as :

  1. Diclinous
  2. Uniparous
  3. Unitemic
  4. None of the above.

Answer: 1. Diclinous

Question 32. In the case of the superior ovary, the thalamus is :

  1. Superior
  2. Epigynous
  3. Hypogynous
  4. None of the above.

Answer: 3. Hypogynous

Morphology Of Plants Mcqs For Neet With Answers

Question 33. The arrangement of sepals and petals in a bud condition is also called :

  1. Inflorescence
  2. Aestivation
  3. Venation
  4. Placentation.

Answer: 2. Aestivation

Question 34. Which type of inflorescence occurs in Ficus?

  1. Verticillaster
  2. Hypanthodium
  3. Cymose
  4. Racemose.

Answer: 2. Hypanthodium

Question 35. Spike with unisexual flowers or catkin occurs in :

  1. Mulberry
  2. Grass
  3. Wheat
  4. Callistemon.

Answer: 1. Mulberry

Question 36. An edible inflorescence is :

  1. Raphanus sativus
  2. Brassica oleracea
  3. Brassica rapa
  4. Mustard.

Answer: 2. Brassica oleracea

Question 37. The smallest flowering plant is :

  1. Woffia
  2. Polyalthia
  3. Rffiesia
  4. Mimosa.

Answer: 1. Woffia

Morphology Of Plants Mcqs For Neet With Answers

Question 38. A bi-or tricarpellary syncarpous unilocular ovary having one ovule at the base represents the placentation of the type :

  1. Parietal
  2. Marginal
  3. Free central
  4. Basal.

Answer: 4. Basal.

Question 39. Umbel inflorescence occurs in :

  1. Coriandrum
  2. Colocasia
  3. Musa
  4. Sunflower.

Answer: 1. Coriandrum

Question 40. A plant is termed monoecious if it bears :

  1. Both male and female flowers
  2. Either male or female flowers
  3. Male, female, and bisexual flowers
  4. Male, female, and neutral flowers.

Answer: 1. Both male and female flowers

Question 41. Monadelphous stamens occur in :

  1. Lady’s Finger
  2. Hibiscus
  3. Gossypium
  4. All of the above

Answer: 4. All of the above

Question 42. From the life cycle point of view, the most important part of a plant is :

  1. Flower
  2. Leaf
  3. Stem
  4. Root.

Answer: 1. Flower

Previous Year Neet Questions On Plant Morphology

Question 43. The ovule is attached to the placenta by :

  1. Petiole
  2. Pedicel
  3. Funiculus
  4. Hilum.

Answer: 3. Funiculus

Morphology of Flowering Plants NEET Questions Question 44. In a flower the placenta is a tissue :

  1. In the corolla tube where filaments are attached
  2. In other lobes where pollens are attached
  3. In the ovary where the ovules are attached
  4. On the thalamus where floral whorls are attached.

Answer: 3. In the ovary where the ovules are attached

Question 45. Which of the following has male and female flowers on different plants :

  1. Ranunculus
  2. Carrica papaya
  3. Caesalpinia
  4. Cotton.

Answer: 2. Carrica papaya

Question 46. The term tetradynamous is applied when there are :

  1. 6-Stamens-2 long and 4 shorl
  2. 4 Stamens-2 long and 2 short
  3. 6 Stamens-2 short in the outer whorl and 4 long in the inner whorl
  4. 6 Stamens-2 short and 4 long

Answer: 3. 6 Stamens-2 short in the outer whorl and 4 long in the inner whorl

Question 47. The vexillum, wings, and keel in pea flowers constitute :

  1. Calyx
  2. Corolla
  3. Androecium
  4. Gynaecium.

Answer: 2. Corolla

Question 48. Staminodes are found in :

  1. Malvaceae
  2. Liliaceae
  3. Caesalpinoideae
  4. Mimosoideae.

Answer: 3. Caesalpinoideae

Question 49. A monoecious anther is :

  1. A sterile stamen
  2. A stamen with two lobes
  3. Another with one lobe
  4. Fused in all parts.

Answer: 3. Anther with one lobe

Previous Year Neet Questions On Plant Morphology

Question 50. A stalk-bearing androecium and gynoecium are called :

  1. Anthropocene
  2. Andropore
  3. Sporangiophore
  4. Gynandrophore.

Answer: 4. Gynandrophore.

Question 51. What is the technical term used for a sterile stamen?

  1. Spur
  2. Staminode
  3. Stallion
  4. Staminate.

Answer: 2. Staminode

Question 52. Glumes are modified :

  1. Leaves
  2. Bracts
  3. Calyx
  4. None of the above.

Answer: 2. Bracts

Question 53. Anemophilous Plants have :

  1. Small petals and stick pollen
  2. No petals and light pollen
  3. Colored petals and large pollen
  4. Colored petals and heavy pollen.

Answer: 2. No petals and light pollen

Question 54. Diadelphous condition is present on :

  1. Citrus
  2. Bombyx
  3. Pisum
  4. Brassica.

Answer: 3. Pisum

Important Neet Questions On Plant Morphology

Question 55. Number of female flowers in a cyathium is :

  1. 1
  2. 2
  3. 3
  4. Several.

Answer: 1. 1

Question 56. Cleistogamous flowers are found in :

  1. Ficus bengalensis
  2. Commelina benghalensis
  3. Adina portfolio
  4. Anthoc ephalus cadamba.

Answer: 2. Commelina benghalensis

Question 57. The inflorescence in the family Compositae is :

  1. Capitulum
  2. Spadix
  3. Umbel
  4. Catkin.

Answer: 1. Capitulum

Question 58. Superficial placentation is seen in :

  1. Cosmos
  2. Calotropis
  3. Nymphaea
  4. Brassica.

Answer: 3. Nymphaea

Question 59. Spadix inflorescence occurs in :

  1. Mulberry
  2. Banana
  3. Coriander
  4. Delonix.

Answer: 2. Banana

Important Neet Questions On Plant Morphology

Question 60. The ovule is attached to the funiculus at the point called :

  1. Pedicel
  2. Petiole
  3. Anthropocene
  4. Hilum.

Answer: 4. Hilum.

Question 61. When stamens are adnate to perianth leaves it is known AS:

  1. Episepalous
  2. Epipetalous
  3. Gynandrous
  4. Epiphyllous.

Answer: 4. Epiphyllous.

Question 62. The longest stigma is found in :

  1. Zea mays
  2. Dioscorea
  3. Date palm
  4. Bamboo.

Answer: 1. Zea mays

Question 63. A flower is said to be actinomorphic if it can be divided in two :

  1. Similar halves by a single vertical section.
  2. Exactly equal halves by any vertical section through the center
  3. Halves having sepals and petals in equal numbers
  4. Both ‘A’ and ‘C’.

Answer: 2. Exactly equal halves by any vertical section through the center

Question 64. Perianth is found in a flower in which :

  1. Calyx and corolla are not distinguishable
  2. Stamens are leaf-like
  3. Corolla is leaf-like but calyx is coloured
  4. None of the above.

Answer: 1. Corolla is leaf-like but calyx is coloured

Important Neet Questions On Plant Morphology

Question 65. Hypanthodium is :

  1. Thalamus
  2. Fruit
  3. Inflorescence
  4. Ovary.

Answer: 3. Inflorescence

Question 66. Persistent calyx forms a dry bladder-like enclosing edible berry in :

  1. Nicotiana
  2. Solanum
  3. Physalis
  4. Capsicum.

Answer: 3. Physalis

Question 67. The colored structures associated with the flowers of Poinsettia (dogwood) are :

  1. Petals
  2. Bracts
  3. Perianth
  4. Carpels.

Answer: 2. Bracts

Question 68. A bisexual flower that never opens in its lifespan is called:

  1. Heterogamous
  2. Homogamous
  3. Cleistogamous
  4. Dichogamous.

Answer: 3. Cleistogamous

Question 69. Hypanthodium inflorescence is found in :

  1. Coriander
  2. Sunflower
  3. Cauliflower
  4. Fig.

Answer: 4. Fig.

Question 70. Stamens with free anthers but filaments fused into several groups are:

  1. Polyadelphous
  2. Diadelphous
  3. Monadelphous
  4. Syngenesious

Answer: 1. Polyadelphous

Question 71. In the flowering plants, angiosperms, an ovule represents:

  1. Megasporophyll
  2. Megasporangium
  3. A megaspore
  4. A megaspore mother cell.

Answer: 2. Megasporangium

Morphology of Flowering Plants MCQ With Answers Question 72. An orthotropous ovule is one in which the micropyle and chalazaarc’.

  1. Oblique of funiculus
  2. At the right angle to the funiculus
  3. Parallel to funiculus
  4. In the straight line of funiculus.

Answer: 4. In the straight line of funiculus.

Question 73. Pappus is a modification of :

  1. Calyx
  2. Corolla
  3. Stamens
  4. Gynoecium.

Answer: 1. Calyx

Question 74. Gynandrophore is found in:

  1. Malverstrum
  2. Brassica campestris
  3. Gynadropsis
  4. Allium cepa.

Answer: 3. Gynadropsis

Question 75. Diadelphous slamens occur in :

  1. Gramineae
  2. Cucurbitaceae
  3. Papilionatae
  4. Malvaceae.

Answer: 4. Malvaceae.

Question 76. Synandrous refers to the fusion of:

  1. Filaments only
  2. Anthers only
  3. Filaments and anthers
  4. Anthers and gynoecium.

Answer: 3. Filaments and anthers

Question 77. In synanthropic condition :

  1. Anthers of a flower are fused but the filaments are free
  2. Filaments of androecium are used but anthers are free
  3. Filaments and anthers are fused
  4. Anthers filaments and gynoecium are fused.

Answer: 1. Anthers of a flower are fused but the filaments are free

Question 78. In a flowering plant the largest number of haploid cells occur in :

  1. Ovule
  2. Microsporangia
  3. Root tip
  4. Cambium.

Answer: 2. Microsporangia

Question 79. Which of the following is a polycarpic plant?

  1. Pea
  2. Agave
  3. Pear
  4. Bamboo.
  5. Agave

Answer: 3. Bamboo.

Question 80. Syngenesious condition is found in :

  1. Acacia
  2. Peruniu
  3. Sunflower
  4. Hibiscus.

Answer: 3. Sunflower

Enhancement In Food Production MCQ For NEET Biology

Enhancement In Food Production MCQ For NEET Biology

Question 1. Maximum contrilnilion to the total milk production of our country comics from:

  1. Cows
  2. Buffaloes
  3. Camels
  4. Goat.

Answer: 2. Buffaloes

Question 2. Murrah is a breed of:

  1. Cow
  2. Sheep
  3. Buffaloes
  4. Goat

Answer: 3. Buffaloes

Question 3. Lac is a:

  1. Plant product
  2. Mineral product
  3. Synthetic product
  4. Animal product.

Answer: 4. Animal product.

Question 4. Aquaculture includes:

  1. Freshwater fishing
  2. Brackish water fishes
  3. Marine fishery
  4. All of the above.

Answer: 4. All of the above.

Read and Learn More NEET Biology Multiple Choice Question and Answers

Question 5. Which of the following species is specially domesticated and reared for high economic importance?

  1. Apis indica
  2. Apis mellifera
  3. Apis dorsata
  4. Apis florea.

Answer: 1. Apis Indica

Enhancement In Food Production MCQ For NEET Biology

Question 6. Cryopreservation is:

  1. Preservation of living beings in chemicals
  2. Preservation at very low temperature
  3. Preservation through exposure to irradiation
  4. Preservation at high temperature.

Answer: 2. Preservation at very low temperature

Enhancement In Food Production Mcq For Neet

Question 7. Cryopreservation is useful for:

  1. Preservation of semen
  2. Very young fetuses
  3. Living cells and body parts
  4. All the above.

Answer: 4. All the above.

Question 8. Exotic breeds:

  1. Require specific environment
  2. Hardy and high-yielding
  3. Are sturdy
  4. Take less food.

Answer: 1. Require specific environment

Question 9. Exotic breeds are:

  1. Used for cross-breeding
  2. Allowed to multiply and replace local breeds
  3. Easy to manage
  4. Resistant to local pests and pathogens.

Answer: 1. Used for cross-breeding

Question 10. Infertility of local breeds of cattle can be overcome by the use of:

  1. Cross-breeding with exotic breeds
  2. Good nourishment
  3. Stilbesterol
  4. Gonadotropin.

Answer: 4. Gonadotropin.

Question 11. Stilbesterol is used for:

  1. Induction of lactation
  2. Artificial insemination
  3. Super-ovulation
  4. Cryopreservation.

Answer: 1. Induction of lactation

Question 12. A surrogate mother is:

  1. Mother without lactation
  2. Future mother with embryo implanted from another
  3. Carrying several embryos at one time
  4. Artificially inseminated female

Answer: 2. Future mother with embryo implanted from another

Enhancement In Food Production Mcq For Neet

Question 13. Artificial insemination is better than natural insemination in cattle because

  1. Semen of good bulls can be provided everywhere
  2. There is no likelihood of contagious diseases
  3. It is economical
  4. All the above.

Answer: 4. It is economical

Enhancement of Food Production MCQs Question 14. A milch breed of cow is:

  1. Haryana
  2. Malvi
  3. Kankrcj
  4. Hallikcr.

Answer: 1. Haryana

Question 15. A draught breed of cattle is:

  1. Red Sindhi
  2. Gir
  3. Malvi
  4. Haryana.

Answer: 3. Malvi

Question 16. An exotic breed of cow is:

  1. Ongolc
  2. Friesian
  3. Hallikcr
  4. Deoni.

Answer: 2. Friesian

Question 17. Hybrid breed of cattle is:

  1. Sunandini
  2. Holstein
  3. Brown Swiss
  4. Kankrcj.

Answer: 1. Sunandini

Neet Biology Food Production Mcqs

Question 18. The gestation period for buffalo is:

  1. 9 months
  2. 14 months
  3. 10 months
  4. 21-22 months.

Answer: 3. 10 months

Question 19. Cows and buffaloes remain in heat for:

  1. 24-36 hours
  2. 36-48 days
  3. 7-10 days
  4. 15-20 days.

Answer: 1. 24-36 hours

Enhancement of Food Production MCQs Question 20. Bhutia is a breed of:

  1. Chicken
  2. Goat
  3. Sheep
  4. Horse.

Answer: 4. Horse

Question 21. Ship of the desert is:

  1. Elephant
  2. Camel
  3. Sheep
  4. Goat.

Answer: 2. Camel

Question 22. The animal most useful on difficult terrain

  1. Mule
  2. Yak
  3. Camel
  4. Elephant.

Answer: 1. Mule

Question 23. Bactrian camel is characterized by:

  1. Two humps and a long neck
  2. Two humps and long limbs
  3. Two humps and a thick coat
  4. Single hump and thick coat.

Answer: 3. Two humps and a thick coat

Question 24. A beast of burden that needs little care is:

  1. Pig
  2. Donkey
  3. Mule
  4. Yak.

Answer: 2. Donkey

Question 25. The largest land animal is:

  1. Camel
  2. Elephant
  3. Rhino
  4. Python.

Answer: 2. Elephant

Question 26. Elephants are sought after for:

  1. Skin
  2. Hair
  3. Meat
  4. Ivory.

Answer: 4. Ivory.

Food Production And Management Mcq Neet

Question 27. The earliest animal to be domesticated was:

  1. Goat
  2. Dog
  3. Horse
  4. Cat.

Answer: 2. Dog

Question 28. The most used domesticated animal by Eskimos is:

  1. Cow
  2. Sheep
  3. Goat
  4. Husky.

Answer: 4. Husky.

Question 29. Huskies are:

  1. Yaks
  2. Donkeys
  3. Thick coated dogs
  4. Water buffaloes.

Answer: 3. Thick coated dogs

Question 30. The best source for dietary protein for a vegetarian is:

  1. Soya Bean
  2. Gram
  3. Groundnut
  4. Milk.

Answer: 4. Milk.

Food Production And Management Mcq Neet

Question 31. Zebu cattle are:

  1. Water Buffalo
  2. Indian Buffalo
  3. Cow
  4. Sheep

Answer: 3. Cow

Question 32. Cow Water Buffalo is

  1. European breed of buffalo that prefers living in water for most of the day
  2. Buffalo-like animals living in rivers
  3. Llama
  4. Buffalo.

Answer: 4. Buffalo.

Question 33. Which is the real product of Honey bee:

  1. Honey
  2. Pollen
  3. Beeswax
  4. Propolis.

Answer: 3. Beewax

Question 34. The hatching net is called:

  1. Nursery kind
  2. Production pond
  3. Stocking pond
  4. Hapa.

Answer: 4. Hapa.

Question 35. Spawning in fishes can be induced by:

  1. TSH
  2. Thyroxine
  3. FSH and LH
  4. STH.

Answer: 3. FSH and LH

Food Production And Management Mcq Neet

Question 36. The percentage of proteins in the fish meal is:

  1. 15-20%
  2. 25-50%
  3. 40-50%
  4. 55-70%.

Answer: 4. 55-70%.

Question 37. The rearing and breeding of fish in ponds, tanks, and artificial reservoirs are called

  1. Aquaculture
  2. Fishing
  3. Pisciculture
  4. Apiculture.

Answer: 3. Pisciculture

Question 38. Composite fish farming is called

  1. Polyculture
  2. Pisciculture
  3. Monoculture
  4. None of these.

Answer: 1. Polyculture

Question 39. Pisciculture has a bright future in India due to:

  1. Considerable demand
  2. Good response of native fishes to culture
  3. Abundance of cultivable waters
  4. All of these.

Answer: 4. All of these.

Question 40. Silk, honey, and lac are:

  1. Secretory substances of insects
  2. Secretory substances of plants
  3. Artificial chemicals
  4. All of the above.

Answer: 3. Artificial chemicals

Question 41. Match the terms in Column A with suitable terms in Column B.

Strategies For Enhancement In Food Production Animal Sources Match The Column With Suitable Items

  1. (1—D) (2—F), (3—G), (4—C), (5—A), (6—B), (7—E)
  2. (1—D). (2—F), (3—A), (4—C), (5—B), (6—E), (7—C)
  3. (1—D), (2-F), (3—A), (4—G), (5—C), (6—B), (7—E)
  4. (1—D), (2—F), (3—G), (4—C), (5—B), (6—A), (7—E)

Answer: 3. (1—D), (2-F), (3—A), (4—G), (5—C), (6—B), (7—E)

Question 42. The draught breeds of cattle include:

  1. Malvi, Nageri and Hallikar
  2. Malvi, Nageri and Ongole
  3. Nageri, Ongole and Haryana
  4. All the above.

Answer: 1. Malvi, Nageri and Hallikar

Food Production And Management Mcq Neet

Question 43. The method maximum used in cattle breeding is:

  1. Random breeding
  2. Artificial insemination
  3. Controlled breeding
  4. Superovulation and embryo transplant.

Answer: 2. Artificial insemination

Question 44. Rinderpest is the disease of:

  1. Cattle
  2. Poultry
  3. Fish
  4. Camel.

Answer: 1. Cattle

Question 45. Which of the following countries has the maximum average annual milk yield per cow?

  1. United Kingdom
  2. U.S.A.
  3. Denmark
  4. India.

Answer: 2. U.S.A.

Question 46. Which of the following countries has a minimum average annual milk yield per cow?

  1. India
  2. Pakistan
  3. Netherlands
  4. England.

Answer: 1. India

Question 47. Which of the following diseases in poultry is caused by nutritional deficiency?

  1. Perosis
  2. Fowl pox
  3. Coryza
  4. Aspergillosus.

Answer: 1. Perosis

Question 48. Ranikhet or New Castle Disease ‘of poultry is caused by:

  1. Bacteria
  2. Virus
  3. Fungus
  4. None of these.

Answer: 2. Virus

Biotechnology In Food Production Mcq

Question 49. The animal close to human beings which is cloned by an American scientist Dr. Don Wolf 1996 is:

  1. Gorilla
  2. Chimpanzee
  3. Gibbon
  4. Monkey.

Answer: 4. Monkey.

Question 50. Ambergris is the secretion from the intestine used in the manufacture of perfumes and other cosmetics:

  1. Tachyglossus- Echidna
  2. Physeter-Sperm whale
  3. Musk-Deer
  4. Kangaroo-Macropus.

Answer: 2. Physeter-Sperm whale

Question 51. Parthenogenesis is commonly round in:

  1. Ants, boos, and wasps
  2. Ascaris, oarlliwonn, and liver fluke
  3. Frogs, fishes, and foxes
  4. Starfish, Jellyfish, and cuttlefish.

Answer: 1. Ascaris, oarlliwonn, and liver fluke

Question 52. The length of silk fiber which surrounds a cocoon is about:

  1. 800 to 1200 yards
  2. 8000 to 12000 yards
  3. 800 to 1200 feet
  4. 8000 to 12000 meters.

Answer: 1. 800 to 1200 yards

MCQs on Enhancement of Food Production Question 53. The technique of silk production from the cocoons of silkworms was first known to:

  1. India
  2. China
  3. United Kingdom
  4. U.S.A.

Answer: 2. China

Question 54. Maximum cocoon and raw silk production is in:

  1. China
  2. Japan
  3. U.S.S.R.
  4. Brazil.

Answer: 1. China

Question 55. Central Silk Research and Training Institute (CSRTI) is located at:

  1. Assam
  2. Bahrampur
  3. Tarai region
  4. Shanthivials (Mysore).

Answer: 4. Shanthivials (Mysore).

Biotechnology In Food Production Mcq

Question 56. Most commercial silkworm strains are:

  1. Uni-voltine
  2. Vi-colline
  3. Multi-volcanic
  4. All of these.

Answer: 2. Vi-colline

MCQs on Enhancement of Food Production Question 57. The larval form of the silk moth is called:

  1. Naiad
  2. Maggot
  3. Caterpillar
  4. Wriggler.

Answer: 3. Caterpillar

Question 58. Eri silk is produced by:

  1. Bombyx mori
  2. Atticus ricin
  3. Anthenea roylre
  4. Anthenea paphia.

Answer: 2. Attcicus ricin

Question 59. Passive, non-locomotory, and non-feeding stages in the life history of the Silk moth are:

  1. Caterpillar
  2. Imago
  3. Nymph
  4. Pupa.

Answer: 4. Pupa.

Question 60. Nosemia sp. a protozoan produces diseases in:

  1. Silk moth
  2. Honey bee
  3. Both silk moth and honey bee
  4. Lac insect.

Answer: 3. Both silk moth and honey bee

Question 61. Which type of silk is obtained from Bombyx mori?

  1. Reeled silk
  2. Muga silk
  3. Arandi silk
  4. Tasar silk.

Answer: 1. Reeled silk

Biotechnology In Food Production Mcq

Question 62. Silk glands of silkworms are modified:

  1. Crop glands
  2. Salivary glands
  3. Gastric glands
  4. Intestinal glands

Answer: 2. Salivary glands

Question 63. Hinny Finny is a crossbreed between

  1. Male donkey and female horse
  2. Female donkey and male horse
  3. Male mule and female horse
  4. None of these.

Answer: 2. Male mule and female horse

Question 64. Match the terms of Column A with suitable terms in column B.

Strategies For Enhancement In Food Production Animal Sources Match The Columns With Suitable Terms

  1. (1-C), (2-B), (3-E), (4-D), (5-A)
  2. (1—C), (2—A), (3—E), (4—D), (5-B)
  3. (1—C), (2—A), (3—E), (4—B), (5—D)
  4. (1—E), (2—E), (3—B), (4—A), (5—D).

Answer: 3. (1—C), (2—A), (3—E), (4—B), (5—D)

Question 65. Poultry includes:

  1. Fowl, duck, tortoise, and turkey
  2. Fowl, duck, pigeon, and tortoise
  3. Duck, fowl, tortoise and turtle
  4. Fowl, duck, turkey, and pigeon.

Answer: 4. Fowl, duck, turkey, and pigeon.

Question 66. The percentage of proteins in the egg white is:

  1. 12%
  2. 35%
  3. 64%
  4. 70%.

Answer: 3. 64%

Question 67. The main protein type found in egg white is:

  1. Ovalbumin
  2. Canalbumin
  3. Phosvitin
  4. Lipovitellin.

Answer: 1. Ovalbumin

Food Security And Gm Crops Mcq Neet

Question 68. Central Food Technological Research Institute is located at:

  1. Izatnagar
  2. Lucknow.
  3. Dehradun
  4. Mysore.

Answer: 4. Mysore

Question 69. Which one of the following is our indigenous breed of chicken?

  1. Plymouth Rock
  2. White Leghorn
  3. Aseel
  4. Rhode Island Red.

Answer: 3. Aseel

NEET Biology Strategies for Enhancement in Food  Question 70. A hybrid variety produced, having more meat-producing capacity, in chickens is:

  1. Broilers
  2. Plymouth rock
  3. White Romish
  4. New Hemisphere.

Answer: 1. Broilers

Strategies For Enhancement In Food Production Animal Sources Questions From Competitive Examinations

Question 1. Which of the following lias have been recently used for increasing the productivity of super milk cows:

  1. Artificial insemination by a pedigree bull only
  2. Superovulation of a high-production cow only
  3. Embryo transplantation only
  4. A combination of superovulation, artificial insemination, and embryo transplantation into a carrier cow (surrogate mother).

Answer: 4. A combination of superovulation, artificial insemination, and embryo transplantation into a carrier cow (surrogate mother).

Question 2. The name of the sheep that was cloned for the first time is:

  1. Dolly
  2. Polly
  3. Molly
  4. Holly.

Answer: 3. Molly

Question 3. Inland fisheries is referred to as:

  1. Culturing fish in freshwater
  2. Trapping and capturing fish from seacoast
  3. Deep sea fishing
  4. Extraction of oil from fish.

Answer: 1. Culturing fish in freshwater

Question 4. On the basis of utility. Nagapuri buffaloes are categorized as:

  1. Grazers
  2. Dual purpose
  3. Draught cattle
  4. Milkers.

Answer: 4. Milkers.

Question 5. Natural silk contains:

  1. Potassium
  2. Phosphorus
  3. Nitrogen
  4. Magnesium.

Answer: 3. Nitrogen

Food Security And Gm Crops Mcq Neet

Question 6. In India the best aquarium is located at:

  1. Z.S.I. Kolkata
  2. Tarapur, Mumbai
  3. Chennai
  4. Vishakhapatnam.

Answer: 2. Chennai

Question 7. Pearl oyster belongs to class:

  1. Gastropoda
  2. Pelecypoda
  3. Scaphopoda
  4. Amphineura.

Answer: 2. Pelecypoda

Question 8. Lac is produced as:

  1. Feces of lac body
  2. Secretion from body
  3. Excretion from body
  4. Excess from oozing out of the body.

Answer: 2. Secretion from body

Question 9. Which one is the best silk?

  1. Eri silk
  2. Mulberry silk
  3. Tasar silk
  4. None of the above.

Answer: 2. Mulberry silk

Question 10. Lac is produced from

  1. Only males
  2. Only females
  3. More females than males
  4. More males than females.

Answer: 2. Only females

Question 11. The silkworm spins its cocoon:

  1. From inside to outside
  2. Outside to inside
  3. Random
  4. Inside.

Answer: 2. Outside to inside

Question 12. The three major carps. -Cattle, Labeo, and Cirhinus grown in the same pond are due to:

  1. There is no competition among them for food material
  2. Their feeding habits are different
  3. They live in different habitats
  4. None of the above.

Answer: 1. There is no competition among them for the food material

Question 13. The Indian tiger prawn is:

  1. Pennons implicit
  2. Penacus monodon
  3. Macrobradmm
  4. Palaemon.

Answer: 2. Penacus monodon

Food Security And GM Crops Mcq Neet

Question 14. Shagreen is obtained from:

  1. Dried skin of shark
  2. Skin of codfish
  3. Air bladder of fishes
  4. None of the above.

Answer: 1. Dried skin of shark

Question 15. Ishingless is obtained from:

  1. Liver of frog
  2. Scales of fishes
  3. Air bladder of fishes
  4. The skin of a shark.

Answer: 3. Air bladder of fishes

Question 16. Lac is:

  1. Excretion of lac insect
  2. Dead body of lac insect
  3. Body secretion of lac insect
  4. None of the above.

Answer: 3. Body secretion of lac insect

Question 17. It is now possible to breed plants and animals with desired characteristics through:

  1. Ikebana technique
  2. Tissue culture
  3. Genetic Engineering
  4. Chromosome Engineering.

Answer: 3. Genetic Engineering

Question 18. The large distribution of clean quality milk all the world over can be said to be due to the great work of:

  1. Robert Koch
  2. Leeuwenhoek
  3. Louis Pasteur
  4. Blackman.

Answer: 3. Louis Pasteur

Question 19. In lac insect, lac is produced from:

  1. Abdominal glands
  2. Salivary glands
  3. Skin glands of the abdomen
  4. None of the above.

Answer: 3. Skin glands of the abdomen

Food Security And GM Crops Mcq Neet

Question 20. The honey bees exhibit a type of dance to communicate the location of food. This is known as:

  1. Tap dance
  2. Round dance and waggling dance
  3. Breakdance
  4. Waggle dance.

Answer: 4. Waggle dance.

Question 21. Arhenotoky is a type of:

  1. Parthenogenesis found in honey bees, wasps and ants
  2. Parthenogenesis found in every insect
  3. Parthenogenesis found in mosquitoes
  4. Parthenogenesis is found in butterflies.

Answer: 1. Parthenogenesis found in honey bees, wasps and ants

Question 22. Which among the following is the real product of honey bees?

  1. Pollen
  2. Bee wax
  3. Honey
  4. Propolis.

Answer: 4. Propolis

Question 23. Which one of the following is the source of silk?

  1. Eggs
  2. Caterpillar
  3. Cocoon
  4. Pupa.

Answer: 3. Cocoon

Question 24. Which one of the following mollusca groups is primarily used in the pearl formation?

  1. Monoplacophorans
  2. Cephalopods
  3. Gastropods
  4. Pelecypods.

Answer: 4. Pelecypods.

Question 25. The main composition of lac is:

  1. Glue, pigment, and sugar
  2. Wax, pigment, and glue
  3. Resin, pigment, wax, and glue
  4. Resin, sugar, and wax.

Answer: 3. Resin, pigment, wax, and glue

Question 26. The main product of poultry is:

  1. Eggs
  2. Chicken
  3. Meat
  4. Eggs and meat.

Answer: 1. Eggs

Question 27. The insect that is not found in the wild state is:

  1. Lac insect
  2. Cochineal insect
  3. Honey bee
  4. Silk moth.

Answer: 2. Cochineal insect

Enhancement In Food Production Mcq For Neet

Question 28. The scientific name of the lac insect is:

  1. Tachardia lacca
  2. Bombyx mori
  3. Cimex lectularis
  4. Pediculus pithiris.

Answer: 1. Tachardia lacca

Question 29. The milch breeds of cattle are?

  1. Mallikar, Nageri and Malvi
  2. Gir, Sahiwal and Deoni
  3. Kankrej, Haryanna and Ongole
  4. Tharparkar and Kangayam.

Answer: 2. Gir, Sahiwal and Deoni

Question 30. Common wild rock honey bees are:

  1. Apis mellifera
  2. Apis indica
  3. Apis dorscita
  4. None of the above.

Answer: 3. Apis dorscita

Question 31. The tassar silk moth belongs to the family:

  1. Bombycidae
  2. Stumidae
  3. Hymenoptera
  4. Diptera.

Answer: 2. Stumidae

Question 32. The Indian carp is:

  1. Scoliodon
  2. Labeo
  3. Torpedo
  4. Pristis.

Answer: 2. Labeo

Question 33. Gambusia is a:

  1. Predator on mosquito larvae
  2. Pest of fishes
  3. Parasite on crab
  4. Pathogenic protozoan.

Answer: 1. Predator on mosquito larvae

Question 34. Silk glands are modified:

  1. Salivary glands
  2. Anal glands
  3. Colleterial glands
  4. Mushroom glands.

Answer: 1. Salivary glands

Question 35. The largest silk-producing state of India is:

  1. Karnataka
  2. Bihar
  3. Assam
  4. West Bengal.

Answer: 1. Karnataka

Question 36. Pearl-producing Indian species are:

  1. Pinctada indica
  2. Ostrea indica
  3. Pinctada vulgaris
  4. Ostrea vulgaris.

Answer: 3. Pinctada vulgaris

Enhancement In Food Production Mcq For Neet

Question 37. The world’s highly prized wool-yielding ‘Pashmina breed’ is:

  1. Sheep
  2. Goat
  3. Goat-sheep cross
  4. Kashmir sheep-afghan sheep cross.

Answer: 2. Goat

Question 38. Match the breeds of cattle given under Column A with the place of their origin listed under Column B. Choose the answer that gives the correct combination of alphabets of the two columns.

Strategies For Enhancement In Food Production Animal Sources Match The Breeds Of Cattle

  1. 1 = B, 2 = D, 3 = E. 4 = A
  2. 1 = D, 2 = C, 3 = E, 4 = A
  3. 1 = B, 2 = D, 3 = A, 4 = E
  4. 1 = D, 2 = E, 3 = A, 4 = C.

Answer: 2. 1 = D, 2 = C, 3 = E, 4 = A

Question 39. Which of the following is the sequence of cultivation of fish?

  1. Fry—fingerlings—spawn—Adult
  2. Spawn—fry—fingerlings—adult
  3. Adult—spawn—fingerlings—fry
  4. Fingerlings—fry—spawn—adult.

Answer: 3. Adult—spawn—fingerlings—fry

NEET Biology Strategies for Enhancement in Food  Question 40. The amount of protein per 100 g (without water, approximately 2 eggs) is:

  1. 11.9
  2. 20.1
  3. 16
  4. 45

Answer: 2. 20.1

Question 41. MOET is a method of:

  1. Fish cultivation
  2. Cloning in sheep
  3. Hybridization in cattle
  4. Birth control in humans

Answer: 3. Hybridization in cattle

Question 42. When a cross is made between two species of the same genus, then the cross is known as

  1. Intraspecific hybridization
  2. Interspecific hybridization
  3. Intergeneric hybridization
  4. Intervarietal hybridization.

Answer: 2. Interspecific hybridization

Question 43. Which one of the following types of silk is being produced extensively in South India?

  1. Eri
  2. Mulberry
  3. Tussar
  4. Muga.

Answer: 3. Tussar

Question 44. Mating between two individuals differing in genotype produces a genetic variation called

  1. Domestication
  2. Incubation
  3. Hybridization
  4. Mutation.

Answer: 3. Hybridization

Question 45. Which of the following organisms is useful for us?

  1. Musca
  2. Bombyx
  3. Pheretima
  4. Periplaneta.

Answer: 2. Bombyx

Question 46. Which of the statements about breeding is wrong?

  1. By inbreeding purelines cannot be evolved.
  2. Continued inbreeding, especially close inbreeding reduces fertility and productivity.
  3. Cross-breeding allows the desirable qualities of two different breeds to be combined.
  4. Inbreeding exposes harmful recessive genes that are eliminated by selection.
  5. A single outcross often helps to overcome inbreeding depression.

Answer: 2. Continued inbreeding, especially close inbreeding reduces fertility and productivity.

Question 47. Compared to a bull a bullock is docile because of:

  1. Higher levels of cortisone
  2. Lower levels of blood testosterone
  3. Lower levels of adrenalin/noradrenalin in its blood
  4. Higher levels of thyroxine.

Answer: 2. Lower levels of blood testosterone

NEET MCQs on Gene Expression And Gene Regulation

NEET Biology Gene Expression Multiple Choice Questions

Question 1. Co-repressor is a:

  1. Protein
  2. Metabolite
  3. Hormone
  4. Enzyme.

Answer: 2. Metabolite

Question 2. Reverse transcription was discovered by :

  1. Watson and Crick
  2. Porter
  3. Wilkins
  4. Temin.

Answer: 4. Temin.

Question 3. In the operon concept, the regulator gene regulates chemical reactions in the cell by :

  1. Inhibiting transcription of mRNA
  2. Inactivating enzymes in the reaction
  3. Inhibiting the substrate in the reactions
  4. Inhibiting the migration of tn-RNA in cytoplasm.

Answer: 1. Inhibiting transcription of mRNA

Gene Expression MCQs For NEET

Question 4. Which of the following statements is incorrect?

  1. Genetic code is ambiguous.
  2. Genetic code is degenerate.
  3. Genetic code is universal.
  4. Genetic code is non-overlapping.

Answer: 2. Genetic code is degenerate.

Read and Learn More NEET Biology Multiple Choice Question and Answers

Question 5. In E. coli according to the operon concept, an operator gene combines with:

  1. Inducer gene to switch on
  2. Regulator protein to “switch on” structural gene transcription
  3. Regulator gene to “switch off’ structural gene transcription
  4. Regulator protein to switch off structural gene transcription.

Answer: 3. Regulator gene to “switch off’ structural gene transcription

Question 6. Exons and introns arc parts of :

  1. DNA
  2. RNA
  3. mRNA
  4. Circular DNA.

Answer: 1. DNA

Question 7. Eukaryotes have :

  1. One promoter in gene structure
  2. Two promoters in gene structure
  3. No promoter gene
  4. Many promoters in gene structure.

Answer: 3. No promoter gene

Question 8. In Rous sarcoma virus:

  1. DNA → RNA→ Protein
  2. RNA → DNA → Protein
  3. RNA →DNA → RNA→ Protein
  4. DNA → RNA → RNA → Proleins.

Answer: 4. DNA → RNA → RNA → Proleins

Gene Expression MCQs For NEET

Question 9. Presence of F factor in bacteria :

  1. Indicates it as male
  2. Female
  3. Fast factor
  4. Free factor

Answer: 1. Indicates it as male

Question 10. The viral genes are expressed by :

  1. Lytic processes
  2. Lysogenic
  3. Both 1 and 2
  4. None of the above.

Answer: 3. Both 1 and 2

Question 11. Which of the following is not a carcinogen?

  1. X-rays
  2. Virus
  3. HNO2
  4. Starch.

Answer: 4. Starch

Question 12. According to the operon concept, the regulator gene forms.

  1. An inducer
  2. A repressor
  3. A small peptide
  4. A general inhibitor,

Answer: 2. A repressor

Gene Expression MCQs For NEET

Question 13. Which virus has a double-stranded RNA?

  1. Rheovirus
  2. Φ×174
  3. T2 phage
  4. TMV

Answer: 1. Rheovirus

Question 14. In the lysogenic cycle, the virus is:

  1. Virulent
  2. Temperate
  3. Harmless to the host cell
  4. Reproduces slowly.

Answer: 2. Temperate

Question 15. In bacteria, the exchange of genetic material between two different cells is brought by the process of:

  1. Transformation
  2. Transduction
  3. Conjugation
  4. All of the above

Answer: 4. All of the above

Gene Expression MCQs For NEET

Question 16. Phage host represents :

  1. Virion protein coat
  2. Virion nucleic acid
  3. Virion protein and nucleic acid
  4. None of the above.

Answer: 1. Virion protein coat

Question 17. The regulated unit of genetic material is called :

  1. Operator gene
  2. Regulator
  3. Operon
  4. Promoter gene.

Answer: 3. Operon

Question 18. A retrovirus is:

  1. TMV
  2. HIV
  3. Papillomavirus
  4. Both 2 and 3

Answer: 2. HIV

NEET Biology Gene Regulation Questions

Question 19. Bacteriophages are :

  1. Modified bacteria
  2. Primitive bacteria
  3. Viruses infecting bacteria
  4. Viruses infecting cyanobacteria.

Answer: 3. Viruses infecting bacteria

Question 20. Provirus differs from prophage about:

  1. Integration of RNA with host DNA
  2. Integration of genetic DNA with host DNA
  3. Integration of copy DNA of retrovirus with host DNA
  4. None of above

Answer: 3. Integration of copy DNA of retrovirus with host DNA

Question 21. Which virus has a rod-shaped structure 7

  1. Rlieo viruses
  2. Φ×174
  3. T phage
  4. TMV.

Answer: 4. TMV

Question 22. Tryptophan Operon is:

  1. Repressible system
  2. Inducible
  3. Controlled by regulator gene
  4. Made of 3 structural genes.

Answer: 1. Repressible system

Question 23. The presence of F-Factor in bacteria helps as :

  1. Fertility factor
  2. Female
  3. Fast factor
  4. Free factor.

Answer: 1. Fertility factor

Question 24. Exons and Introns are parts of;

  1. DNA
  2. mRNA
  3. RNA
  4. None of the above

Answer: 1. DNA

NEET Biology Gene Regulation Questions

Question 25. Eukaryotes have:

  1. One glue per cell
  2. Ten genes per cell
  3. Hundred genes per cell
  4. Thousand genes per cell.

Answer: 4. Thousand genes per cell.

Question 26. Oncogenic viruses are harmful in :

  1. Provirus stage
  2. Lytic phase
  3. Prophage stage
  4. Hybrid stage,

Answer: 1. Provirus stage

Question 27. Which of the following viruses have been extensively used to fuse cells in tissue culture :

  1. Sendai virus
  2. T2 viruses
  3. Phage lambda
  4. TMV,

Answer: 1. Sendai virus

Operon Model MCQs For NEET

Question 28. Jumping genes in maize were discovered by :

  1. H.G. Khorana
  2. Beadle
  3. Barbara McClintock
  4. Jacob.

Answer: 3. Barbara McClintock

Gene Regulation Recommended MCQs  Question 29. Thalassemia is an example of:

  1. Mutation
  2. Silent mutation
  3. Frameshift mutation
  4. Genetic disorders.

Answer: 3. Frameshift mutation

Question 30. Who found the occurrence of sexuality in bacteria ‘!

  1. Lederberg and Tatum
  2. Beadle and Tatum
  3. Sutton and Boveri
  4. Briggs and Kings.

Answer: 1. Lederberg and Tatum

Question 31. Operon consists of the following :

  1. Regulator and repressor
  2. Regulator, structural, and operator
  3. Regulator, structural, operator, and promoter
  4. Regulator and operator.

Answer: 3. Regulator, structural, operator, and promoter

Operon Model MCQs For NEET

Question 32. Restriction enzymes are used in genetic engineering because :

  1. They can cut DNA at specific base sequences.
  2. They are proteolytic enzymes which can degrade harmful proteins.
  3. They are nucleases that cut DNA at various sites
  4. They can join different DNA fragments.

Answer: 1. They can cut DNA at specific base sequence

Question 33. Wild-type E.cali cells are growing in a normal medium with glucose. They are transferred to a medium containing only lactose as the sugar. Which one of the following changes takes place?

  1. The lac operon is repressed
  2. All operons are induced
  3. E.coli cells stop dividing
  4. The lac operon is induced.

Answer: 4. The lac operon is induced

Question 34. An environmental agent that triggers transcription from an operon is a :

  1. Derepressor
  2. Inducer.
  3. Regulator
  4. Controlling element.

Answer: 2. Inducer

Question 35. The lac operon is an example of:

  1. Arabinose operon
  2. Inducible operon
  3. Repressive operon
  4. Overlapping genes,

Answer: 2. Inducible operon

NEET Previous Year Questions On Gene Regulation

Question 36. In split genes, the coding sequences are called :

  1. Cistrons
  2. Operons
  3. Exons
  4. Introns.

Answer: 3. Exons

Question 37. In the case of cyanobacteria :

  1. DNA → RNA → Protein
  2. RNA → DNA → Protein
  3. RNA → DNA → RNA → Protcin
  4. DNA → RNAH → RNA → Proteins.

Answer: 1. DNA → RNA → Protein

Question 38. A retrovirus is :

  1. TMV
  2. HIV
  3. Rheo virus
  4. Both 2 and 3

Answer: 4. Both 2 and 3

NEET Previous Year Questions On Gene Regulation

Question 39. The sequence of structural genes of Lac operon is :

  1. Lac Z, Lac Y, Lac A
  2. Lac Y, Lac Z, Lac A
  3. Lac A, Lac Z, Lac Y
  4. Lac A, Lac Y, Lac Z.

Answer: 1. Lac Z, Lac Y, Lac A

Question 40. Which virus has a single-stranded DNA :

  1. Rhevirus
  2. Φ×174 virus
  3. T2 phage
  4. TMV.

Answer: 2. Φ×174 virus

Question 41. In the lytic cycle, the virus is :

  1. Virulent
  2. Temperate
  3. Harmless to the host cell
  4. Reproduces slowly.

Answer: 1. Virulent

Lac Operon MCQs For NEET

Question 42. Resistance to antibiotics is a genetic trait that spreads naturally from one type of bacterium to :

  1. Another bacterium of the same strain
  2. Enkaryolic cells of all types
  3. Almost any other type of bacterium
  4. Any other cell containing copy DNA.

Answer: 3. Almost any other type of bacterium

Gene Regulation in Eukaryotes NEET Questions Question 43. Reverse transcriptase is :

  1. RNA-dependent DNA polymerase
  2. RNA-dependent RNA polymerase
  3. DNA-dependent RNA polymerase
  4. DNA-dependent DNA polymerase

Answer: 2. RNA-dependent RNA polymerase

Question 44. Transduction in bacteria is mediated by :

  1. Cosmids
  2. Phage vectors
  3. Plasmid vectors
  4. F-factors.

Answer: 2. Phage vectors

Question 45. The nuclease enzyme which begins its attack from a free end of a polynucleotide :

  1. Endonuclease
  2. Kinase
  3. Exonuclease
  4. Polymerase.

Answer: 3. Exonuclease

Question 46. Normally, the DNA molecule has A-T, and G-C pairing. However, these bases can exist in alternative, valency consistent status, owing to rearrangement called :

  1. Tautomerization
  2. Base analogue
  3. Frameshift mutation
  4. Point mutation

Answer: 3. Frameshift mutation

Lac Operon MCQs For NEET

Question 47. The fertility factor or F+ factor that plays a key role in conjugation is a:

  1. Retrovirus
  2. Plasmid
  3. Viroid
  4. Lysogenic phage

Answer: 2. Plasmid

Question 48. When DNA is exchanged between two bacteria via cytoplasmic bridges, the process is called :

  1. Transformation
  2. General transduction
  3. Restricted transduction
  4. Conjugation.

Answer: 4. Conjugation

Question 49. When a bacteriophage, in its lytic phage, carries some of the bacterium’s partially digested chromosome with it to another host cell, the process is called :

  1. Transformation
  2. General transduction
  3. Restricted transduction
  4. Conjugation

Answer: 2. General transduction

Question 50. In general, bacterial genes are regulated at the time of:

  1. Transcription
  2. Translation
  3. Post translation
  4. Post transcription.

Answer: 1. Transcription

Lac Operon MCQs For NEET

Question 51. The activity of a repressor depends on whether :

  1. The repressor is positioned next to the operon
  2. The repressor is positioned next to the promoter
  3. A key substance in the metabolic pathway is present
  4. There is enough RNA polymerase present.

Answer: 2. The repressor is positioned next to the promoter

Question 52. In gene therapy, DNA is inserted in a cell to compensate for :

  1. The absence of plasmid
  2. Mutant alleles
  3. Holes in the DNA made by viruses
  4. The lack of copy DNA.

Answer: 2. Mutant alleles

Question 53. In the lac operon structural gene ‘Z’ is responsible for the synthesis of the enzyme :

  1. β-galactosidase
  2. Galactosidase permease
  3. Galactosidase transacetylase.

Answer: 1. β-galactosidase

Gene Regulation in Eukaryotes NEET Questions Question 54. In the genetic code dictionary, how many codons are used to code for all the 20 amino acids?

  1. 64
  2. 61
  3. 60
  4. 20.

Answer: 2. 61

Question 55. Replication of DNA occurs during the S-phase of interphase Okazaki fragments are joined in a correct sequence by:

  1. DNA polymerase I
  2. DNA ligase
  3. Primase and helicase
  4. RNA polymerase.

Answer: 2. DNA ligase

Question 56. Which of the following makes use of RNA as a template to synthesize DNA?

  1. DNA polymerase
  2. RNA polymerase
  3. Reverse transcriptase
  4. DNA-dependent RNA polymerase.

Answer: 3. Reverse transcriptase

Lac Operon MCQs For NEET

Question 57. Which one of the following triplet codes is correctly matched with its specificity for an amino acid in protein synthesis or as a start or stop signal?

  1. UUU – Stop
  2. UGU Lencino
  3. UAC – Tyrosine
  4. UCG – Start.

Answer: 2. UGU Lencino

Question 58. How many genes are present on chromosomes Y and A respectively :

  1. 2869,231
  2. 232, 2968
  3. 231,2968
  4. 2968,231.

Answer: 3. 231,2968

Question 59. UTR is present on :

  1. MRNA at one end
  2. 3′ end of tRNA
  3. 5′ and 3′ end of mRNP
  4. 3′ end 5′ end of tRNA.

Answer: 3. 5′ and 3′ end of mRNP

Question 60. Which of the following is a ‘dual function’?

  1. AUG
  2. UUU
  3. GUA
  4. CCC.

Answer: 1. AUG

Question 61. The base sequence for a nucleic acid segment is given as GAG AGG GGA CCA. From this it can be concluded that it is a segment of:

  1. DNA strand
  2. mRNA
  3. t-RNA strand
  4. Data is not sufficient.

Answer: 4. Data not sufficient

Question 62. Which of the following does not follow the central dogma of molecular biology?

  1. mUcor
  2. Chlamydomonas
  3. HIV
  4. Mycobacterium.

Answer: 3. HIV

Question 63. The largest gene in humans is

  1. Oncogene
  2. Tumor suppress gene
  3. Dystrophin
  4. Insulin.

Answer: 3. Dystrophin

Question 64. In a DNA molecule, adenine is 15% what would be % the age of Guanine?

  1. 15%
  2. 30%
  3. 35%
  4. 85%.

Answer: 3. 35%

Question 65. The length of DNA with 23 base pairs is :

  1. 78.4 A°
  2. 78.2
  3. 78 A°
  4. 74.8A°

Answer: 2. 78.2

Transcription And Translation NEET MCQs

Question 66. Which of the following have ds RNA?

  1. TMV
  2. Ribozyme
  3. SnRNA
  4. Rheovirus.

Answer: 4. Rheovirus

Question 67. Regulation of lac operon by repressor is referred to as :

  1. +ve regulation
  2. – ve regular
  3. Repressible
  4. Anabolic.

Answer: 2. – ve regular

Question 68. The accessibility of the promoter region of prokaryotic DNA is many cases regulated by the interaction of proteins with a sequence termed operator. The operator region is adjacent to :

  1. Structural gene
  2. Regulator gene
  3. Promoter element
  4. Gene ‘a’.

Answer: 3. Promoter element

Question 69. At the time of organogenesis, genes regulate the process at different levels and a different times due to the:

  1. Promoter
  2. Regulator
  3. Intron
  4. Exon.

Answer: 4. Exon

Question 70. In Negative operon :

  1. Co-repressor binds with repressor
  2. Co-repressor does not bind with the repressor
  3. Corepressor binds with inducer.
  4. cAMP hurts lac operon

Answer: 1. Co-repressor binds with repressor

Question 71. Restriction enzymes:

  1. Are endonucleases that cleave DNA at specific sites
  2. Make DNA complementary to an existing DNA or RNA
  3. Cut or join DNA fragments
  4. Are required in vectorless direct gene transfer.

Answer: 1. Are endonucleases which cleave DNA at specific sites

Question 72. The process of introduction of foreign genes for improving genotype is called :

  1. Tissue culture
  2. Vernalization
  3. Genetic engineering
  4. Eugenics.

Answer: 4. Eugenics

Transcription And Translation NEET MCQs

Question 73. The diagram shows an important concept in the genetic implication of DNA. Fill in the blanks A to C.

Gene Expression And Gene Regulation Genetic Implication Of DNA

  1. A – translation B – transcription C – Erevin Chargaff
  2. A – transcription B – translation C – Francis Crick
  3. A – translation B – extension C – Rosalind Franklin
  4. A – transcription B – replication C – James Watson

Answer: 2. A – transcription B – translation C – Francis Crick

Question 74. Which one of the following conditions though harmful in itself, is also a potential saviour from all mosquito-borne infectious diseases?

  1. Pernicious anemia
  2. Leukaemia
  3. Thalassaemia
  4. Sickle cell anemia.

Answer: 4. Sickle cell anemia

Question 75. In E. coli, during lactose metabolism repressor binds to :

  1. Regulator gene
  2. Promoter gene
  3. Operator gene
  4. Structural gene.

Answer: 2. Promoter gene

MCQs on Regulation Of Gene Expression In Eukaryotes Question 76. The genes are responsible for the growth and differentiation of living organisms through the regulation of :

  1. Translation
  2. Transcription
  3. Transduction
  4. Both 1 and 2

Answer: 3. Transduction

Question 77. Which of the following is specifically used in genetic engineering?

  1. Ligase
  2. Gyrase
  3. Restriction endonuclease
  4. DNA polymerase.

Answer: 3. Restriction endonuclease

Question 78. Restriction endonucleases :

  1. Are present in mammalian cells for degradation of DNA when the cell dies
  2. Are used in genetic engineering for ligating two DNA molecules
  3. Are used for in vitro DNA synthesis
  4. Are synthesized by bacteria as part of their defense

Answer: 4. Are synthesized by bacteria as part of their defense

Transcription And Translation NEET MCQs

Question 79. Cancer cells are more easily damaged by radiation than normal cells because they are :

  1. Starved of mutation
  2. Undergoing rapid division
  3. Different in structure
  4. Non-dividing.

Answer: 2. Undergoing rapid division

Question 80. DNA fingerprinting refers to :

  1. Molecular analysis of profiles of DNA samples
  2. Analysis of DNA sample using imprinting device
  3. Techniques used for molecular analysis of different specimens of DNA
  4. Techniques used for identification of fingerprints of

Answer: 4. Techniques used for the identification of fingerprints of

Question 81. What kind of evidence suggested that man is more closely related to chimpanzees than to other hominoid apes?

  1. Evidence from DNA from sex chromosomes only
  2. Comparison of chromosomal morphology only
  3. Evidence from fossil remains and the fossil mitochondrial DNA alone
  4. Evidence from DNA extracted from sex chromosomes, autosomes, and mitochondria.

Answer: 4. Evidence from DNA extracted from sex chromosomes, autosomes, and mitochondria

Question 82. In transgenics, expression of transgene in target tissue is determined by :

  1. Enhancer
  2. Promoter
  3. Transgene
  4. Reporter.

Answer: 4. Reporter

MCQs on Regulation Of Gene Expression In Eukaryotes Question 83. The Ti plasmid is often used for making transgenic plants. This plasmid is found in :

  1. Azotobacter
  2. Rhizobium of the roots of leguminous plants
  3. Agrobacterium
  4. yeast as a 2μm plasmid.

Answer: 3. Agrobacterium

Gene Expression MCQs For NEET

Question 84. Which enzyme/s will be produced in a cell in which there is a nonsense mutation in the lac Y gene?

  1. Lactose permease
  2. Transacetylase
  3. Lactose permease and transacetylase
  4. β-galactosidase.

Answer: 4. β-galactosidase.

Question 85. Supercoiled DNA can be traced in :

  1. Prokaryotes and eukaryotes
  2. Eukaryotes only
  3. Prokaryotes only
  4. None of these

Answer: 1. Prokaryotes and eukaryotes

Question 86. Phosphorus is present in :

  1. Protein
  2. DNA
  3. RNA
  4. Both DNA and RNA.

Answer: 4. Both DNA and RNA

Question 87. In a given DNA segment ATG, ACC, AGG, ACC, CCA, ACA, the first base gets mutated. The effect of this on coding by this DNA segment will result in :

  1. A complete change in the type as well as a sequence of amino acids
  2. Change in the first amino acid only
  3. One amino acid less in the protein
  4. No change in the sequence
  5. No coding.

Answer: 2. One amino acid less in the protein

Question 88. Okazaki fragments are joined in a correct sequence by :

  1. DNA polymerase I
  2. DNA ligase
  3. RNA polymerase
  4. Primase
  5. Heliease.

Answer: 2. DNA ligase

Gene Expression MCQs For NEET

Question 89. In the lac operon, the structural genes are switched off when :

  1. The repressor binds to the operator
  2. Repressor binds to the promoter
  3. The repressor binds to the regulator
  4. Repressor binds to the inducer
  5. The repressor binds to the allolactose.

Answer: 1. The repressor binds to the operator

Question 90. In the lac operon structural gene V is responsible for the synthesis of the enzyme :

  1. β-galactosidase
  2. Galactosidase permease
  3. Galactosidase transacetylase
  4. None of these.

Answer: 1. β-galactosidase

Question 91. When lactose is added to the culture of E.coli, a few of its molecules get into the cells with the help of:

  1. Galactosidase
  2. Permease
  3. Lactase
  4. Transacetylase.

Answer: 2. Permease

Gene Regulation Recommended MCQs Question 92. During transcription, holoenzyme RNA polymerase binds to a DNA sequence and the DNA assumes a saddle Ike structure at that point. What is that sequence called?

  1. TATA box
  2. AAAT box
  3. GGTT box
  4. CAAT box

Answer: 1. TATA box

NEET Biology Gene Regulation Questions

Question 93. In the lac operon model, lactose molecules function a is :

  1. Inducers that bind with the operator gene
  2. Repressors that bind with the operator gene
  3. Inducers that bind with the repressor protein
  4. Compressors that bind with repressor protein.

Answer: 3. Inducers that bind with the repressor protein

Question 94. Protein synthesis in an animal cell occurs :

  1. Only on the ribosomes present in the cytosol
  2. Only on ribosomes attached to the nuclear envelope and endoplasmic reticulum
  3. On ribosomes present in the nucleolus as well as in the cytoplasm
  4. No ribosomes are present in the cytoplasm as well as in mitochondria.

Answer: 4. No ribosomes present in the cytoplasm as well as in mitochondria

Question 95. E.coli cells with a mutated z gene of the lac operon cannot grow in a medium containing only lactose as the source of energy because :

  1. In the presence of glucose, E.coli cells do not utilize lactose
  2. They cannot transport lactose from the medium into the cell
  3. The lac operon is constitutively active in these cells
  4. They cannot synthesize functional beta-galactosidase.

Answer: 4. They cannot synthesize functional beta-galactosidase

Question 96. Which one of the following makes use of RNA as a template to synthesize DNA?

  1. Reverse transcriptase
  2. DNA dependant RNA polymerase
  3. DNA polymerase
  4. RNA polymerase.

Answer: 1. Reverse transcriptase

Question 97. Differentiation of organs and tissues in a developing organism is associated with:

  1. Differential expression of genes
  2. Lethal mutations
  3. Deletion of genes
  4. Developmental mutations.

Answer: 1. Differential expression of genes

NEET Biology Gene Regulation Questions

Question 98. Intron transcripts in heterogenous nuclear RNA (hn- RNA) are removed and exon transcripts are joined together under the direction of protein complexes. These complexes are :

  1. Polysomes
  2. Cdk complex
  3. Spliceosomes
  4. Endopeptidases.

Answer: 3. Spliceosomes

Question 99. In regulation of gene expression in prokaryotes :

  1. Lactose acts as the suppressor for gene expression
  2. Tryptophan acts as the inducer of gene expression
  3. The regulator gene is the one that produces the repressor molecule
  1. 1 alone correct
  2. alone correct
  3. 3 alone correct
  4. 2 and 3 are correct.

Answer: 3. 3 alone correct

Question 100. The sequence of structural genes in the lac operon concept is :

  1. Lac A, lac Z, lac Y
  2. Lac A, lac Y, lac Z
  3. Lac Y, lac Z, lac A
  4. Lac Z, lac Y, lac A.

Answer: 4. Lac Z, lac Y, lac A.

NEET Biology Gene Regulation Questions

Question 101. All genes located on the same chromosome :

  1. Form different groups depending on their relative distance
  2. Form one linkage group
  3. Will not form any linkage groups.
  4. Form interactive groups that affect the phenotype

Answer: 2. Will not form any linkage groups.

Question 102. Conditions of a karyotype 2 n+1 and 2n ± 2 are called:

  1. Aneuploidy
  2. Polyploidy
  3. Allopolyploidy
  4. Monosomy.

Answer: 1. Aneuploidy

Question 103. Distance between the genes and advantage of recombination shows :

  1. A direct relationship
  2. An inverse relationship
  3. A parallel relationship
  4. No relationship.

Answer: 2. An inverse relationship

Question 104. If genetic disease is transferred from a phenotypically normal but carrier female to only some of the male progeny, the disease is :

  1. Autosomal dominant
  2. Autosomal recessive
  3. Sex-linked dominant
  4. Sex-linked recessive.

Answer: 4. Sex-linked recessive.

Operon Model MCQs For NEET

Question 105. In sickle cell anaemia glutamic acid is replaced by valine. Which one of the following triplets codes for valine?

  1. G G G
  2. A A G
  3. GAA
  4. GUG.

Answer: 4. GUG.

Question 106. A person having genotype IA IB would show the blood group as AB. This is because of:

  1. Pleiotropy
  2. Co-dominance
  3. Segregation
  4. Incomplete dominance.

Answer: 2. Co-dominance

Gene Regulation in Eukaryotes NEET Questions Question 107. ZZ / ZW type of sex determination is seen in :

  1. Platypus
  2. Snails
  3. Cockroach
  4. Peacock.

Answer: 4. Peacock.

Question 108. A cross between two tall plants resulted in offspring having few dwarf plants. What would be the genotypes of both the parents?

  1. TT and Tt
  2. Tt and Tt
  3. TT and TT
  4. Tt and tt.

Answer: 2. Tt and Tt

Question 109. In a dihybrid cross, if you get a 9:3:3:1 ratio it denotes that:

  1. The alleles of two genes interact with each other
  2. It is a multigenic inheritance
  3. It is a case of multiple alleles
  4. The alleles of two genes segregate independently.

Answer: 4. The alleles of two genes are segregating independently.

Operon Model MCQs For NEET

Question 110. Which of the following will not result in variations among siblings?

  1. Independent assessment of genes
  2. Crossing over
  3. Linkage
  4. Mutation.

Answer: 3. Linkage

Question 111. Mendel’s law of independent assortment holds good for genes situated on the :

  1. Non-homologous chromosomes
  2. Homologous chromosomes
  3. Extranuclear genetic element
  4. Same chromosome.

Answer: 1. Non-homologous chromosomes

Gene Regulation in Eukaryotes NEET Questions Question 112. Occasionally, a single gene may express more than one effect. The phenomenon is called :

  1. Multiple allelism
  2. Mosaicism
  3. Pleiotropy
  4. Polygeny.

Answer: 3. Pleiotropy

Question 113. In a certain taxon of insects, some have 1 7 chromosomes and the others have 18 chromosomes. The 17 and 18 chromosome-bearing organisms are :

  1. Males and females, respectively
  2. Females and males, respectively
  3. All males
  4. All females.

Answer: 1. Males and females, respectively

Question 114. The inheritance pattern of a gene over generations among humans is studied by the pedigree analysis. The character studied in the pedigree analysis is equivalent to :

  1. Quantitative trait
  2. Mendelian trait
  3. Polygenic trait
  4. Maternal trait.

Answer: 2. Mendelian trait

Question 115. It is said that Mendel proposed that the factor controlling any character is discrete and independent. This proposition was based on the :

  1. Results of F3 generation of a cross.
  2. Observations that the offspring of a cross made between the plants having two contrasting characters show only one character without any blending.
  3. Self-pollination of F1 offspring
  4. Cross-pollination of parental generations.

Answer: 2. Observations that the offspring of a cross made between the plants having two contrasting characters show only one character without any blending.

Question 116. Two genes ‘A’ and ‘B’ are linked. In a dihybrid cross involving these two genes, the F1 heterozygote is crossed with the homozygous recessive parental type (aa bb). What would be the ratio of offspring in the next generation?

  1. 1 : 1: 1: 1
  2. 9 : 3 : 3: 1
  3. 3:1
  4. 1: 1.

Answer: 1. 1: 1 : 1: 1

Operon Model MCQs For NEET

Question 117. In the F2 generation of a Mendelian dihybrid cross the number of phenotypes and genotypes are :

  1. Phenotypes – 4; genotypes – 16
  2. Phenotypes – 9; genotypes – 4
  3. Phenotypes – 4; genotypes – 8
  4. Phenotypes – 4; genotypes – 9

Answer: 4. Phenotypes – 4; genotypes – 9

Regulation of Gene Expression in Eukaryotes MCQ Question 118. The mother and father of a person with the ‘O’ blood group have ‘A’ and ‘B’ blood groups respectively. What would be the genotype of both mother and father?

  1. The mother is homozygous for the ‘A’ blood group and the father is heterozygous for ‘B’.
  2. Mother is heterozygous for ‘A’ blood group and father is homozygous for ‘B’
  3. Both mother and father are heterozygous for the ‘A’ and ‘B’ blood groups, respectively
  4. Both mother and father are homozygous for the ‘A’ and ‘B’ blood groups, respectively.

Answer: 3. Both mother and father are heterozygous for the ‘A’ and ‘B’ blood groups, respectively

Question 119. In a DNA strand, the nucleotides are linked together by:

  1. Glycosidic bonds
  2. Phosphodiester bonds
  3. Peptide bonds
  4. Hydrogen bonds.

Answer: 2. Phosphodiester bonds

Question 120. A nucleoside differs from a nucleotide. It lacks the

  1. Base
  2. Sugar
  3. Phosphate group
  4. Hydroxyl group.

Answer: 3. Phosphate group

Question 121. Both deoxyribose and ribose belong to a class of sugars called :

  1. Trioses
  2. Hexoses
  3. Pentoses
  4. Polysaccharides.

Answer: 3. Pentoses

Question 122. The fact that a purine base is always paired through hydrogen bonds with a pyrimidine base leads to, in the DNA double helix :

  1. The antiparallel nature
  2. The semi-conservative nature
  3. Uniform width throughout DNA
  4. Uniform length in all DNA.

Answer: 3. Uniform width throughout DNA

Question 123. The net electric charge on DNA and histones is :

  1. Both positive
  2. Both negative
  3. Negative and positive, respectively
  4. Zero

Answer: 3. Negative and positive, respectively

Regulation of Gene Expression in Eukaryotes MCQ Question 124. The promoter site and the terminator site for transcription are located at :

  1. 3’ (downstream) end and 5’ (upstream) end, respectively of the transcription unit
  2. 5’ (upstream) end and 3’ (downstream) end, respectively of the transcription unit
  3. The 5’ (upstream) end
  4. The 3’ (downstream) end.

Answer: 2. 5’ (upstream) end and 3’ (downstream) end, respectively of the transcription unit

Question 125. Which of the following statements is the most appropriate for sickle cell anemia?

  1. It cannot be treated with iron supplements
  2. It is a molecular disease
  3. It confers resistance to acquiring malaria
  4. All of the above.

Answer: 4. All of the above

Question 126. One of the following is true concerning AUG

  1. It codes for methionine only
  2. It is also an initiation codon
  3. It codes for methionine in both prokaryotes and eukaryotes
  4. All of the above.

Answer: 4. All of the above

Question 127. The first genetic material could be :

  1. Protein
  2. Carbohydrates
  3. DNA
  4. RNA

Answer: 4. RNA

Question 128. About mature ntRNA in eukaryotes :

  1. Exons and introns do not appear in the mature RNA
  2. Exons appear but introns do not! appear in the mature RNA
  3. Introns appear but exons do not appear in the mature RNA
  4. Both exons and introns appear in the mature RNA.

Answer: 2. Exons appear but introns do not! appear in the mature RNA

Question 129. The human chromosomes with the highest and least number of genes in them are respectively :

  1. Chromosome 21 and Y
  2. Chromosome 1 and X
  3. Chromosome 1 and Y
  4. Chromosome X and Y.

Answer: 3. Chromosome 1 and Y

Question 130. Who amongst the following scientists had no contribution in the development of the double helix model for the structure of DNA?

  1. Rosalind Franklin
  2. Maurice Wilkins
  3. Erwin Chargaff
  4. Meselson and Stahl.

Answer: 4. Meselson and Stahl.

Question 131. DNA is a polymer of nucleotides that are linked to each other by a 3″-5’ phosphodiester bond. To prevent the polymerization of nucleotides, which of the following modifications would you choose?

  1. Replace purine with pyrimidines
  2. Remove/Replace 3″ OH group in deoxyribose
  3. Remove/Replacc 2’ OH group with some other group in deoxyribose
  4. Both ‘2’ and ‘3’.

Answer: 2. Remove/Replace 3″ OH group in deoxyribose

Question 132. Discontinuous synthesis of DNA occurs in one strand, because :

  1. DNA molecule being synthesized is very long
  2. DNA-dependent DNA polymerase catalyzes polymerization only in one direction (5’- 3’)
  3. It is a more efficient process
  4. DNA ligase has to have a role.

Answer: 2. DNA-dependent DNA polymerase catalyzes polymerization only in one direction (5’-3’)

Question 133. Which of the following steps in transcription is catalyzed by RNA polymerase?

  1. Initiation
  2. Elongation
  3. Termination
  4. All of the above.

Answer: 2. Elongation

Question 134. Control of gene expression takes place at the level of:

  1. DNA-replication
  2. Transcription
  3. Transition
  4. None of the above

Answer: 2. Transcription

NEET Previous Year Questions On Gene Regulation

Question 135. Regulatory proteins are the accessory proteins that interact with RNA polymerase and affect its role in transcription. Which of the following statements is correct about regulatory protein?

  1. They only increase expression
  2. They only decrease expression.
  3. They interact with RNA polymerase but do not affect the expression
  4. They can act both as activators and as repressors

Answer: 4. They can act both as activators and as repressors

Question 136. Which was the last human chromosome to be completely sequenced :

  1. Chromosome 1
  2. Chromosome 11
  3. Chromosome 21
  4. Chromosome X.

Answer: 1. Chromosome 1

Question 137. Which of the following are the functions of RNA?

  1. It is a carrier of genetic information from DNA to ribosomes synthesizing polypeptides
  2. It carries amino acids to ribosomes
  3. It is a constituent component of ribosomes
  4. All of the above.

Answer: 4. All of the above.

Question 138. While analyzing tire DNA of an organism a total number of 5386 nucleotides were found out of which the proportion of different bases was: Adenine = 29%, Guanine = 17%, Cytosine = 32%. Thymine = 17%. Considering Chargaffs rule it can be concluded that:

  1. It is a double-stranded circular DNA
  2. It is a single-stranded DNA
  3. It is a double-stranded linear DNA
  4. No conclusion can be drawn.

Answer: 2. It is single-stranded DNA

Question 139. In some viruses, DNA is synthesized by using RNA as a template. Such a DNA is called :

  1. A-DNA
  2. B-DNA
  3. cDNA
  4. DNA.

Answer: 3. cDNA

Question 140. IfMeselson and Stahl’s experiment is continued for four generations in bacteria, the ratio of 15N-/15N: 15N/14N/: 1 4N/ 14N containing DNA in the fourth generation would be :

  1. 1:1:0
  2. 1:4:0
  3. 0:l:3
  4. 0:1:7.

Answer: 4. 0:1:7

Question 141. If the sequence of nitrogen bases of the coding strand of DNA in a transcription unit is: 5’ – ATG A ATG-3’, the sequence of bases in its RNA transcript would be :

  1. 5’ – AUG A AUG-3’
  2. 5’-UACUUAC-3’
  3. 5’ – CAUUCAU-3’
  4. 5’ – G U A A G U A – 3’.

Answer: 1. 5’ – AUG A AUG-3’

Question 142. The RNA polymerase holoenzyme transcribes :

  1. The promoter, structural gene, and the terminator region
  2. The promoter, and the terminator
  3. The structural gene and the terminator regions
  4. The structural gene only.

Answer: 3. the structural gene and the terminator regions

Question 143. If the base sequence of a codon mmRNA is 5’-AUC- 3’, the sequence of tRNA pairing with it must be :

  1. 5’ – UAC – 3’
  2. 5’ – CAU – 3’
  3. 5’ -AUG -3’
  4. 5’ – GUA – 3’

Answer: 2. 5’ – CAU – 3’

Question 144. The amino acid attaches to the tRNA at its :

  1. 5’-end
  2. 3’-end
  3. Anti codon site
  4. DHU loop

Answer: 2. 3’-end

Question 145. To initiate translation, the mRNA first binds to :

  1. The smaller ribosomal sub-unit,
  2. The larger ribosomal sub-unit
  3. The whole ribosome
  4. No such specificity exists.

Answer: 1. The smaller ribosomal sub-unit,

Question 146. In E.coli, the lac operon gets switched on when :

  1. lactose is present and it binds to the repressor
  2. The repressor binds to the operator
  3. RNA polymerase binds to the operator
  4. Lactose is present and it binds to RNA polymerase.

Answer: 1. lactose is present and it binds to the repressor

Question 147. Which of the following statements are correct?

  1. RNA polymerase 1 transcribes rRNAs
  2. RNA polymerase 2 transcribes snRNAs
  3. RNA polymerase 3 transcribes hnRNA
  4. RNA polymerase 2 transcribes hnRNA.
  1. 1 and 2 correct
  2. 1 and 3 are correct
  3. 1, 2, and 4 are correct
  4. 2 and 3 are correct
  5. 1 and 4 are correct.

Answer: 5. 1 and 4 are correct.

Question 148. In Hershey and Chase experiments, radioactive 32P was used to culture bacteriophages which resulted in radioactive :

  1. ViralDNA
  2. Bacterial capsule
  3. Viral proteins
  4. Plasma membrane of bacteria.

Answer: 1. ViralDNA

Question 149. The inducer for switching ‘on’ the lac operon in bacteria is:

  1. Presence of lactose
  2. Number of bacteria
  3. Presence of structural genes in the bacteria
  4. Presence of sucrose
  5. Presence of RNA polymerase

Answer: 1. Presence of lactose

Question 150. Select the incorrect statement (s):

1. Six codons do not code for any amino acid.

2. Codon is read in mRNA in a continuous fashion

3. Three condoms function as stop codons

4. The initiator codon AUG codes for methionine.

  1. 1,2 and 4 are incorect
  2. 1, 2 and 3 are incorect
  3. 2, 3 and 4 are incorect
  4. 2 alone is correct
  5. 1 alone is incorrect.

Answer: 5. 1 alone is incorrect.

Question 151. The collection of cloned DNA segments obtained from the complete genome is called :

  1. DNA library
  2. Genomic bank
  3. Gene bank
  4. Both 2 and 3

Answer: 4. Both 2 and 3

NEET Previous Year Questions On Gene Regulation

Question 152. In the operon model, the regulator gene functions as :

  1. Regulator
  2. Inhibitor
  3. Repressor
  4. Stimulator.

Answer: 3. Repressor

Question 153. Genes involved in turning on and off of structural genes are:

  1. Operator genes
  2. Regulator genes
  3. Redundant genes
  4. Promoter genes.

Answer: 2. Regulator genes

Question 154. Lac operon is related to :

  1. Synthesis of enzymes for lactose catabolism
  2. Synthesis of enzymes for lactose anabolism
  3. Synthesis of lac by lac insects
  4. Degradation of lac by lac insects.

Answer: 1. Synthesis of enzymes for lactose catabolism

Question 155. According to the operon concept, the regulator gene regulates chemical reactions in the cell by :

  1. Inactivating enzyme in the reaction
  2. Inhibiting the substrate in the reaction
  3. Inhibiting transcription of m-RNA
  4. Inhibiting the migration of mRNA into the cytoplasm.

Answer: 3. Inhibiting transcription of m-RNA

Question 156. The modem concept of a gene is that it is :

  1. A segment of DNA
  2. A segment of chromosome
  3. A functional unit of DNA
  4. All of these

Answer: 3. A functional unit of DNA

Question 157. SV 40 has five genes but the type of proteins synthesized by it is more than twice the number of genes present in it. It shows the presence of:

  1. Contained genes
  2. Split genes
  3. Overlapping genes
  4. Degenerate genes.

Answer: 3. overlapping genes

Question 158. Provirus differs from prophage about:

  1. Integration of RNA with host DNA
  2. Integration of genetic DNA with host DNA
  3. Integration of copy DNA of retrovirus with host DNA
  4. None of the above.

Answer: 3. Integration of copy DNA of retrovirus with host DNA

Question 159. Which virus has a rod-shaped structure?

  1. Rheo viruses
  2. Φ× 174
  3. T phage
  4. TMV.

Answer: 4. TMV.

Question 160. Tryptophan Operon is :

  1. Repressible system
  2. Inducible
  3. Controlled by regulator gene
  4. Made of 3 structural genes.

Answer: 1. Repressible system